Prisma 不喜欢关注用户的帖子

Question

我正在尝试从关注的用户那里获取所有 帖子，以便这些帖子未被以下用户（又名我）点赞。

我如何创建模式并查询这样的东西？

我目前有这个：

model User {
  id        String  @id @default(autoincrement())
  username  String
  followers Follows[] @relation("follower")
  following Follows[] @relation("following")
  likes Post[] @relation(references: [id])
}

model Follows {
  follower    User @relation("follower", fields: [followerId], references: [id])
  followerId  String
  following   User @relation("following", fields: [followingId], references: [id])
  followingId String

  @@id([followerId, followingId])
}

model Post {
  id Int @id @default(autoincrement())
  title String
  likedBy User[] @relation(references: [id])
}

Answer 1

架构中存在一些问题：

Follows table 中的关系似乎颠倒了，（即 followerId 应该映射到 User 模型上的 following 关系
我假设每个 post 都是由用户制作的，所以我在 Post 模型中添加了 author 字段
autoincrement() 使用 Int 类型，因此在 User 模型

cuid()

更新架构：

model User {
  id        String    @id @default(cuid())
  username  String
  followers Follows[] @relation("follower")
  following Follows[] @relation("following")
  posts     Post[]    @relation("author")
  likes     Post[]    @relation(references: [id])
}

model Follows {
  follower    User   @relation("following", fields: [followerId], references: [id])
  followerId  String
  following   User   @relation("follower", fields: [followingId], references: [id])
  followingId String

  @@id([followerId, followingId])
}

model Post {
  id       Int    @id @default(autoincrement())
  title    String
  authorId String
  author   User   @relation("author", fields: [authorId], references: [id])
  likedBy  User[] @relation(references: [id])
}

要从关注的用户那里获得所有不喜欢的 post：

const posts = await prisma.post.findMany({
    where: {
        likedBy: {
            none: {
                id: 'cl3g1s5a20011llvcsllnzlra', // same as followerId
            },
        },
        author: {
            followers: {
                some: {
                    followerId: 'cl3g1s5a20011llvcsllnzlra',
                },
            },
        },
    },
});

some：Returns 一条或多条（“一些”）相关记录符合过滤条件的所有记录。

https://www.prisma.io/docs/reference/api-reference/prisma-client-reference#some

none: Returns 零个相关记录符合过滤条件的所有记录。
- 您可以使用不带参数的none来return所有没有关系的记录

https://www.prisma.io/docs/reference/api-reference/prisma-client-reference#none

Prisma 不喜欢关注用户的帖子

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postgresql

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