对 cut R 函数产生的水平的操作

Question

我想对 cut R 函数生成的关卡进行一些操作。我想在我的 MWE 中加入 exp(Labs)。

set.seed(12345)
Y <- rnorm(n = 50, mean = 500, sd = 1)
Y1 <-  cut(log(Y), 5)
Labs <- levels(Y1)
Labs
[1] "(6.21,6.212]"  "(6.212,6.213]" "(6.213,6.215]" "(6.215,6.217]" "(6.217,6.219]"

exp(cbind(lower = as.numeric( sub("\((.+),.*", "\1", Labs) ),
      upper = as.numeric( sub("[^,]*,([^]]*)\]", "\1", Labs) )))
        lower    upper

[1,] 497.7013 498.6976
[2,] 498.6976 499.1966
[3,] 499.1966 500.1960
[4,] 500.1960 501.1974
[5,] 501.1974 502.2008

问题

我怎样才能得到exp(Labs)这里？

期望输出

"(497.7013, 498.6976]"  "(498.6976, 499.1966]" "(499.1966, 500.1960]" "(500.1960, 501.1974]"  "(501.1974, 502.2008]"

已编辑

基于@akrun 的回答：

    Labs1 <- c("(-2.32,0.99]", "(0.99,4.28]", "(4.28,7.58]", "(7.58,10.9]", "(10.9,14.2]")

Labs1
    [1] "(-2.32,0.99]" "(0.99,4.28]"  "(4.28,7.58]"  "(7.58,10.9]"  "(10.9,14.2]"

    exp(cbind(lower = as.numeric( sub("\((.+),.*", "\1", Labs1) ),
              upper = as.numeric( sub("[^,]*,([^]]*)\]", "\1", Labs1) )))

            lower        upper
[1,] 9.827359e-02 2.691234e+00
[2,] 2.691234e+00 7.224044e+01
[3,] 7.224044e+01 1.958629e+03
[4,] 1.958629e+03 5.417636e+04
[5,] 5.417636e+04 1.468864e+06


    gsubfn('([0-9.]+)', ~round(exp(as.numeric(x)),4), Labs1)

[1] "(-10.1757,2.6912]"         "(2.6912,72.2404]"          "(72.2404,1958.629]"       
[4] "(1958.629,54176.3638]"     "(54176.3638,1468864.1897]"

    res1 <-  exp(as.data.frame(t(sapply(strsplit(Labs1, '[^0-9.]+'), 
                                       function(x) as.numeric(x[-1])))))
    sprintf('(%s]', do.call(paste, c(round(res1,4), sep=", ")))


[1] "(10.1757, 2.6912]"          "(2.6912, 72.2404]"          "(72.2404, 1958.629]"       
[4] "(1958.629, 54176.3638]"     "(54176.3638, 1468864.1897]"

Answer 1

一个紧凑的选项是使用 gsubfn。我们在 pattern 参数中用点 (([0-9.]+)) 匹配数字元素，我们通过首先将其转换为 'numeric' 来替换匹配的元素，取 exp 和 round。

library(gsubfn)
gsubfn('([-0-9.]+)', ~round(exp(as.numeric(x)),4), Labs)
#[1] "(497.7013,498.6976]" "(498.6976,499.1966]" "(499.1966,500.196]" 
#[4] "(500.196,501.1974]"  "(501.1974,502.2008]"

注意：这取决于我们使用的模式。

或者避免两次调用 sub 的另一种选择是 strsplit。我们在非数字元素上 split 。输出将是一个 list，所以我们可以使用 lapply/sapply 循环遍历列表元素，转换为 numeric class，并创建一个 'data.frame' 有两个列。

res <-  exp(as.data.frame(t(sapply(strsplit(Labs, '[^-0-9.]+'), 
              function(x) as.numeric(x[-1])))))

关于根据 OP 代码获得预期输出。我把原来代码里的cbind改成了data.frame，这样就可以用do.call了。

 res <-  exp(data.frame(lower = as.numeric( sub("\((.+),.*", "\1", Labs) ),
         upper = as.numeric( sub("[^,]*,([^]]*)\]", "\1", Labs) )))

我们 paste 'res' (do.call(paste0) 的行元素，然后用 sprintf 或另一个 paste [=33] 添加额外的括号=]

  sprintf('(%s]', do.call(paste, c(round(res,4), sep=", ")))
  #[1] "(497.7013, 498.6976]" "(498.6976, 499.1966]" "(499.1966, 500.196]" 
  #[4] "(500.196, 501.1974]"  "(501.1974, 502.2008]"

更新

使用 'Labs1'

检查输出

 gsubfn('([-0-9.]+)', ~round(exp(as.numeric(x)),4), Labs1)
 #[1] "(0.0983,2.6912]"           "(2.6912,72.2404]"         
 #[3] "(72.2404,1958.629]"        "(1958.629,54176.3638]"    
 #[5] "(54176.3638,1468864.1897]"


 exp(as.data.frame(t(sapply(strsplit(Labs1, '[^-0-9.]+'), 
             function(x) as.numeric(x[-1])))))
 #           V1           V2
 #1 9.827359e-02 2.691234e+00
 #2 2.691234e+00 7.224044e+01
 #3 7.224044e+01 1.958629e+03
 #4 1.958629e+03 5.417636e+04
 #5 5.417636e+04 1.468864e+06

对 cut R 函数产生的水平的操作

Manipulation on levels produced by cut R function

r

cut

更新