Bash 如果多个匹配则正则表达式覆盖行

Question

我有一个 bash 脚本，其中有 3 个正则表达式。我想通过条件 if 找到文件中第一个模式的匹配项。

如果有匹配项，则在第二个模式中查找匹配项，但仅限于与第一个模式匹配的行。

最后，只检查第三个模式与匹配第二个模式的行（也就是已经匹配第一个模式的行）。

我有以下代码，但我不知道如何判断是否有匹配覆盖“行”值以将总行数减少到仅匹配的行数。

 #!/bin/bash
    pattern1= egrep '^([^,]*,){31}[1-9][0-9].*'
    pattern2= egrep '^([^,]*,){16}[0-1].[3-9].*'
    pattern3= egrep '^([^,]*,){32}[2-9][0-9].*'

while read line
    do
        if [[$line == $pattern1]];then
        newline == $pattern1
        if [[$newline == $pattern2 ]];then
        newline2 == $pattern2
        if [[$newline2 == $pattern3 ]]; then
        echo $pattern3

        fi
    done < mj1.csv  #this is the input file

我会这样调用这个脚本 ./b1.sh <filename>

一些输入数据：

EndYear,Rk,G,Date,Years,Days,Age,Tm,Home,Opp,Win,Diff,GS,MP,FG,FGA,FG_PCT,3P,3PA,3P_PCT,FT,FTA,FT_PCT,ORB,DRB,TRB,AST,STL,BLK,TOV,PF,PTS,GmSc
1985,1,1,10/26/1984,21,252,21.6899384,CHI,1,WSB,1,16,1,40,5,16,0.313,0,0,,6,7,0.857,1,5,6,7,2,4,5,2,16,12.5
1985,2,2,10/27/1984,21,253,21.69267625,CHI,0,MIL,0,-2,1,34,8,13,0.615,0,0,,5,5,1,3,2,5,5,2,1,3,4,21,19.4
1985,3,3,10/29/1984,21,255,21.69815195,CHI,1,MIL,1,6,1,34,13,24,0.542,0,0,,11,13,0.846,2,2,4,5,6,2,3,4,37,32.9
1985,4,4,10/30/1984,21,256,21.7008898,CHI,0,KCK,1,5,1,36,8,21,0.381,0,0,,9,9,1,2,2,4,5,3,1,6,5,25,14.7
1985,5,5,11/1/1984,21,258,21.7063655,CHI,0,DEN,0,-16,1,33,7,15,0.467,0,0,,3,4,0.75,3,2,5,5,1,1,2,4,17,13.2
1985,6,6,11/7/1984,21,264,21.72279261,CHI,0,DET,1,4,1,27,9,19,0.474,0,0,,7,9,0.778,1,3,4,3,3,1,5,5,25,14.9
1985,7,7,11/8/1984,21,265,21.72553046,CHI,0,NYK,1,15,1,33,15,22,0.682,0,0,,3,4,0.75,4,4,8,5,3,2,5,2,33,29.3
1985,8,8,11/10/1984,21,267,21.73100616,CHI,0,IND,1,2,1,42,9,22,0.409,0,0,,9,12,0.75,2,7,9,4,2,5,3,4,27,21.2
1985,9,9,11/13/1984,21,270,21.73921971,CHI,1,SAS,1,3,1,43,18,27,0.667,1,1,1,8,11,0.727,2,8,10,4,3,2,4,4,45,37.5
1985,10,10,11/15/1984,21,272,21.74469541,CHI,1,BOS,0,-20,1,33,12,24,0.5,0,1,0,3,3,1,0,2,2,2,2,1,1,4,27,17.1
1985,11,11,11/17/1984,21,274,21.75017112,CHI,1,PHI,0,-9,1,44,4,17,0.235,0,0,,8,8,1,0,5,5,7,5,2,4,5,16,12.5
1985,12,12,11/19/1984,21,276,21.75564682,CHI,1,IND,0,-17,1,39,11,26,0.423,0,3,0,12,16,0.75,2,3,5,2,2,1,3,3,34,20.8
1985,13,13,11/21/1984,21,278,21.76112252,CHI,0,MIL,0,-10,1,42,11,22,0.5,0,0,,13,14,0.929,4,9,13,2,2,2,6,3,35,26.7
1985,14,14,11/23/1984,21,280,21.76659822,CHI,0,SEA,1,19,1,30,9,13,0.692,0,0,,5,6,0.833,0,4,4,3,4,1,4,4,23,19.5
1985,15,15,11/24/1984,21,281,21.76933607,CHI,0,POR,0,-10,1,41,10,24,0.417,0,1,0,10,10,1,3,3,6,8,3,1,4,4,30,23.9
1985,16,16,11/27/1984,21,284,21.77754962,CHI,0,GSW,0,-6,1,24,6,10,0.6,0,0,,1,1,1,0,2,2,3,3,2,4,1,13,11.1
1985,17,17,11/29/1984,21,286,21.78302533,CHI,0,PHO,0,-5,1,30,9,17,0.529,1,1,1,3,4,0.75,1,2,3,2,2,0,2,5,22,14
1985,18,18,11/30/1984,21,287,21.78576318,CHI,0,LAC,1,4,1,37,9,15,0.6,0,0,,2,4,0.5,2,3,5,5,3,0,4,4,20,15.5
1985,19,19,12/2/1984,21,289,21.79123888,CHI,0,LAL,1,1,1,42,7,13,0.538,0,0,,6,8,0.75,2,0,2,3,1,1,4,3,20,12.9
1985,20,20,12/4/1984,21,291,21.79671458,CHI,1,NJN,1,15,1,35,7,13,0.538,0,0,,6,6,1,1,2,3,6,1,0,3,3,20,16
1985,21,21,12/7/1984,21,294,21.80492813,CHI,1,NYK,1,2,1,43,8,16,0.5,0,1,0,5,7,0.714,1,1,2,3,2,0,6,5,21,9.3
1985,22,22,12/8/1984,21,295,21.80766598,CHI,1,DAL,1,2,1,35,10,23,0.435,0,0,,0,0,,4,3,7,2,0,2,2,3,20,11.2
1985,23,23,12/11/1984,21,298,21.81587953,CHI,1,DET,0,-7,1,37,13,28,0.464,0,1,0,1,3,0.333,1,7,8,6,2,0,3,4,27,16.2
1985,24,24,12/12/1984,21,299,21.81861739,CHI,0,DET,0,-7,1,30,6,17,0.353,0,2,0,9,10,0.9,0,1,1,2,2,1,1,5,21,12.5
1985,25,25,12/14/1984,21,301,21.82409309,CHI,0,NJN,0,-2,1,44,12,25,0.48,0,0,,10,10,1,2,6,8,8,1,0,0,4,34,29.5
1985,26,26,12/15/1984,21,302,21.82683094,CHI,1,PHI,0,-12,1,27,7,16,0.438,0,0,,0,0,,1,1,2,2,1,0,1,2,14,7.2
1985,27,27,12/18/1984,21,305,21.83504449,CHI,1,HOU,0,-8,1,45,8,20,0.4,0,1,0,2,4,0.5,1,2,3,8,3,0,1,2,18,14.5
1985,28,28,12/20/1984,21,307,21.84052019,CHI,0,ATL,1,3,1,41,12,22,0.545,0,0,,10,16,0.625,4,4,8,7,5,1,7,5,34,26.6

