更改自定义函数返回的日期格式 - google 工作表/应用程序脚本
changing date format returned in custom function - google sheets/ appscript
我一直在使用这个我从之前的问题
调整过的脚本并且它一直运行良好，除了我开始在一个新的 sheet 并且日期格式现在显示为
"Tue May 03 2022 00:00:00 GMT-0800 (GMT-08:00) - 381.1
2022 年 5 月 4 日星期三 00:00:00 GMT-0800 (GMT-08:00) - 70.7"
而不是之前显示的 -
"5/3/22 - 381.1
5/4/22 - 70.7"
我确定这与源数据单元格中的日期格式有关，但我无法更改它们，因为它们正在拉动来自其他文档并比较数据。
这是我进行的测试 sheet：https://docs.google.com/spreadsheets/d/1etBO4hsrvmi_rw6F_Bw7T4DgLzHvfueIHdKa6wezWjA/edit#gid=1539515971
这是脚本，该函数在 sheet "Master":
的 A2 中调用
function createMaster(source) {
const ss = SpreadsheetApp.getActive();
const sourceSheet = ss.getSheetByName(source);
const sourceArray = sourceSheet.getRange(2,1, sourceSheet.getLastRow(), 14); // Get source data
const sourceValues = sourceArray.getValues()
const groups = sourceValues.map(row => { // Get unique combinations
return JSON.stringify([row[0]].concat(row.slice(2,6)).concat(row.slice(9,10)));
}).reverse().filter((e, i, a) => a.indexOf(e, i + 1) === -1)
.reverse().map(JSON.parse);
let groupedData = groups.map(group => {
const groupRows = sourceValues.filter(row => { // Get matching rows
return JSON.stringify([row[0]].concat(row.slice(2,6)).concat(row.slice(9,10))) === JSON.stringify(group);
});
return groupRows.reduce((acc, current) => { // Adding the values from same combination
const date = acc[1] === "" ? current[1] + " - " + current[8]: acc[1] + "\n" + current[1] + " - " + current[8];
const caseType = acc[6] === current[6] ? acc[6] : acc[6] + "\n" + String(current[6]);
const freshFrozen = acc[5] === current[5] ? acc[5] : acc[5] + "\n" + String(current[5]);
const aggregate = acc[10] === current[10] ? acc[10] : acc[10] + "\n" + String(current[10]);
const location = acc[13] === "" ? current[13] : acc[13] + "\n" + current[13];
const pallet = acc[11] === current[11] ? acc[11] : acc[11] + "\n" + String(current[11]);
const unit = (Number(acc[7]) + Number(current[7]) > 0) ? (Number(acc[7]) + Number(current[7])) : 1;
const weight = Number(acc[8]) + Number(current[8]);
const comments = acc[12] + "\n" + current[12];
return [group[0], date, ...group.slice(1,4), freshFrozen, caseType, unit, weight, group[5], aggregate, pallet, comments, location];
}, Array(14).fill(""));
});
groupedData.forEach(row => { // Removing duplicate dates, case types, locations
row[1] = [...new Set(row[1].split("\n"))].join("\n");
row[5] = [...new Set(row[5].split("\n"))].join("\n");
row[6] = [...new Set(row[6].split("\n"))].join("\n");
row[11] = [...new Set(row[11].split("\n"))].join("\n");
row[12] = [...new Set(row[12].split("\n"))].join("\n");
row[13] = [...new Set(row[13].split("\n"))].join("\n");
});
return groupedData;
}
我相信你的目标如下。
- 您想在脚本中
5/3/22 - 381.1\n5/4/22 - 70.7 而不是 Tue May 03 2022 00:00:00 GMT-0800 (GMT-08:00) - 381.1\nWed May 04 2022 00:00:00 GMT-0800 (GMT-08:00) - 70.7。
如果我的理解是正确的，下面的修改怎么样？
发件人：
return groupRows.reduce((acc, current) => { // Adding the values from same combination
const date = acc[1] === "" ? current[1] + " - " + current[8]: acc[1] + "\n" + current[1] + " - " + current[8];
收件人：
return groupRows.reduce((acc, current) => { // Adding the values from same combination
current[1] = current[1] instanceof Date ? Utilities.formatDate(current[1], ss.getSpreadsheetTimeZone(), "dd/MM/yy") : current[1]; // Added
const date = acc[1] === "" ? current[1] + " - " + current[8]: acc[1] + "\n" + current[1] + " - " + current[8];
测试：
将此修改用于您的脚本和您提供的电子表格时，将获得以下结果。
发件人：
收件人：
注：
- 根据你的问题，我使用
MM/dd/yy 作为日期格式。如果要修改为dd/MM/yy，请自行修改
参考：
试试下面的代码：
function createMaster(source) {
const ss = SpreadsheetApp.getActive();
const sourceSheet = ss.getSheetByName(source);
const sourceArray = sourceSheet.getRange(2, 1, sourceSheet.getLastRow(), 14); // Get source data
const sourceValues = sourceArray.getValues()
const groups = sourceValues.map(row => { // Get unique combinations
return JSON.stringify([row[0]].concat(row.slice(2, 6)).concat(row.slice(9, 10)));
}).reverse().filter((e, i, a) => a.indexOf(e, i + 1) === -1)
.reverse().map(JSON.parse);
