MongoDB 如何在数组中对 objects 进行分组并找到前 3 个

Question

我想找出用户评论最多的前 3 个位置（如果有的话）。

更具体地说，我有一个 collection 评论，其中包含 user_id 和 business_id 以及一个 collection 业务，其中包含 business_id 和经度以及纬度。如果用户从位置（38.551126，-110.880452）和（38.999999，-110.000000）进行了评论，我们可以说用户在此位置 (38, -110) 有 2 条评论。

Collection.review:

{
  "review_id": "KU_O5udG6zpxOg-VcAEodg",
  "user_id": "mh_-eMZ6K5RLWhZyISBhwA",
  "business_id": "XQfwVwDr-v0ZS3_CbbE5Xw",
  "stars": 3,
  "useful": 0,
  "funny": 0,
  "cool": 0,
  "text": "If you decide to eat here, ...",
  "date": "2018-07-07 22:09:11"
}

collection.business:

{
  "business_id": "XQfwVwDr-v0ZS3_CbbE5Xw",
  "name": "Turning Point of North Wales",
  "address": "1460 Bethlehem Pike",
  "city": "North Wales",
  "state": "PA",
  "postal_code": "19454",
  "latitude": 40.2101961875,
  "longitude": -75.2236385919,
  "stars": 3,
  "review_count": 169,
  "is_open": 1,
  "attributes": Object
  "categories": "Restaurants, Breakfast & Brunch, Food",
  "hours": Object
}

我是 mongodb 的初学者，我唯一有一些结果的管道就是这个。

review.aggregate([{
 $match: {
  user_id: {
   $in: [some_list]
  }
 }
}, {
 $lookup: {
  from: 'business',
  localField: 'business_id',
  foreignField: 'business_id',
  as: 'business'
 }
}, {
 $unwind: {
  path: '$business'
 }
}, {
 $group: {
  _id: '$user_id',
  coordinates: {
   $push: {
    latitude: {
     $toInt: '$business.latitude'
    },
    longitude: {
     $toInt: '$business.longitude'
    }
   }
  },
  places: {
   $sum: 1
  }
 }
}])

输出

_id: "xoZvMJPDW6Q9pDAXI0e_Ww"
coordinates: Array
    0: Object
        latitude: 39
        longitude: -119
    1: Object
        latitude: 39
        longitude: -119
    2: Object
        latitude: 39
        longitude: -119
    3: Object
        latitude: 39
        longitude: -119
    4: Object
        latitude: 39
        longitude: -119
places: 5

之后我在 python 中处理结果。有什么办法可以立即从管道中完成并得到类似这样的结果（并且仅限于前 3 名）

_id: "xoZvMJPDW6Q9pDAXI0e_Ww"
top_places: Array
    0: Object
        latitude: 39
        longitude: -119
    1: Object
        latitude: 23
        longitude: 56

Answer 1

您只需要添加一个额外的分组阶段，先按位置和用户分组，然后再按用户分组，如下所示：

db.review.aggregate([
  {
    $lookup: {
      from: "business",
      localField: "business_id",
      foreignField: "business_id",
      as: "business"
    }
  },
  {
    $unwind: {
      path: "$business"
    }
  },
  {
    $group: {
      _id: {
        user: "$user_id",
        latitude: {
          $toInt: "$business.latitude"
        },
        longitude: {
          $toInt: "$business.longitude"
        }
      },
      places: {
        $sum: 1
      }
    }
  },
  {
    $group: {
      _id: "$_id.user",
      coordinates: {
        $push: {
          latitude: "$_id.latitude",
          longitude: "$_id.longitude",
          
        }
      },
      places: {
        $sum: "$places"
      }
    }
  }
])

Mongo Playground

MongoDB 如何在数组中对 objects 进行分组并找到前 3 个

MongoDB how to group objects in array and find the top 3

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