如何在每一行的开头添加字符串？

Question

我需要在列表中的每行 id 的开头添加五次。 file_id 赞

text_file 喜欢

pla pla pla 
text text text 
dsfdfdfdfd
klfdklfkdkf
poepwoepwo
lewepwlew

结果应该是

5 pla pla pla 
5  text text text
5  dsfdfdfdfd
5  klfdklfkdkf
5  poepwoepwo
8  lewepwlew

等等..id的数量等于5000个id，文本等于25000个句子..每个id将有五个句子。我试着做类似的事情

import fileinput
import sys   
f = open("id","r")
List=[]
for id in f.readlines():
    List.append(id)    
file_name = 'text.txt'    
with open(file_name,'r') as fnr:
    text = fnr.readlines()
i=0
text = "".join([List[i]+" " + line.rstrip()  for line in text])    
with open(file_name,'w') as fnw:
    fnw.write(text)

但有结果

 5
 pla pla pla5
 text text text5
 dsfdfdfdfd5
 klfdklfkdkf5
 poepwoepwo5
 lewepwlew5

Answer 1

而不是：

i=0
text = "".join([List[i]+" " + line.rstrip()  for line in text])

你可以试试：

new_text = []
for i, line in enumerate(text):
    new_text.append(List[i % 5] + " " + line.rstrip())

然后将new_text写入文件。

Answer 2

你可以试试这个：虽然我还没有测试过

lst = []
with open("id","r") as f:
    ids = f.read().split('\n')
    file_name = 'text.txt'
    with open(file_name,'r') as fnr:
        text = fnr.read().split('\n')
        counter = 0
        for id_num in ids:
            for _ in range(5):
                if counter >= len(text):
                    break
                lst.append(id_num + " " + text[counter])
                counter += 1

text = '\n'.join(lst)
with open(file_name,'w') as fnw:
    fnw.write(text)

输出：

1 pla pla pla
1 text text text
1 dsfdfdfdfd
1 klfdklfkdkf
1 poepwoepwo
2 lewepwlew
2

如何在每一行的开头添加字符串？

How can i add string at the beginning each line?

python

file