将时间戳从 API 转换为日期并添加 +3 小时

Question

我有以下来自 API 调用的时间戳：

2022-05-22T13:53:42.010238Z
2022-05-22T11:53:30.910039Z
2022-05-22T11:46:43.904101Z
2022-05-22T11:46:27.815341Z
2022-05-22T11:46:12.581602Z
2022-05-22T11:41:56.246782Z
2022-05-22T11:41:39.443423Z

我想将它们转换成可读的日期示例：22/05/2022-13:53:42 并添加 +3 小时给他们。

Answer 1

在您的情况下，下面的示例脚本怎么样？

示例脚本：

function myFunction() {
  const data = [
    "2022-05-22T13:53:42.010238Z",
    "2022-05-22T11:53:30.910039Z",
    "2022-05-22T11:46:43.904101Z",
    "2022-05-22T11:46:27.815341Z",
    "2022-05-22T11:46:12.581602Z",
    "2022-05-22T11:41:56.246782Z",
    "2022-05-22T11:41:39.443423Z",
  ];
  const add = 3 * 60 * 60 * 1000;
  const res = data.map(e => Utilities.formatDate(new Date(new Date(e).getTime() + add), "GMT", "dd/MM/yyyy-HH:mm:ss"));
  console.log(res)
}

当此脚本为运行时，日志中显示如下结果。

  [
    '22/05/2022-16:53:42',
    '22/05/2022-14:53:30',
    '22/05/2022-14:46:43',
    '22/05/2022-14:46:27',
    '22/05/2022-14:46:12',
    '22/05/2022-14:41:56',
    '22/05/2022-14:41:39'
  ]

参考文献：

Answer 2

你可以试试下面的公式-

=SUM(SPLIT(SUBSTITUTE(A1,"Z",""),"T"))+TIME(3,0,0)

Answer 3

转换时间戳并增加 3 小时

function lfunko() {
  const dA = [
    "2022-05-22T13:53:42.010238Z", "2022-05-22T11:53:30.910039Z", "2022-05-22T11:46:43.904101Z", "2022-05-22T11:46:27.815341Z", "2022-05-22T11:46:12.581602Z", "2022-05-22T11:41:56.246782Z", "2022-05-22T11:41:39.443423Z"];
  dtA = dA.reduce((a, c, i) => {
    let dt = new Date(c);
    dt.setHours(new Date(c).getHours() + 3);
    a.dts.push(dt);
    return a;
  }, { dts: [] }).dts;
  Logger.log(JSON.stringify(dtA))
}

Execution log
10:06:46 PM Notice  Execution started
10:06:45 PM Info    ["2022-05-22T16:53:42.010Z","2022-05-22T14:53:30.910Z","2022-05-22T14:46:43.904Z","2022-05-22T14:46:27.815Z","2022-05-22T14:46:12.581Z","2022-05-22T14:41:56.246Z","2022-05-22T14:41:39.443Z"]
10:06:47 PM Notice  Execution completed

将时间戳从 API 转换为日期并添加 +3 小时

Convert timestamp from API into date and add +3 hours

google-apps-script

google-sheets

示例脚本：

参考文献：

转换时间戳并增加 3 小时