如何将对象列表转换为简单列表,从对象列表中选择单个属性?
How to convert a list of objects into a simple list, selecting a single attribute from the list of objects?
假设我们有这个:
whitelist = [
{
cidr = "10.0.0.0/8",
desc = "customer1"
},
{
cidr = "10.1.0.0/8",
desc = "customer2"
},...
]
如何制作一个简单的列表 whitelist_cidrs 即:
whitelist_cidrs = [ "10.0.0.0/8", "0.1.0.0/8",...]
如何将对象列表转换为简单的字符串列表?
for expression 可能是您正在寻找的:
locals {
whitelist = [
{
cidr = "10.0.0.0/8",
desc = "customer1"
},
{
cidr = "10.1.0.0/8",
desc = "customer2"
}
]
}
output "whitelist_cidrs" {
value = [for p in local.whitelist : p.cidr]
}
输出:
Changes to Outputs:
+ whitelist_cidrs = [
+ "10.0.0.0/8",
+ "10.1.0.0/8",
]
假设我们有这个:
whitelist = [
{
cidr = "10.0.0.0/8",
desc = "customer1"
},
{
cidr = "10.1.0.0/8",
desc = "customer2"
},...
]
如何制作一个简单的列表 whitelist_cidrs 即:
whitelist_cidrs = [ "10.0.0.0/8", "0.1.0.0/8",...]
如何将对象列表转换为简单的字符串列表?
for expression 可能是您正在寻找的:
locals {
whitelist = [
{
cidr = "10.0.0.0/8",
desc = "customer1"
},
{
cidr = "10.1.0.0/8",
desc = "customer2"
}
]
}
output "whitelist_cidrs" {
value = [for p in local.whitelist : p.cidr]
}
输出:
Changes to Outputs:
+ whitelist_cidrs = [
+ "10.0.0.0/8",
+ "10.1.0.0/8",
]