比较 BigQuery 中的两个结构递归地忽略键顺序

Compare two structs in BigQuery recursively ignoring key order

假设我有一个复杂的结构,可能有十层嵌套和重复字段。有没有内置的方法来比较这两个对象,看看它们是否相同减去键的排序?这可能与:有关。一个例子可能是:

{
    "id": "0001",
    "type": "donut",
    "topping":
        [
            { "id": "5001", "type": "None" },
            { "id": "5002", "type": "Glazed" },
            { "id": "5005", "type": "Sugar" },
            { "type": "Powdered Sugar" , "id": "5007"},
            { "id": "5006", "type": "Chocolate with Sprinkles" },
            { "id": "5003", "type": "Chocolate" },
            { "id": "5004", "type": "Maple" }
        ],
    "name": "Cake",
    "ppu": 0.55,
    "batters":
        {
            "batter":
                [
                    { "id": "1001", "type": "Regular" },
                    { "id": "1002", "type": "Chocolate" },
                    { "id": "1003", "type": "Blueberry" },
                    { "id": "1004", "type": "Devil's Food" }
                ]
        }
}

对战:

{
    "id": "0001",
    "type": "donut",
    "name": "Cake",
    "ppu": 0.55,
    "batters":
        {
            "batter":
                [
                    { "id": "1001", "type": "Regular" },
                    { "id": "1002", "type": "Chocolate" },
                    { "id": "1003", "type": "Blueberry" },
                    { "id": "1004", "type": "Devil's Food" }
                ]
        },
    "topping":
        [
            { "type": "None", "id": "5001"  },
            { "id": "5002", "type": "Glazed" },
            { "id": "5005", "type": "Sugar" },
            { "id": "5007", "type": "Powdered Sugar" },
            { "id": "5006", "type": "Chocolate with Sprinkles" },
            { "id": "5003", "type": "Chocolate" },
            { "id": "5004", "type": "Maple" }
        ]
}

,我们了解到JSON类型允许这样的比较,那么就是如何使用JSON类型作为代理来比较2个结构的问题了

with data as (
  select struct<a string, b struct<x string, y string>>('a', ('x', 'y')) col1,
         struct<b struct<y string, x string>, a string>(('y', 'x'), 'a') col2,
) select col1,
         col2,
         TO_JSON_STRING(PARSE_JSON(TO_JSON_STRING(col1))) = TO_JSON_STRING(PARSE_JSON(TO_JSON_STRING(col2)))
 from data;