如何从这组字符串中提取这个特定的数字？

Question

我正在使用 SQL Server 2014，我的 table 中有一个列（称为 RankDetails）。我需要提取出现在这些字符串中的 2 个特定数字。

排名详情栏：

RankDetails

#1 of 223 hotels in Maldives
#3 of 223 hotels in Maldives
...
#10 of 223 hotels in Maldives
...
#126 of 223 hotels in Maldives

我在找什么：

       RankDetails                Rank         OutOf

#1 of 223 hotels in Maldives       1            223
#3 of 223 hotels in Maldives       3            223
...                                ...          ...
#10 of 223 hotels in Maldives      10           223
...                                ...          ...
#126 of 223 hotels in Maldives     126          223

我可以使用以下 T-SQL 代码提取 [Rank] 列：

select 

Rank = SUBSTRING([RankDetails], PATINDEX('%[0-9]%', [RankDetails]), PATINDEX('%[0-9][a-z !@#$%^&*(()_]%', [RankDetails]) - PATINDEX('%[0-9]%', [RankDetails]) + 1),
*

from [MyTable]

但是，我很难弄清楚如何输出 [OutOf] 列。

我在此处查看：寻找可能的解决方案，但仍然无法实现。

Answer 1

可能的解决方案之一是：

DECLARE @t TABLE (
    Id          INT          NOT NULL PRIMARY KEY,
    RankDetails VARCHAR(100) NOT NULL
);

INSERT INTO @t (Id, RankDetails) VALUES (1, '#126 of 223 hotels in Maldives');
INSERT INTO @t (Id, RankDetails) VALUES (2, '#10 of 223 hotels in Maldives');


WITH Words AS
(
    SELECT Id,
           Word       = REPLACE(value, '#', ''),
           WordNumber = ROW_NUMBER () OVER (PARTITION BY Id ORDER BY (SELECT 1))
    FROM @T
    CROSS APPLY STRING_SPLIT(RankDetails, ' ')
)
SELECT Id,
       Rank  = MAX(IIF(WordNumber = 1, Word, NULL)),
       OutOf = MAX(IIF(WordNumber = 3, Word, NULL))
FROM Words
WHERE WordNumber IN (1, 3)
GROUP BY Id;

Answer 2

很遗憾您还没有（还）升级您的 SQL 服务器版本，因为较新的版本通过 openJson.[=13 等功能使这变得更加容易=]

根据您的示例数据，您可以尝试以下操作：

select RankDetails,
  Try_Convert(int, Replace(Left(rankdetails, NullIf(o, 0)-1), '#', '')) [Rank],
  Try_Convert(int, Substring(rankdetails, o+3, l)) OutOf
from t
cross apply (values(CharIndex('of ', rankdetails) ))v(o)
cross apply (values(CharIndex('hotels', rankdetails) -o -4))h(l);

示例DB<>Fiddle

只是为了好玩，更现代的版本可以这样工作：

select RankDetails, 
  Max(case when k=0 then v end) [Rank],
  Max(case when k=2 then v end) OutOf
from t
cross apply (
  select Try_Convert(int,Replace(value,'#',''))v, [key] k
  from OpenJson(Concat('["',replace(rankdetails, ' ', '","'),'"]'))
)x
group by RankDetails;

Answer 3

请尝试以下解决方案。

它正在使用 XML 和 XQuery 进行标记化。

无需解析、搜索、应用任何条件逻辑等

SQL

-- DDL and sample data population, start
DECLARE @tbl TABLE (Id int IDENTITY PRIMARY KEY, RankDetails VARCHAR(100));
insert into @tbl VALUES 
('#1 of 223 hotels in Maldives'),
('#3 of 223 hotels in Maldives'),
('#10 of 223 hotels in Maldives'),
('#126 of 223 hotels in Maldives');
-- DDL and sample data population, end

DECLARE @separator CHAR(1) = SPACE(1);

SELECT t.*
    , REPLACE(c.value('(/root/r[1]/text())[1]', 'VARCHAR(10)'),'#','') AS [Rank]
    , c.value('(/root/r[3]/text())[1]', 'INT') AS [OutOf]
FROM @tbl AS t
CROSS APPLY (SELECT TRY_CAST('<root><r><![CDATA[' + 
      REPLACE(RankDetails, @separator, ']]></r><r><![CDATA[') + 
      ']]></r></root>' AS XML)) AS t1(c);

输出

+----+--------------------------------+------+-------+
| Id |          RankDetails           | Rank | OutOf |
+----+--------------------------------+------+-------+
|  1 | #1 of 223 hotels in Maldives   |    1 |   223 |
|  2 | #3 of 223 hotels in Maldives   |    3 |   223 |
|  3 | #10 of 223 hotels in Maldives  |   10 |   223 |
|  4 | #126 of 223 hotels in Maldives |  126 |   223 |
+----+--------------------------------+------+-------+

