添加新列,其列名的值大于和小于平均值

Add new column with column names with values greater and lower than mean

我有一个数据框:

set.seed(100)
A <- floor(runif(5, min=0, max=10))
B <- floor(runif(5, min=0, max=10))
C <- floor(runif(5, min=0, max=10))
D <- floor(runif(5, min=0, max=10))
df <- data.frame(A,B,C,D)
df$ms <- rowMeans(df)
df
  A B C D   ms
1 3 4 6 6 4.75
2 2 8 8 2 5.00
3 5 3 2 3 3.25
4 0 5 3 3 2.75
5 4 1 7 6 4.50

现在,当特定行中的值在 A 列和 B 列中低于平均值并且在 C 列和 D 列中也高于平均值时,我想添加带有列名的列(较低和较高)。期望的结果:

  A B C D   ms  lower greater
1 3 4 6 6 4.75  A,B   C,D
2 2 8 8 2 5.00  A     C
3 5 3 2 3 3.25  B     NA
4 0 5 3 3 2.75  A     NA
5 4 1 7 6 4.50  A,B   C,D

我试图用 which() 来做这个但是我卡住了,你能给我一个提示吗?

lapply(apply(df,1, function(x) which(df$ms)),names)

在 base R 中,我想你可以这样做:

df$lower  <- lapply(df[1:2], \(x) x < df$ms) |>
  data.frame() |>
  apply(1, \(x) paste(names(x)[x], collapse = ","))

df$greater  <- lapply(df[3:4], \(x) x > df$ms) |>
  data.frame() |>
  apply(1, \(x) paste(names(x)[x], collapse = ","))

# Replace any zero-length strings
df[df==""]  <- NA

df
#   A B C D   ms lower greater
# 1 3 4 6 6 4.75   A,B     C,D
# 2 2 8 8 2 5.00     A       C
# 3 5 3 2 3 3.25     B    <NA>
# 4 0 5 3 3 2.75     A     C,D
# 5 4 1 7 6 4.50   A,B     C,D

您可以在基础 R 中使用 apply

df$lower <- apply(df, 1, function(x) paste(names(which(x[1:2] < x["ms"])), collapse = ", "))
df$greater <- apply(df, 1, function(x) paste(names(which(x[3:4] > x["ms"])), collapse = ", "))

  A B C D   ms lower greater
1 3 4 6 6 4.75  A, B    C, D
2 2 8 8 2 5.00     A       C
3 5 3 2 3 3.25     B        
4 0 5 3 3 2.75     A    C, D
5 4 1 7 6 4.50  A, B    C, D

另一种方法也使用 apply 但在开始时测试条件。

df$lower <- apply(df[1:2] < df$ms, 1, \(x) toString(names(which(x))))
df$greater <- apply(df[3:4] > df$ms, 1, \(x) toString(names(which(x))))

df
#  A B C D   ms lower greater
#1 3 4 6 6 4.75  A, B    C, D
#2 2 8 8 2 5.00     A       C
#3 5 3 2 3 3.25     B        
#4 0 5 3 3 2.75     A    C, D
#5 4 1 7 6 4.50  A, B    C, D

或重用代码:

cbind(df, lapply(list(lower = df[1:2] < df$ms, greater = df[3:4] > df$ms),
                 apply, 1, \(x) paste(names(x)[x], collapse=",") ))
#  A B C D   ms lower greater
#1 3 4 6 6 4.75   A,B     C,D
#2 2 8 8 2 5.00     A       C
#3 5 3 2 3 3.25     B        
#4 0 5 3 3 2.75     A     C,D
#5 4 1 7 6 4.50   A,B     C,D