SQL 与之前的结果合计

Question

我有以下table

Year1	Year2	Value
2014	2014	1
2014	2014	2
2014	2015	3
2014	2016	4
2015	2015	5
2015	2016	6
2015	2017	7
2015	2017	8

我需要写一个 SQL 查询来给我这个：

Year1	Year2	Value
2014	2014	3
2014	2015	6
2014	2016	10
2015	2015	5
2015	2016	11
2015	2017	26

group by 可以帮助对 year1 和 year2 进行分组，但我的问题是过去聚合的累积结果。

Answer 1

首先在您的组中聚合，然后使用窗口聚合：

WITH CTE AS(
    SELECT Year1,
           Year2,
           SUM([Value]) AS [Value]
    FROM dbo.YourTable
    GROUP BY Year1,
             Year2)
SELECT Year1,
       Year2,
       SUM([Value]) OVER (PARTITION BY Year1 ORDER BY Year2) AS [Value]
FROM CTE;

SQL 与之前的结果合计

SQL aggregate with the previous result

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