Laravel 7: 查找两个日期之间有条件的天数和日期

Question

用户提交请假申请时，需要select开始和结束日期。但在保存之前需要检查两个日期之间是否有任何假期或每周假期。如果假期或每周假期匹配，则将从总天数中扣除假期总数。

每周假期：

id	day	working_status
1	Fri	1

假日Table：（模型名称：假日）

id	date	publication_status
1	2022-05-26	1

离开Table:

id	start_date	end_date	total_days
1	2022-05-25	2022-05-28	2

控制器：

$leave = new User;
  $leave->start_date = $request->start_date;
  $leave->end_date = $request->end_date;
  
  //get and convert day name for weekly holiday compare like Fri, Sat etc.
  $start_day = date("D", strtotime($request->start_date));
  $end_day = date("D", strtotime($request->end_date));

  // get and convert date for monthly holiday compare
  $start = strtotime($request->start_date);
  $end = strtotime($request->end_date);
  
  $diff = $end - $start;
  $diff_in_days = floor($diff/(60*60*24)) + 1;
  // Suppose  Fri is holiday now we have to count how many Fri day in between start and end date. 
  here need help
   $weekly_holidays = WorkingDay::where('working_status', 1)
         ->get(['day'])->count();

    // we have to count how many Monthly holiday in between start and end date. here need help
   $monthly_holidays= Holiday::where('publication_status', 1)->get(['date'])->count();
    
   $total_days = $diff_in_days - ($weekly_holidays + $monthly_holidays);
       if($request->halfday == 1){
                $leave->total_days = 0.5;
            }
            else{
                $leave->total_days = $total_days;
            }

示例：

 WorkingDay = day = Fri
 Holiday = date = 2022-05-26
 start_date = 2022-05-25
 end_date = 2022-05-28
 total_days = 2 
 // from 25 to 28, the total days are 4, but 26 is a holiday, and 27 is Friday. Holidays can be multiple dates. If there is multiple holidays between the start and end date, it will calculate according to this.

Answer 1

实际上更容易。你不需要把它复杂化。 Carbon 来拯救这里。

$startDate = Carbon::parse('start date here');
$endDate = Carbon::parse('date string here');

$weekdays = $startDate->diffInWeekdays($endDate);

这将为您提供工作日的天差，不包括任何周末。

现在无论您使用哪个数据库，您都可以使用一个函数来获取星期几 0 stands for Sunday 和 6 for Saturday。对于Postgres，我举个例子

weekdays_holiday_count = select count(*) from holidays where date_part('dow', date) not in (0, 6) # 0 for Sunday and 6 for Saturday

此查询计算工作日的假期。我在这里给你原始查询。不过，这里的重点是在函数的魔力下。

现在你可以轻松地做数学了

$weekdays - $weekdays_holiday_count

确保在顶部导入 Carbon\Carbon。

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