测试 Rust 字符串是否包含在字符串数组中

Question

我是 Rust 初学者，我正在尝试扩展当前测试字符串与另一个字符串文字是否相等的条件，以便现在测试该字符串是否包含在字符串文字数组中。

在Python中，我会写string_to_test in ['foo','bar']。我怎样才能将它移植到 Rust？

这是我的尝试，但无法编译：

fn main() {
  let test_string = "foo";
  ["foo", "bar"].iter().any(|s| s == test_string);
}

有错误：

   Compiling playground v0.0.1 (/playground)
error[E0277]: can't compare `&str` with `str`
 --> src/main.rs:3:35
  |
3 |   ["foo", "bar"].iter().any(|s| s == test_string);
  |                                   ^^ no implementation for `&str == str`
  |
  = help: the trait `PartialEq<str>` is not implemented for `&str`
  = note: required because of the requirements on the impl of `PartialEq<&str>` for `&&str`

For more information about this error, try `rustc --explain E0277`.
error: could not compile `playground` due to previous error

不幸的是，我无法解决这个问题，也无法在 Whosebug 或论坛上找到类似的问题。

Answer 1

Herohtar建议通用解决方案：

["foo", "bar"].contains(&test_string)

PitaJ suggested this terse macro in a comment, this works only with tokens known at compile time as Finomnis 在评论中指出：

matches!(test_string, "foo" | "bar")

这就是我让代码工作的方式：

["foo", "bar"].iter().any(|&s| s == test_string);

测试 Rust 字符串是否包含在字符串数组中

Testing if Rust string is contained in an array of strings

arrays

string

contains

rust