let groupedData = groups.map(group => {
const groupRows = sourceValues.filter(row => { // Get matching rows
return JSON.stringify([row[0]].concat(row.slice(2, 6)).concat(row.slice(9, 10))) === JSON.stringify(group);
});
return groupRows.reduce((acc, current) => { // Adding the values from same combination
//Added codes to convert object to string and change date format *** START
if (typeof(current[1]) != "string"){
var dateString = current[1].toDateString();
var formattedDate = Utilities.formatDate(new Date(dateString), "SAST", "MM/dd/YY");
}
var date = acc[1] === "" ? formattedDate + " - " + current[8] : acc[1] + "\n" + formattedDate + " - " + current[8];
if (date == "undefined - "){
date = " - ";
}
//Added codes to convert object to string and change date format ***END
const caseType = acc[6] === current[6] ? acc[6] : acc[6] + "\n" + String(current[6]);
const freshFrozen = acc[5] === current[5] ? acc[5] : acc[5] + "\n" + String(current[5]);
const aggregate = acc[10] === current[10] ? acc[10] : acc[10] + "\n" + String(current[10]);
const location = acc[13] === "" ? current[13] : acc[13] + "\n" + current[13];
const pallet = acc[11] === current[11] ? acc[11] : acc[11] + "\n" + String(current[11]);
const unit = (Number(acc[7]) + Number(current[7]) > 0) ? (Number(acc[7]) + Number(current[7])) : 1;
const weight = Number(acc[8]) + Number(current[8]);
const comments = acc[12] + "\n" + current[12];
return [group[0], date, ...group.slice(1, 4), freshFrozen, caseType, unit, weight, group[5], aggregate, pallet, comments, location];
}, Array(14).fill(""));
});
groupedData.forEach(row => { // Removing duplicate dates, case types, locations
row[1] = [...new Set(row[1].split("\n"))].join("\n");
row[5] = [...new Set(row[5].split("\n"))].join("\n");
row[6] = [...new Set(row[6].split("\n"))].join("\n");
row[11] = [...new Set(row[11].split("\n"))].join("\n");
row[12] = [...new Set(row[12].split("\n"))].join("\n");
row[13] = [...new Set(row[13].split("\n"))].join("\n");
});
return groupedData;
}
我稍微调整了你的代码。目前您的日期是一个对象，因此必须将其转换为日期字符串，然后应用您想要的格式 MM/dd/YY，这就是我添加的代码所做的。
结果如下：
参考：
我一直在使用这个我从之前的问题
调整过的脚本并且它一直运行良好，除了我开始在一个新的 sheet 并且日期格式现在显示为
"Tue May 03 2022 00:00:00 GMT-0800 (GMT-08:00) - 381.1
2022 年 5 月 4 日星期三 00:00:00 GMT-0800 (GMT-08:00) - 70.7"
而不是之前显示的 -
"5/3/22 - 381.1
5/4/22 - 70.7"
我确定这与源数据单元格中的日期格式有关，但我无法更改它们，因为它们正在拉动来自其他文档并比较数据。
这是我进行的测试 sheet：https://docs.google.com/spreadsheets/d/1etBO4hsrvmi_rw6F_Bw7T4DgLzHvfueIHdKa6wezWjA/edit#gid=1539515971
这是脚本，该函数在 sheet "Master":
function createMaster(source) {
const ss = SpreadsheetApp.getActive();
const sourceSheet = ss.getSheetByName(source);
const sourceArray = sourceSheet.getRange(2,1, sourceSheet.getLastRow(), 14); // Get source data
const sourceValues = sourceArray.getValues()
const groups = sourceValues.map(row => { // Get unique combinations
return JSON.stringify([row[0]].concat(row.slice(2,6)).concat(row.slice(9,10)));
}).reverse().filter((e, i, a) => a.indexOf(e, i + 1) === -1)
.reverse().map(JSON.parse);
let groupedData = groups.map(group => {
const groupRows = sourceValues.filter(row => { // Get matching rows
return JSON.stringify([row[0]].concat(row.slice(2,6)).concat(row.slice(9,10))) === JSON.stringify(group);
});
return groupRows.reduce((acc, current) => { // Adding the values from same combination
const date = acc[1] === "" ? current[1] + " - " + current[8]: acc[1] + "\n" + current[1] + " - " + current[8];
const caseType = acc[6] === current[6] ? acc[6] : acc[6] + "\n" + String(current[6]);
const freshFrozen = acc[5] === current[5] ? acc[5] : acc[5] + "\n" + String(current[5]);
const aggregate = acc[10] === current[10] ? acc[10] : acc[10] + "\n" + String(current[10]);
const location = acc[13] === "" ? current[13] : acc[13] + "\n" + current[13];
const pallet = acc[11] === current[11] ? acc[11] : acc[11] + "\n" + String(current[11]);
const unit = (Number(acc[7]) + Number(current[7]) > 0) ? (Number(acc[7]) + Number(current[7])) : 1;
const weight = Number(acc[8]) + Number(current[8]);
const comments = acc[12] + "\n" + current[12];
