Lodash isEqual - 如何获取不同对象的键

Question

我正在尝试获取一组键，这些键因比较两个对象而不同。我只能使用 isEqualWith 和 mapKeys 来做到这一点，就像这样：

const differencies = [];
const objA = {
  a: 1,
  b: 2,
  c: 3
};
const objB = {
  a: 1,
  b: 2,
  c: 100
};

function customizer(objOne, objTwo) {
  if (lodash.isEqual(objOne, objTwo)) {
    return true;
  }

  lodash.mapKeys(objOne, (value, key) => {
    if (value !== objTwo[key]) {
      differencies.push(key);
    }
  });

  return false;
}

lodash.isEqualWith(objA, objB, customizer);
console.log(differencies);

<script src="https://cdn.jsdelivr.net/npm/lodash@4.17.21/lodash.min.js"></script>
<script>const lodash = _;</script>

问题是：是否有更好的方法来获取使用 lodash 的不同对象的键？

Answer 1

由于您只需要比较键相同但值可能不同的对象，您可以利用 keys() or keysIn() (if you want to also traverse the prototype chain) and remove all entries that do not have a matching value with filter().

const objA = { a: 1, b: 2, c: 4 };
const objB = { a: 1, b: 2, c: 100 };

const differencies = lodash.filter(
  lodash.keys(objA), 
  key => objA[key] !== objB[key]
);
console.log(differencies);

<script src="https://cdn.jsdelivr.net/npm/lodash@4.17.21/lodash.min.js"></script>
<script>const lodash = _;</script>

或者使用 chaining syntax:

const objA = { a: 1, b: 2, c: 4 };
const objB = { a: 1, b: 2, c: 100 };

const differencies = lodash(objA)
  .keys()
  .filter(key => objA[key] !== objB[key]);
console.log(differencies);

<script src="https://cdn.jsdelivr.net/npm/lodash@4.17.21/lodash.min.js"></script>
<script>const lodash = _;</script>

对于这种功能，Lodash 可能有点矫枉过正。简单的 JavaScript 等价于 Object.keys() and Array#filter():

const objA = { a: 1, b: 2, c: 4 };
const objB = { a: 1, b: 2, c: 100 };

const differencies = Object.keys(objA)
  .filter(key => objA[key] !== objB[key]);
console.log(differencies);

Lodash isEqual - 如何获取不同对象的键

Lodash isEqual - How to get keys of objects that differ

javascript

key

object

typescript

lodash