为开放哈希动态分配的结构数组 table
dynamically allocated struct array for open hash table
为了学习,我正在尝试用 C++ 实现一个简单的开放哈希。我对函数与数组指针的交互感到非常困惑,我已经无计可施了。
代码:
struct node{
int data;
node* next;
node* prev;
bool state;
node(){
prev = next = NULL;
state = true;
}
};
//state true means empty, state false means full.
void insert(node *array,int value){
node *current = array;
if(array->state == true){
array->data = value;
array->state = false;
} else {
node* add = new node();
add->data = value;
add->state = false;
while(current->next != NULL){
current = current->next;
}
current->next = add;
add->prev = current;
}
}
void display(node *array, int size){
node *show = new node();
for(int i = 0; i< size; i++){
if(array->state == false){
cout<<array->data;
show = array;
while(show->next != NULL){
show = show->next;
cout<<" --> "<<show->data;
}
} else {
cout<<"Empty.";
}
cout<<"\n\n";
}
}
int main(){
int size;
cout<<"Enter size of the hash table: ";
cin>>size;
node *array = new node[size];
int value;
cout<<"Enter Value: ";
cin>>value;
int index = value%size;
//inserting single value
insert(&array[index],value);
//Hash table output.
display(array,size);
return 0;
}
当我 运行 这段代码时,在数组状态为空的地方没有显示“空”,似乎整个数组具有相同的值。问题出在insert函数上,我怎么也想不通
您可以通过使 Hashtable 成为指向 Node 的指针数组来简化此操作。 nullptr
表示插槽为空,并且您没有空节点和满节点。此外,节点只需要一个下一个指针,并且通常将新条目添加到桶的开头而不是末尾(允许重复条目“替换”旧条目)。使用 Node **
.
在列表的开头插入变得非常容易
#include <cstddef>
#include <iostream>
struct Table {
struct Node {
Node * next;
int data;
Node(Node **prev, int data_) : next{*prev}, data{data_} {
*prev = this;
}
};
std::size_t size;
Node **tbl;
Table(std::size_t size_) : size{size_}, tbl{new Node*[size]} { }
~Table() {
for (std::size_t i = 0; i < size; ++i) {
Node *p = tbl[i];
while(p) {
Node *t = p->next;
delete p;
p = t;
}
}
delete[] tbl;
}
void insert(int value) {
Node **slot = &tbl[value % size];
new Node(slot, value);
}
void display() const {
for(std::size_t i = 0; i < size; i++) {
std::cout << "Slot " << i << ":";
for (const Node *node = tbl[i]; node; node = node->next) {
std::cout << " " << node->data;
}
std::cout << std::endl;
}
}
};
int main(){
std::size_t size;
std::cout << "Enter size of the hash table: ";
std::cin >> size;
Table table{size};
int value;
std::cout << "Enter Value: ";
std::cin >> value;
//inserting single value
table.insert(value);
//Hash table output.
table.display();
return 0;
}
为了学习,我正在尝试用 C++ 实现一个简单的开放哈希。我对函数与数组指针的交互感到非常困惑,我已经无计可施了。
代码:
struct node{
int data;
node* next;
node* prev;
bool state;
node(){
prev = next = NULL;
state = true;
}
};
//state true means empty, state false means full.
void insert(node *array,int value){
node *current = array;
if(array->state == true){
array->data = value;
array->state = false;
} else {
node* add = new node();
add->data = value;
add->state = false;
while(current->next != NULL){
current = current->next;
}
current->next = add;
add->prev = current;
}
}
void display(node *array, int size){
node *show = new node();
for(int i = 0; i< size; i++){
if(array->state == false){
cout<<array->data;
show = array;
while(show->next != NULL){
show = show->next;
cout<<" --> "<<show->data;
}
} else {
cout<<"Empty.";
}
cout<<"\n\n";
}
}
int main(){
int size;
cout<<"Enter size of the hash table: ";
cin>>size;
node *array = new node[size];
int value;
cout<<"Enter Value: ";
cin>>value;
int index = value%size;
//inserting single value
insert(&array[index],value);
//Hash table output.
display(array,size);
return 0;
}
当我 运行 这段代码时,在数组状态为空的地方没有显示“空”,似乎整个数组具有相同的值。问题出在insert函数上,我怎么也想不通
您可以通过使 Hashtable 成为指向 Node 的指针数组来简化此操作。 nullptr
表示插槽为空,并且您没有空节点和满节点。此外,节点只需要一个下一个指针,并且通常将新条目添加到桶的开头而不是末尾(允许重复条目“替换”旧条目)。使用 Node **
.
#include <cstddef>
#include <iostream>
struct Table {
struct Node {
Node * next;
int data;
Node(Node **prev, int data_) : next{*prev}, data{data_} {
*prev = this;
}
};
std::size_t size;
Node **tbl;
Table(std::size_t size_) : size{size_}, tbl{new Node*[size]} { }
~Table() {
for (std::size_t i = 0; i < size; ++i) {
Node *p = tbl[i];
while(p) {
Node *t = p->next;
delete p;
p = t;
}
}
delete[] tbl;
}
void insert(int value) {
Node **slot = &tbl[value % size];
new Node(slot, value);
}
void display() const {
for(std::size_t i = 0; i < size; i++) {
std::cout << "Slot " << i << ":";
for (const Node *node = tbl[i]; node; node = node->next) {
std::cout << " " << node->data;
}
std::cout << std::endl;
}
}
};
int main(){
std::size_t size;
std::cout << "Enter size of the hash table: ";
std::cin >> size;
Table table{size};
int value;
std::cout << "Enter Value: ";
std::cin >> value;
//inserting single value
table.insert(value);
//Hash table output.
table.display();
return 0;
}