如何根据ID获取重量变化并使用php和mysql显示在table中？
How to fetch weight variation according to ID and display in a table using php and mysql?
这是我的数据库 table 的样子：
cattle_id
weight
weight_date
10001
300 KG
01-01-2022
10002
350 KG
01-01-2022
10003
400 KG
01-01-2022
10001
310 KG
15-01-2022
10002
362 KG
15-01-2022
10003
415 KG
15-01-2022
10001
318 KG
30-01-2022
10002
375 KG
30-01-2022
10003
430 KG
30-01-2022
我需要一个查询来获得如下结果：
Cattle ID
Last Weight
2nd Last Weight
3rd Last Weight
Remarks
Last Weight Date
10001
318 KG
310 KG
300 KG
Not Satisfactory
30-01-2022
10002
375 KG
362 KG
350 KG
Not Satisfactory
30-01-2022
10003
430 KG
415 KG
400 KG
Satisfactory
30-01-2022
注意：每 15 天测量一次体重且每天至少增长 1 公斤为满意。
数据已正确插入数据库。我只想像上面那样检索数据。我怎样才能做到这一点？
可以使用以下查询-
with cte_1 as(
select Cattle_ID,
case
when (row_number() over (partition by Cattle_ID order by weight_date asc)) = 3 then weight end last_weight,
case when (row_number() over (partition by Cattle_ID order by weight_date asc)) = 2 then weight end 2ndlast_weight,
case when (row_number() over (partition by Cattle_ID order by weight_date asc)) = 1 then weight end 3rdlast_weight,
weight_date
from weight_calc
), cte_2 as (
select cattle_id,max(last_weight) lw,
max(2ndlast_weight) lw_2,
max(3rdlast_weight) lw_3 ,
max(weight_date) lwd
from cte_1
group by cattle_id)
select cte_2.cattle_id,
cte_2.lw as "Last Weight",
cte_2.lw_2 as "2nd Last Weight",
cte_2.lw_3 as "3rd Last Weight",
case when (lw - lw_3)>=30 then "Satisfactory" else "Not satisfactory" end remarks,
cte_2.lwd as "Last Weight"
from cte_2
这是数据库 fiddle。
这是我的数据库 table 的样子：
| cattle_id | weight | weight_date |
|---|---|---|
| 10001 | 300 KG | 01-01-2022 |
| 10002 | 350 KG | 01-01-2022 |
| 10003 | 400 KG | 01-01-2022 |
| 10001 | 310 KG | 15-01-2022 |
| 10002 | 362 KG | 15-01-2022 |
| 10003 | 415 KG | 15-01-2022 |
| 10001 | 318 KG | 30-01-2022 |
| 10002 | 375 KG | 30-01-2022 |
| 10003 | 430 KG | 30-01-2022 |
我需要一个查询来获得如下结果：
| Cattle ID | Last Weight | 2nd Last Weight | 3rd Last Weight | Remarks | Last Weight Date |
|---|---|---|---|---|---|
| 10001 | 318 KG | 310 KG | 300 KG | Not Satisfactory | 30-01-2022 |
| 10002 | 375 KG | 362 KG | 350 KG | Not Satisfactory | 30-01-2022 |
| 10003 | 430 KG | 415 KG | 400 KG | Satisfactory | 30-01-2022 |
注意：每 15 天测量一次体重且每天至少增长 1 公斤为满意。
数据已正确插入数据库。我只想像上面那样检索数据。我怎样才能做到这一点？
可以使用以下查询-
with cte_1 as(
select Cattle_ID,
case
when (row_number() over (partition by Cattle_ID order by weight_date asc)) = 3 then weight end last_weight,
case when (row_number() over (partition by Cattle_ID order by weight_date asc)) = 2 then weight end 2ndlast_weight,
case when (row_number() over (partition by Cattle_ID order by weight_date asc)) = 1 then weight end 3rdlast_weight,
weight_date
from weight_calc
), cte_2 as (
select cattle_id,max(last_weight) lw,
max(2ndlast_weight) lw_2,
max(3rdlast_weight) lw_3 ,
max(weight_date) lwd
from cte_1
group by cattle_id)
select cte_2.cattle_id,
cte_2.lw as "Last Weight",
cte_2.lw_2 as "2nd Last Weight",
cte_2.lw_3 as "3rd Last Weight",
case when (lw - lw_3)>=30 then "Satisfactory" else "Not satisfactory" end remarks,
cte_2.lwd as "Last Weight"
from cte_2
这是数据库 fiddle。