您如何使用 luxon / moment 判断日期时间是上午还是下午?
How do you tell if a datetime is am or pm using luxon / moment?
这个:
import {DateTime} from "luxon";
[
"2022-05-30T11:00:00Z",
"2022-05-30T11:00:00+01:00",
"2022-05-30T11:00:00-01:00",
].map(raw => {
var sysTime = DateTime.fromISO(raw);
var amPm = sysTime.hour < 12 ? "am" : "pm";
console.log(`${raw}: ${amPm}`);
});
发出这个:
2022-05-30T11:00:00Z: pm
2022-05-30T11:00:00+01:00: pm
2022-05-30T11:00:00-01:00: pm
这显然是错误的。
是的,是错误的,因为2022-05-30T11:00:00+01:00
不是那个时区的pm
。
由于 luxon 自动存储 SystemZone
,您必须明确地将其转换为正确的时区,如果您碰巧知道它是什么,例如:
[
"2022-05-30T11:00:00Z",
"2022-05-30T11:00:00+01:00",
"2022-05-30T11:00:00-01:00",
].map(raw => {
var sysTime = DateTime.fromISO(raw);
var realTime = sysTime.setZone('UTC+1'); // <---- explicit
var amPm = realTime.hour < 12 ? "am" : "pm";
console.log(`${raw}: ${amPm}`);
});
发出这个:
2022-05-30T11:00:00Z: pm <---- still wrong
2022-05-30T11:00:00+01:00: am <--- correct
2022-05-30T11:00:00-01:00: pm
那么,正确的做法是什么?
...需要说明的是,我并不是要在没有时区的情况下 解析这些日期时间 ,而是试图以一种保留“UTC+X”时区,即 在原始日期字符串中 。
这可能吗?
使用:setZone: true
在 fromISO
.
import {DateTime} from "luxon";
[
"2022-05-30T11:00:00Z",
"2022-05-30T11:00:00+01:00",
"2022-05-30T11:00:00-01:00",
].map(raw => {
var sysTime = DateTime.fromISO(raw, {setZone: true});
var amPm = sysTime.hour < 12 ? "am" : "pm";
console.log(`${raw}: ${amPm}`);
});
这个:
import {DateTime} from "luxon";
[
"2022-05-30T11:00:00Z",
"2022-05-30T11:00:00+01:00",
"2022-05-30T11:00:00-01:00",
].map(raw => {
var sysTime = DateTime.fromISO(raw);
var amPm = sysTime.hour < 12 ? "am" : "pm";
console.log(`${raw}: ${amPm}`);
});
发出这个:
2022-05-30T11:00:00Z: pm
2022-05-30T11:00:00+01:00: pm
2022-05-30T11:00:00-01:00: pm
这显然是错误的。
是的,是错误的,因为2022-05-30T11:00:00+01:00
不是那个时区的pm
。
由于 luxon 自动存储 SystemZone
,您必须明确地将其转换为正确的时区,如果您碰巧知道它是什么,例如:
[
"2022-05-30T11:00:00Z",
"2022-05-30T11:00:00+01:00",
"2022-05-30T11:00:00-01:00",
].map(raw => {
var sysTime = DateTime.fromISO(raw);
var realTime = sysTime.setZone('UTC+1'); // <---- explicit
var amPm = realTime.hour < 12 ? "am" : "pm";
console.log(`${raw}: ${amPm}`);
});
发出这个:
2022-05-30T11:00:00Z: pm <---- still wrong
2022-05-30T11:00:00+01:00: am <--- correct
2022-05-30T11:00:00-01:00: pm
那么,正确的做法是什么?
...需要说明的是,我并不是要在没有时区的情况下 解析这些日期时间 ,而是试图以一种保留“UTC+X”时区,即 在原始日期字符串中 。
这可能吗?
使用:setZone: true
在 fromISO
.
import {DateTime} from "luxon";
[
"2022-05-30T11:00:00Z",
"2022-05-30T11:00:00+01:00",
"2022-05-30T11:00:00-01:00",
].map(raw => {
var sysTime = DateTime.fromISO(raw, {setZone: true});
var amPm = sysTime.hour < 12 ? "am" : "pm";
console.log(`${raw}: ${amPm}`);
});