计算 class 成员被打印了多少次
Count how many times class member was printed
我需要计算 class 成员使用函数 Print
打印了多少次 inspector。构造函数应设置 class.
的私有元素
#include <cmath>
#include <iostream>
class Vector3d {
double x, y, z;
mutable int count = 0;
public:
Vector3d();
Vector3d(double x, double y, double z);
void Print() const;
int GetCount() const;
};
Vector3d::Vector3d() {
count = 0;
}
Vector3d::Vector3d(double x, double y, double z) {
count = 0;
Vector3d::x = x;
Vector3d::y = y;
Vector3d::z = z;
}
void Vector3d::Print() const {
count++;
std::cout << "{" << x << "," << y << "," << z << "}";
}
int Vector3d::GetCount() const {
return count;
}
int main() {
Vector3d v1(1, 2, 3);
v1.Print();v1.Print();v1.Print();
Vector3d v2(v1);
v2.Print();v2.Print();
std::cout << v2.GetCount();
return 0;
}
我使用 mutable
int 来启用 const 函数的更改元素。对于 v1.GetCount()
,我得到输出 3,这是正确的。但是,对于 v2.GetCount()
我得到输出 5,这是错误的(正确的是 2)。
你能帮我解决这个问题吗?我哪里出错了?
您需要为 Vector3d
class 重载复制构造函数和复制赋值运算符。
现在您正在将 count
字段的状态复制到 v2
对象中,因此它从 3 而不是 0 开始。
#include <cmath>
#include <iostream>
class Vector3d {
double x, y, z;
mutable int count = 0;
public:
Vector3d(double x, double y, double z);
Vector3d(const Vector3d&);
Vector3d& operator=(const Vector3d&);
Vector3d(Vector3d&&) = delete;
Vector3d& operator=(Vector3d&&) = delete;
void Print() const;
int GetCount() const;
};
Vector3d::Vector3d(double x, double y, double z) {
Vector3d::x = x;
Vector3d::y = y;
Vector3d::z = z;
}
Vector3d::Vector3d(const Vector3d& that)
: Vector3d(that.x, that.y, that.z)
{
}
Vector3d& Vector3d::operator=(const Vector3d& that)
{
x = that.x;
y = that.y;
z = that.z;
return *this;
}
void Vector3d::Print() const {
count++;
std::cout << "{" << x << "," << y << "," << z << "}";
}
int Vector3d::GetCount() const {
return count;
}
int main() {
Vector3d v1(1, 2, 3);
v1.Print();v1.Print();v1.Print();
Vector3d v2(v1);
v2.Print();v2.Print();
std::cout << v2.GetCount();
return 0;
}
更新:
有人提到显式删除 move ctor 和 operator 是不行的,我理解,但对我来说不清楚我们是否应该 move
反对其他实例。因此这里可能的实现方式:
#include <cmath>
#include <iostream>
class Vector3d {
double x, y, z;
mutable int count = 0;
public:
Vector3d(double x, double y, double z);
Vector3d(const Vector3d&);
Vector3d(Vector3d&&);
Vector3d& operator=(Vector3d);
void Print() const;
int GetCount() const;
private:
void swap(Vector3d&);
};
Vector3d::Vector3d(double x, double y, double z) {
Vector3d::x = x;
Vector3d::y = y;
Vector3d::z = z;
}
Vector3d::Vector3d(const Vector3d& that)
: Vector3d(that.x, that.y, that.z)
{
}
Vector3d::Vector3d(Vector3d&& that)
: Vector3d(that.x, that.y, that.z)
{
count = that.count;
}
Vector3d& Vector3d::operator=(Vector3d that)
{
swap(that);
return *this;
}
void Vector3d::swap(Vector3d& that)
{
std::swap(x, that.x);
std::swap(y, that.y);
std::swap(z, that.z);
std::swap(count, that.count);
}
void Vector3d::Print() const {
count++;
std::cout << "{" << x << "," << y << "," << z << "}";
}
int Vector3d::GetCount() const {
return count;
}
int main() {
Vector3d v1(1, 2, 3);
v1.Print();v1.Print();v1.Print();
Vector3d v2 = std::move(v1);
v2.Print();v2.Print();
std::cout << v2.GetCount();
return 0;
}
但是这些更多的是针对评论者而不是问题作者。
我需要计算 class 成员使用函数 Print
打印了多少次 inspector。构造函数应设置 class.
