年月日总和 - Oracle SQL

Question

一年=365天，一个月=31天

Select 1 as year, 5 as month, 10 as day from dual
union all
Select 1 as year, 10 as month, 25 as day from dual

需要结果为：

years  month  day
3      4      4

Answer 1

我们可以根据条件使用一些算法来计算天数

one year = 365 days
one month = 31 days

年份：（年 * 365 + 月 * 31 + 日）除以 365 得到数字的总年份。
Month : (month * 31 + day) 除以 31 得到总月数，但我们需要从中得到 mod 因为如果总月数大于 12 则将被携带.

作为这个查询。

select CAST(SUM((year * 365 + month * 31 + day) / 365) AS INT) years  ,
       CAST(MOD(SUM(month * 31 + day)/31, 12) AS INT) month,
       MOD(SUM(day) , 31) day
from 
(
  Select 1 as year, 5 as month, 10 as day from dual
  union all
  Select 1 as year, 10 as month, 25 as day from dual 
) t1;

sqlfiddle

Answer 2

如果 1 年 = 365 天，1 个月 = 31 天，则：

SELECT TRUNC(SUM(year*365 + month*31 + day)/365) AS years,
       TRUNC(MOD(SUM(month*31 + day), 365)/31) AS month,
       MOD(MOD(SUM(month*31 + day), 365), 31) AS day
FROM
(
  Select 1 as year, 5 as month, 10 as day from dual
  union all
  Select 1 as year, 13 as month, 25 as day from dual 
) t1;

输出：

YEARS MONTH DAY

3 7 11

如果 1 年 = 12 个月，1 个月 = 31 天，那么您需要：

SELECT TRUNC(SUM(year + month/12 + day/31/12)) AS years,
       TRUNC(MOD(SUM(month + day/31), 12)) month,
       MOD(SUM(day) , 31) day
FROM
(
  Select 1 as year, 5 as month, 10 as day from dual
  union all
  Select 1 as year, 13 as month, 25 as day from dual 
) t1;

输出：

YEARS MONTH DAY

3 7 4

db<>fiddle here

年月日总和 - Oracle SQL

Sum year, month and day - Oracle SQL

sql

oracle