SQL 分组依据的最大值总和

Question

我有一个 table 具有以下结构。

Fruit	Color	Origin	Popularity	Price
Apple	Red	IN	100	100
Apple	Red	IN	90	50
Apple	Red	FR	50	75
Apple	Red	FR	50	80
Apple	Red		20	20

我想获得按水果和颜色分组的总价 (100 + 50 + 75 + 80 + 20)，包括按产地分类的最大受欢迎程度总和 (100 + 50 + 20)。以下是预期结果。

Fruit	Color	Popularity	Price
Apple	Red	170	325

我试过用不同的总和进行分组，但给出了错误的结果。

select Fruit, Color, SUM(distinct Popularity), SUM(Price) FROM FRUITS_TABLE Group by Fruit, Color

如果有任何解决方案可以在单个查询中实现此结果，请分享。

我正在使用 MS SQL。

谢谢

Answer 1

我们可以尝试将 ROW_NUMBER window 函数与子查询一起使用，以通过名为 rn.

的原始行获得最大流行度

然后使用条件聚合函数求和所有最大流行度

select Fruit, 
      Color, 
      SUM(IIF(rn = 1,Popularity,0)) Popularity, 
      SUM(Price) Price
FROM (
   SELECT *,
          ROW_NUMBER() OVER(PARTITION BY Fruit, Color,origin ORDER BY Popularity DESC) rn
   FROM FRUITS_TABLE
) t1
Group by Fruit, Color

sqlfiddle

Answer 2

CREATE TABLE Fruit (
    Fruit varchar(8) NOT NULL,
    Color varchar(8) NOT NULL,
    Origin varchar(2)    NULL,
    Popularity int NOT NULL,
    Price      int NOT NULL,

    -- What is the PK?
)

INSERT INTO Fruit (Fruit, Color, Origin, Popularity, Price)
VALUES 
    ('Apple', 'Red', 'IN', 100, 100),
    ('Apple', 'Red', 'IN', 90, 50),
    ('Apple', 'Red', 'FR', 50, 75),
    ('Apple', 'Red', 'FR', 50, 80),
    ('Apple', 'Red', NULL, 20, 20)

SELECT Fruit, Color, SUM(PriceSum) AS PriceSum, SUM(PopularityMax) AS PopularityMaxSum
FROM (
    SELECT Fruit, Color, Origin,
        SUM(Price) AS PriceSum,
        MAX(Popularity) AS PopularityMax
    FROM Fruit
    GROUP BY Fruit, Color, Origin
) T
GROUP BY Fruit, Color

SQL 分组依据的最大值总和

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