#include <cmath>
#include <iostream>
class Vector3d {
double x, y, z;
mutable int count = 0;
public:
Vector3d();
Vector3d(double x, double y, double z);
void Print() const;
int GetCount() const;
};
Vector3d::Vector3d() {
count = 0;
}
Vector3d::Vector3d(double x, double y, double z) {
count = 0;
Vector3d::x = x;
Vector3d::y = y;
Vector3d::z = z;
}
void Vector3d::Print() const {
count++;
std::cout << "{" << x << "," << y << "," << z << "}";
}
int Vector3d::GetCount() const {
return count;
}
int main() {
Vector3d v1(1, 2, 3);
v1.Print();v1.Print();v1.Print();
Vector3d v2(v1);
v2.Print();v2.Print();
std::cout << v2.GetCount();
return 0;
}
我使用 mutable
int 来启用 const 函数的更改元素。对于 v1.GetCount()
,我得到输出 3,这是正确的。但是,对于 v2.GetCount()
我得到输出 5,这是错误的(正确的是 2)。
你能帮我解决这个问题吗?我哪里出错了?
您需要为 Vector3d
class 重载复制构造函数和复制赋值运算符。
现在您正在将 count
字段的状态复制到 v2
对象中,因此它从 3 而不是 0 开始。
#include <cmath>
#include <iostream>
class Vector3d {
double x, y, z;
mutable int count = 0;
public:
Vector3d(double x, double y, double z);
Vector3d(const Vector3d&);
Vector3d& operator=(const Vector3d&);
Vector3d(Vector3d&&) = delete;
Vector3d& operator=(Vector3d&&) = delete;
void Print() const;
int GetCount() const;
};
Vector3d::Vector3d(double x, double y, double z) {
Vector3d::x = x;
Vector3d::y = y;
Vector3d::z = z;
}
Vector3d::Vector3d(const Vector3d& that)
: Vector3d(that.x, that.y, that.z)
{
}
Vector3d& Vector3d::operator=(const Vector3d& that)
{
x = that.x;
y = that.y;
z = that.z;
return *this;
}
void Vector3d::Print() const {
count++;
std::cout << "{" << x << "," << y << "," << z << "}";
}
int Vector3d::GetCount() const {
return count;
}
int main() {
Vector3d v1(1, 2, 3);
v1.Print();v1.Print();v1.Print();
Vector3d v2(v1);
v2.Print();v2.Print();
std::cout << v2.GetCount();
return 0;
}
更新:
有人提到显式删除 move ctor 和 operator 是不行的,我理解,但对我来说不清楚我们是否应该 move
反对其他实例。因此这里可能的实现方式:
#include <cmath>
#include <iostream>
class Vector3d {
double x, y, z;
mutable int count = 0;
public:
Vector3d(double x, double y, double z);
Vector3d(const Vector3d&);
Vector3d(Vector3d&&);
Vector3d& operator=(Vector3d);
void Print() const;
int GetCount() const;
private:
void swap(Vector3d&);
};
Vector3d::Vector3d(double x, double y, double z) {
Vector3d::x = x;
Vector3d::y = y;
Vector3d::z = z;
}
Vector3d::Vector3d(const Vector3d& that)
: Vector3d(that.x, that.y, that.z)
{
}
Vector3d::Vector3d(Vector3d&& that)
: Vector3d(that.x, that.y, that.z)
{
count = that.count;
}
Vector3d& Vector3d::operator=(Vector3d that)
{
swap(that);
return *this;
}
void Vector3d::swap(Vector3d& that)
{
std::swap(x, that.x);
std::swap(y, that.y);
std::swap(z, that.z);
std::swap(count, that.count);
}
void Vector3d::Print() const {
count++;
std::cout << "{" << x << "," << y << "," << z << "}";
}
int Vector3d::GetCount() const {
return count;
}
int main() {
Vector3d v1(1, 2, 3);
v1.Print();v1.Print();v1.Print();
Vector3d v2 = std::move(v1);
v2.Print();v2.Print();
std::cout << v2.GetCount();
return 0;
}
但是这些更多的是针对评论者而不是问题作者。