根据组内列中的特定值求和值

Question

我有一个顺序数据集，我需要按已解析的不同组对值求和。每次Distinct Group列出现1，我想重新开始求和

提前致谢！！ :)

原文Table：

Customer | Order_col | Name | Val | Distinct_Group 
1        | 1         | A    | 1   |   1
1        | 2         | A    | 2   |   0
1        | 3         | A    | 3   |   0
1        | 4         | B    | 4   |   1
1        | 5         | C    | 5   |   1
1        | 6         | C    | 6   |   0
2        | 1         | A    | 1   |   1
2        | 2         | B    | 2   |   1
2        | 3         | D    | 3   |   1
2        | 4         | D    | 4   |   0

结果：

Customer | Name | Sum 
1        | A    | 6
1        | B    | 4
1        | C    | 11
2        | A    | 1
2        | B    | 2
2        | D    | 7

Answer 1

想法是使用窗口化 SUM 生成 subgrp 列，然后将聚合 SUM 用于每个名称和 subgrp。

Name | Val | Distinct_Group | subgrp
A    | 1   |   1            | 1
A    | 2   |   0            | 1
A    | 3   |   0            | 1
B    | 4   |   1            | 2
C    | 5   |   1            | 3
C    | 6   |   0            | 3

查询：

WITH cte AS (
  SELECT *, SUM(Distinct_Group) OVER(Partition by Customer ORDER BY Order Col) AS subgrp
  FROM tab
)
SELECT Customer, Name, subgrp, SUM(Val) AS Sum
FROM cte
GROUP BY Customer, Name, subgrp;