如何根据日期统计访问量？

Question

访问次数table

USER_ID	VISITED_IN
518	2022-04-13 20:37:04
518	2021-12-29 22:26:50
518	2021-03-04 04:22:46
518	2021-08-13 02:14:54
518	2022-05-26 20:49:01
518	2022-05-05 17:47:46
518	2021-09-12 08:58:33
518	2021-04-07 18:36:59
518	2021-06-14 04:47:52
518	2021-12-26 22:16:47

假设当前时间是 28-5-2022 15:00:00，我正在尝试按日期过滤访问。

执行命令时的预期结果

LAST_60_MINUTES	LAST_24_HOURS	LAST_7_DAYS	LAST_30_DAYS	LAST_6_MONTHS	LAST_12_MONTHS
0	0	1	2	5	8

这是我尝试过的方法，但无法正常工作

SELECT 
    COUNT((SELECT USER_ID FROM VISITS WHERE VISITED_IN >= DATE_SUB(NOW(), INTERVAL 60 MINUTE))) AS LAST_60_MINUTES,
    COUNT((SELECT USER_ID FROM VISITS WHERE VISITED_IN >= DATE_SUB(NOW(), INTERVAL 24 HOUR))) AS LAST_24_HOURS,
    COUNT((SELECT USER_ID FROM VISITS WHERE VISITED_IN >= DATE_SUB(NOW(), INTERVAL 7 DAY))) AS LAST_7_DAYS,
    COUNT((SELECT USER_ID FROM VISITS WHERE VISITED_IN >= DATE_SUB(NOW(), INTERVAL 30 DAY))) AS LAST_30_DAYS,
    COUNT((SELECT USER_ID FROM VISITS WHERE VISITED_IN >= DATE_SUB(NOW(), INTERVAL 6 MONTH))) AS LAST_6_MONTHS,
    COUNT((SELECT USER_ID FROM VISITS WHERE VISITED_IN >= DATE_SUB(NOW(), INTERVAL 12 MONTH))) AS LAST_12_MONTHS
    FROM VISITS WHERE
    USER_ID = 518

有关详细信息，请查看此

Answer 1

要么使用CASE表达式：

SELECT 
    COUNT(CASE WHEN VISITED_IN >= DATE_SUB(NOW(), INTERVAL 60 MINUTE) THEN 1 END) AS LAST_60_MINUTES,
    COUNT(CASE WHEN VISITED_IN >= DATE_SUB(NOW(), INTERVAL 24 HOUR) THEN 1 END) AS LAST_24_HOURS,
    COUNT(CASE WHEN VISITED_IN >= DATE_SUB(NOW(), INTERVAL 7 DAY) THEN 1 END) AS LAST_7_DAYS,
    COUNT(CASE WHEN VISITED_IN >= DATE_SUB(NOW(), INTERVAL 30 DAY) THEN 1 END) AS LAST_30_DAYS,
    COUNT(CASE WHEN VISITED_IN >= DATE_SUB(NOW(), INTERVAL 6 MONTH) THEN 1 END) AS LAST_6_MONTHS,
    COUNT(CASE WHEN VISITED_IN >= DATE_SUB(NOW(), INTERVAL 12 MONTH) THEN 1 END) AS LAST_12_MONTHS
FROM VISITS 
WHERE USER_ID = 518;

或 SUM() 而不是 COUNT():

SELECT 
    SUM(VISITED_IN >= DATE_SUB(NOW(), INTERVAL 60 MINUTE)) AS LAST_60_MINUTES,
    SUM(VISITED_IN >= DATE_SUB(NOW(), INTERVAL 24 HOUR)) AS LAST_24_HOURS,
    SUM(VISITED_IN >= DATE_SUB(NOW(), INTERVAL 7 DAY)) AS LAST_7_DAYS,
    SUM(VISITED_IN >= DATE_SUB(NOW(), INTERVAL 30 DAY)) AS LAST_30_DAYS,
    SUM(VISITED_IN >= DATE_SUB(NOW(), INTERVAL 6 MONTH)) AS LAST_6_MONTHS,
    SUM(VISITED_IN >= DATE_SUB(NOW(), INTERVAL 12 MONTH)) AS LAST_12_MONTHS
FROM VISITS 
WHERE USER_ID = 518;

参见demo。

如何根据日期统计访问量？

How can I count the visits according to the date?

mysql

sql

database

where-clause

conditional-aggregation