Bash 密码验证器

Question

我坚持使用我的 bash 代码。需要一些帮助。我试图编写 bash 代码：长度——最少 10 个字符。包含字母和数字。包括小写字母和大写字母。如果通过验证则将输出着色为绿色，否则为红色。 Return如果通过验证则退出代码0，否则退出代码1。, 可以为我解决的问题是代码不检查大小写。并且有 exit 0，这意味着密码在所有情况下都可以。

 # Color for Output
Warning='3[0;31m'        # Red
Success='3[0;32m'      # Green
NC="3[0m"            # No Color

password=
len="${#password}"
if test $len -ge 4 ; then

echo "$password" | grep -eq [[:digit:]]
if test $? -eq 1 ; then

echo "$password" | grep -e [[:upper:]]
if test $? -e 1 ; then

echo "$password" | grep -e [[:lower:]]  
if test $? -e 1 ; then

printf "${Success}Strong password!\n"
else
 echo "weak password include lower case char"
fi
else
 echo "weak password include capital char" 
fi
else
echo && echo $?
printf "${Success}Strong password!\n"
fi
else
echo $?
printf ${Warning}"Try again... \nPassword must have at least 10 characters.\n"
fi

Answer 1

在 bash 中，在 [[ ... ]] 条件中，== 和 != 运算符执行 模式匹配 。 bash 模式可以包含 POSIX 个字符类.

error() {
    echo "$*" >&2
    exit 1
}

password=

if (( ${#password} < 10 )); then
    error "Too short"
elif [[ $password != *[[:digit:]]* ]]; then
    error "Does not contain a digit"
elif [[ $password != *[[:lower:]]* ]]; then
    error "Does not contain a lower case letter"
elif [[ $password != *[[:upper:]]* ]]; then
    error "Does not contain an upper case letter"
fi

echo "OK"
exit 0

POSIX 个字符类的列表记录在 3.5.8.1 Pattern Matching

的手册中

那个cascading-if可以写得更简洁：

(( ${#password} >= 10 ))         || error "Too short"
[[ $password == *[[:digit:]]* ]] || error "Does not contain a digit"
[[ $password == *[[:lower:]]* ]] || error "Does not contain a lower case letter"
[[ $password == *[[:upper:]]* ]] || error "Does not contain an upper case letter"
echo OK

[[ ... ]]还有=~regular-expression匹配运算符（没有!~否定匹配运算符）：

# it contains a digit, or error
[[ $password =~ [[:digit:]] ]] || error "Does not contain a digit"

Bash 密码验证器

Bash Password validator

linux

passwords

validation

bash

bin