为了让事情更简单，pattern1 匹配列 PTS 高于 10 的所有行，模式 2 匹配列 FG_PCT 高于 0.3 的行，模式 3 匹配列 GmSc 高于 0.3 的所有行比 19.

Answer 1

虽然 awk 解决方案会更快一些......我们将根据 OP 的要求专注于 bash 解决方案。

第一个问题是正则表达式匹配使用 =~ 运算符而不是 == 运算符。

第二个问题是，如果只有所有 3 个正则表达式匹配，则保持一行意味着我们想要和 (&&) 所有 3 个正则表达式匹配的结果。

第三个问题解决了 OP 当前代码的一些基本语法问题（例如，space 在 [[ 之后和 ]] 之前；正则表达式模式对 pattern* 的不正确分配变量）。

一个bash想法：

pattern1='^([^,]*,){31}[1-9][0-9].*'
pattern2='^([^,]*,){16}[0-1].[3-9].*'
pattern3='^([^,]*,){32}[2-9][0-9].*'

head -1 mj1.csv > mj1.new.csv

while read -r line
do
    if [[ "${line}" =~ $pattern1 && "${line}" =~ $pattern2 && "${line}" =~ $pattern3 ]]
    then
        # do whatever with $line, eg:
        echo "${line}"
    fi
done < mj1.csv >> mj1.new.csv

这会生成：

$ cat mj1.new.csv
EndYear,Rk,G,Date,Years,Days,Age,Tm,Home,Opp,Win,Diff,GS,MP,FG,FGA,FG_PCT,3P,3PA,3P_PCT,FT,FTA,FT_PCT,ORB,DRB,TRB,AST,STL,BLK,TOV,PF,PTS,GmSc
1985,3,3,10/29/1984,21,255,21.69815195,CHI,1,MIL,1,6,1,34,13,24,0.542,0,0,,11,13,0.846,2,2,4,5,6,2,3,4,37,32.9
1985,7,7,11/8/1984,21,265,21.72553046,CHI,0,NYK,1,15,1,33,15,22,0.682,0,0,,3,4,0.75,4,4,8,5,3,2,5,2,33,29.3
1985,8,8,11/10/1984,21,267,21.73100616,CHI,0,IND,1,2,1,42,9,22,0.409,0,0,,9,12,0.75,2,7,9,4,2,5,3,4,27,21.2
1985,9,9,11/13/1984,21,270,21.73921971,CHI,1,SAS,1,3,1,43,18,27,0.667,1,1,1,8,11,0.727,2,8,10,4,3,2,4,4,45,37.5
1985,12,12,11/19/1984,21,276,21.75564682,CHI,1,IND,0,-17,1,39,11,26,0.423,0,3,0,12,16,0.75,2,3,5,2,2,1,3,3,34,20.8
1985,13,13,11/21/1984,21,278,21.76112252,CHI,0,MIL,0,-10,1,42,11,22,0.5,0,0,,13,14,0.929,4,9,13,2,2,2,6,3,35,26.7
1985,15,15,11/24/1984,21,281,21.76933607,CHI,0,POR,0,-10,1,41,10,24,0.417,0,1,0,10,10,1,3,3,6,8,3,1,4,4,30,23.9
1985,25,25,12/14/1984,21,301,21.82409309,CHI,0,NJN,0,-2,1,44,12,25,0.48,0,0,,10,10,1,2,6,8,8,1,0,0,4,34,29.5
1985,28,28,12/20/1984,21,307,21.84052019,CHI,0,ATL,1,3,1,41,12,22,0.545,0,0,,10,16,0.625,4,4,8,7,5,1,7,5,34,26.6

注意：OP 还没有（还）提供预期的输出，所以此时我必须假设 OP 的正则表达式是正确的

Bash 如果多个匹配则正则表达式覆盖行

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