未为类型 'Object' 定义运算符“[]”。尝试为 Flutter 定义运算符 '[]'
The operator '[]' isn't defined for the type 'Object'. Try defining the operator '[]' for Flutter
我正在尝试将我的数据库值存储到 class 中,但我无法使用 DataSnapshot 将其转换为我的 class。我已经添加了所有必要的空安全运算符。但是还是报错
class User {
String userID = "";
String name = "";
String phoneNo = "";
String email = "";
String password = "";
User(
{required this.userID,
required this.name,
required this.phoneNo,
required this.email,
required this.password});
User.fromSnapshot(DataSnapshot dataSnapshot) {
userID = dataSnapshot.key!;
if (dataSnapshot.value != null) {
name = dataSnapshot.value!["name"] as String;
email = dataSnapshot.value!['email'];
phoneNo = dataSnapshot.value!['phone'];
password = dataSnapshot.value!['password'];
}
}
}
我正在尝试将快照值定义为字符串,但也与其他字符串相同。
Error message
尝试
if (dataSnapshot.value != null) {
final data = dataSnapshot.value as Map;
name = data["name"] as String;
email = data['email'] as String;
phoneNo = data['phone'] as String;
password = data['password'] as String;
}
尝试指定您的 DataSnapshot 类型:
User.fromSnapshot(DataSnapshot<Map<String,dynamic>> dataSnapshot) {
userID = dataSnapshot.key!;
if (dataSnapshot.value != null) {
name = dataSnapshot.value!["name"] as String;
email = dataSnapshot.value!['email'];
phoneNo = dataSnapshot.value!['phone'];
password = dataSnapshot.value!['password'];
}
}
我正在尝试将我的数据库值存储到 class 中,但我无法使用 DataSnapshot 将其转换为我的 class。我已经添加了所有必要的空安全运算符。但是还是报错
class User {
String userID = "";
String name = "";
String phoneNo = "";
String email = "";
String password = "";
User(
{required this.userID,
required this.name,
required this.phoneNo,
required this.email,
required this.password});
User.fromSnapshot(DataSnapshot dataSnapshot) {
userID = dataSnapshot.key!;
if (dataSnapshot.value != null) {
name = dataSnapshot.value!["name"] as String;
email = dataSnapshot.value!['email'];
phoneNo = dataSnapshot.value!['phone'];
password = dataSnapshot.value!['password'];
}
}
}
我正在尝试将快照值定义为字符串,但也与其他字符串相同。
Error message
尝试
if (dataSnapshot.value != null) {
final data = dataSnapshot.value as Map;
name = data["name"] as String;
email = data['email'] as String;
phoneNo = data['phone'] as String;
password = data['password'] as String;
}
尝试指定您的 DataSnapshot 类型:
User.fromSnapshot(DataSnapshot<Map<String,dynamic>> dataSnapshot) {
userID = dataSnapshot.key!;
if (dataSnapshot.value != null) {
name = dataSnapshot.value!["name"] as String;
email = dataSnapshot.value!['email'];
phoneNo = dataSnapshot.value!['phone'];
password = dataSnapshot.value!['password'];
}
}