Return 基于输入数字的整数列表范围

Question

我在今天的考试中发现了这个问题，我一直试图找到正确的答案，但没有找到。

问题是：

假设我们的页码范围是 0、100。当我们点击页面时，假设是 15，我们只显示 UI 上的 10 页，即从第 10 页到第 20 页

更多示例输入：50 输出：returns列表

[46,47,48,49,50,51,52,53,54,55]

输入：15 输出：returns 列表

[11,12,13,14,15,16,17,18,19,20]

列表还应包括第一页和最后一页，即 0 和 50

所以第一个例子的实际输出是

[0,46,47,48,49,50,51,52,53,54,55,100]

下面是我试过的

def get_thread_page_num(num, max_page_num):
    # Returns 10 numbers dynamically
    new_lst =[1,50]
    
    # default list
    # defult_lst = [1,2,3,4,5,6,7,8,9,10]
    num -4 > 0
    num+5 <max_page_num
    i = 10
    m = 4
    p = 5
    while i != 0:
        if num-1 >0 and m !=0:
            new_lst.append(num-m)
            i=i-1
            m = m-1
        elif num+1<max_page_num and  p != 0:
            new_lst.append(num+p)
            i=i-1
            p = p-1
    
    print(sorted(new_lst))

    get_thread_page_num(9, 50)

Answer 1

在您的代码中，m 和 p 分别以值 4 和 5 开头。在每次迭代中，它们中的任何一个都减少 1。因此，在 9 次迭代后它们都为 0，并且 new_lst 包含 9 个元素。 i 也变成 10-9 = 1。但是 i 永远不会变成 0 并且循环变成无限。

您可以试试下面的代码。请参考评论。

def get_thread_page_num(num, max_page_num):
    # low and high denotes the low and high end of the list
    # where middle element is num
    low = max(0, num - 4)
    high = min(num + 5, max_page_num)

    lst = []
    if max_page_num < 9:
        # 10 element list is not possible
        return lst

    # In case high is same as max, just make the list as
    # high-9, high -8, ..., high
    if high == max_page_num:
        lst = list(range(max(0, high - 9), high + 1))
    else:
        # Just create a list starting from low like -
        # low, low + 1, ..., low + 9
        lst = list(range(low, low+10))

    # Add 0 and max if not already present
    if 0 not in lst:
        lst.append(0)
    if max_page_num not in lst:
        lst.append(max_page_num)

    # return sorted lst
    return sorted(lst)

致电get_thread_page_num()：

print(get_thread_page_num(15, 50))
print(get_thread_page_num(0, 50))
print(get_thread_page_num(2, 50))
print(get_thread_page_num(50, 50))
print(get_thread_page_num(43, 50))

输出：

[0, 11, 12, 13, 14, 15, 16, 17, 18, 19, 20, 50]
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 50]
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9, 50]
[0, 41, 42, 43, 44, 45, 46, 47, 48, 49, 50]
[0, 39, 40, 41, 42, 43, 44, 45, 46, 47, 48, 50]

Return 基于输入数字的整数列表范围

Return range of integer list based on input number

list

python-3.x