return [group[0], date, ...group.slice(1,4), freshFrozen, caseType, unit, weight, group[5], aggregate, pallet, comments, location];
}, Array(14).fill(""));
});
groupedData.forEach(row => { // Removing duplicate dates, case types, locations
row[1] = [...new Set(row[1].split("\n"))].join("\n");
row[5] = [...new Set(row[5].split("\n"))].join("\n");
row[6] = [...new Set(row[6].split("\n"))].join("\n");
row[11] = [...new Set(row[11].split("\n"))].join("\n");
row[12] = [...new Set(row[12].split("\n"))].join("\n");
row[13] = [...new Set(row[13].split("\n"))].join("\n");
});
return groupedData;
}
我相信你的目标如下。
- 您想在脚本中
5/3/22 - 381.1\n5/4/22 - 70.7而不是Tue May 03 2022 00:00:00 GMT-0800 (GMT-08:00) - 381.1\nWed May 04 2022 00:00:00 GMT-0800 (GMT-08:00) - 70.7。
如果我的理解是正确的，下面的修改怎么样？
发件人：
return groupRows.reduce((acc, current) => { // Adding the values from same combination
const date = acc[1] === "" ? current[1] + " - " + current[8]: acc[1] + "\n" + current[1] + " - " + current[8];
收件人：
return groupRows.reduce((acc, current) => { // Adding the values from same combination
current[1] = current[1] instanceof Date ? Utilities.formatDate(current[1], ss.getSpreadsheetTimeZone(), "dd/MM/yy") : current[1]; // Added
const date = acc[1] === "" ? current[1] + " - " + current[8]: acc[1] + "\n" + current[1] + " - " + current[8];
测试：
将此修改用于您的脚本和您提供的电子表格时，将获得以下结果。
发件人：
收件人：
注：
- 根据你的问题，我使用
MM/dd/yy作为日期格式。如果要修改为dd/MM/yy，请自行修改
参考：
试试下面的代码：
function createMaster(source) {
const ss = SpreadsheetApp.getActive();
const sourceSheet = ss.getSheetByName(source);
const sourceArray = sourceSheet.getRange(2, 1, sourceSheet.getLastRow(), 14); // Get source data
const sourceValues = sourceArray.getValues()
const groups = sourceValues.map(row => { // Get unique combinations
return JSON.stringify([row[0]].concat(row.slice(2, 6)).concat(row.slice(9, 10)));
}).reverse().filter((e, i, a) => a.indexOf(e, i + 1) === -1)
.reverse().map(JSON.parse);
let groupedData = groups.map(group => {
const groupRows = sourceValues.filter(row => { // Get matching rows
return JSON.stringify([row[0]].concat(row.slice(2, 6)).concat(row.slice(9, 10))) === JSON.stringify(group);
});
return groupRows.reduce((acc, current) => { // Adding the values from same combination
//Added codes to convert object to string and change date format *** START
if (typeof(current[1]) != "string"){
var dateString = current[1].toDateString();
var formattedDate = Utilities.formatDate(new Date(dateString), "SAST", "MM/dd/YY");
}
var date = acc[1] === "" ? formattedDate + " - " + current[8] : acc[1] + "\n" + formattedDate + " - " + current[8];
if (date == "undefined - "){
date = " - ";
}
//Added codes to convert object to string and change date format ***END
const caseType = acc[6] === current[6] ? acc[6] : acc[6] + "\n" + String(current[6]);
const freshFrozen = acc[5] === current[5] ? acc[5] : acc[5] + "\n" + String(current[5]);
const aggregate = acc[10] === current[10] ? acc[10] : acc[10] + "\n" + String(current[10]);
const location = acc[13] === "" ? current[13] : acc[13] + "\n" + current[13];
const pallet = acc[11] === current[11] ? acc[11] : acc[11] + "\n" + String(current[11]);
const unit = (Number(acc[7]) + Number(current[7]) > 0) ? (Number(acc[7]) + Number(current[7])) : 1;
const weight = Number(acc[8]) + Number(current[8]);
const comments = acc[12] + "\n" + current[12];
return [group[0], date, ...group.slice(1, 4), freshFrozen, caseType, unit, weight, group[5], aggregate, pallet, comments, location];
}, Array(14).fill(""));
});
groupedData.forEach(row => { // Removing duplicate dates, case types, locations
row[1] = [...new Set(row[1].split("\n"))].join("\n");
row[5] = [...new Set(row[5].split("\n"))].join("\n");
row[6] = [...new Set(row[6].split("\n"))].join("\n");
row[11] = [...new Set(row[11].split("\n"))].join("\n");
row[12] = [...new Set(row[12].split("\n"))].join("\n");
row[13] = [...new Set(row[13].split("\n"))].join("\n");
});
return groupedData;
}
我稍微调整了你的代码。目前您的日期是一个对象，因此必须将其转换为日期字符串，然后应用您想要的格式 MM/dd/YY，这就是我添加的代码所做的。
结果如下：
参考：