Answer 4

样品 table 与 SP:

CREATE TABLE STUDENT_GRADE
(
STD_ID INT
,FULL_GRADE VARCHAR(200)
)
INSERT INTO STUDENT_GRADE VALUES (1,'#1 OF 50 STUDENTS IN CLASS')
INSERT INTO STUDENT_GRADE VALUES (2,'#2 OF 50 STUDENTS IN CLASS')
INSERT INTO STUDENT_GRADE VALUES (3,'#3 OF 50 STUDENTS IN CLASS')
INSERT INTO STUDENT_GRADE VALUES (4,'#4 OF 50 STUDENTS IN CLASS')
INSERT INTO STUDENT_GRADE VALUES (5,'#5 OF 50 STUDENTS IN CLASS')

SELECT *FROM STUDENT_GRADE

CREATE PROCEDURE SP_STUDENT_GRADE
AS
BEGIN
    IF OBJECT_ID('tempdb..#TEMP') IS NOT NULL
    DROP TABLE #TEMP 

    CREATE TABLE #TEMP (FULL_GRADE VARCHAR(100), RANKING VARCHAR(20), TOTAL VARCHAR(20))
    DECLARE @STRING VARCHAR(100)
    DECLARE @RANKING VARCHAR(20)
    DECLARE @TOTAL VARCHAR(20)
    DECLARE @ID INT = 1
    DECLARE @FOR_LOOP INT
    SET @FOR_LOOP = (SELECT COUNT(*) FROM STUDENT_GRADE)
    WHILE @ID <= @FOR_LOOP
    BEGIN
        SET @STRING = (SELECT FULL_GRADE FROM STUDENT_GRADE WHERE STD_ID = @ID)
        SET @RANKING = (SELECT SUBSTRING(@STRING,2,CHARINDEX(' ',@STRING)-1))

        DECLARE @STRING_TOTAL VARCHAR(100)
        SET @STRING_TOTAL = (SELECT SUBSTRING(@STRING,CHARINDEX(' ',@STRING)+1,LEN(@STRING)))
        DECLARE @STRING_TOTAL2 VARCHAR(100)
        SET @STRING_TOTAL2 = (SELECT SUBSTRING(@STRING_TOTAL,CHARINDEX(' ',@STRING_TOTAL)+1,LEN(@STRING_TOTAL)))
        SET @TOTAL = (SELECT SUBSTRING(@STRING_TOTAL2,1,CHARINDEX(' ',@STRING_TOTAL2)-1))
        
        INSERT INTO #TEMP VALUES 
        (@STRING, @RANKING, @TOTAL)
        SET @ID = @ID +1
    END
    SELECT *FROM #TEMP
END

SP_STUDENT_GRADE

Answer 5

您的数据

CREATE TABLE test
  (
     id          INT IDENTITY PRIMARY KEY,
     rankdetails VARCHAR(100)
  );

INSERT INTO test
VALUES      ('#1 of 223 hotels in Maldives'),
            ('#3 of 223 hotels in Maldives'),
            ('#10 of 223 hotels in Maldives'),
            ('#126 of 223 hotels in Maldives');

首先使用 SUBSTRING、CHARINDEX 和 REPLACE 函数

获取字符的排名和下一个

select  
Id,
RankDetails           
,REPLACE(SUBSTRING (RankDetails,0,CHARINDEX(' ',RankDetails)), '#', '') Rank
,SUBSTRING(RankDetails,CHARINDEX(' ',RankDetails)+1,LEN(RankDetails)) details
FROM test

Id	RankDetails	Rank	details
1	#1 of 223 hotels in Maldives	1	of 223 hotels in Maldives
2	#3 of 223 hotels in Maldives	3	of 223 hotels in Maldives
3	#10 of 223 hotels in Maldives	10	of 223 hotels in Maldives
4	#126 of 223 hotels in Maldives	126	of 223 hotels in Maldives

然后使用 Subquery 从详细信息列中获取值

select Id,
RankDetails,
Rank,
Left(SubString(details, PatIndex('%[0-9.-]%', details), 8000),
PatIndex('%[^0-9.-]%', SubString(details, PatIndex('%[0-9.-]%', details), 8000) + 'X')-1) OutOf 
from 
(select  
Id,
RankDetails           
,REPLACE(SUBSTRING (RankDetails,0,CHARINDEX(' ',RankDetails)), '#', '') Rank
,SUBSTRING(RankDetails,CHARINDEX(' ',RankDetails)+1,LEN(RankDetails)) details
FROM test) t

dbfiddle

如何从这组字符串中提取这个特定的数字？

How to extract this specific number from this set of strings?

sql

tsql

sql-server