如何从 MongoDB 中的数组中查找特定对象
How to find specific object from array in MongoDB
假设我有这个 MongoDB 文档:
{
"_id": {
"$oid": "628f739398580cae9c21b44f"
},
"place":"Amsterdam",
"events": [
{
"eventName": "Event one",
"eventText": "Event",
"eventDate": "010101"
"host":"Bob"
},
{
"eventName": "E2",
"eventText": "e2",
"eventDate": "020202"
"host":"John"
}
]
}
{
"_id": {
"$oid": "628f739398580cae9c21b44f"
},
"place":"London",
"events": [
{
"eventName": "e3",
"eventText": "e3",
"eventDate": "010101",
"host":"Bob"
}
]
}
我想获取 Bob 主持的事件数组块,我该怎么做?我试过像这样使用 $elemSelector
:
const result = await mongoDatabase
.collection("temp")
.find({ events: { $elemMatch: { eventName: "E2" } } })
.toArray();
console.log(JSON.stringify({ result }));
但它只是 returns 所有与所选地点相同的活动,在本例中为阿姆斯特丹。
想要的结果:
{
"eventName": "Event one",
"eventText": "Event",
"eventDate": "010101"
"host":"Bob"
},
{
"eventName": "e3",
"eventText": "e3",
"eventDate": "010101",
"host":"Bob"
}
试试这个。
db.getCollection('events_or_whatever_u_').find({'_id': ObjectId('xxxxx')})
看看这个
db.collection.aggregate({
$unwind: "$events"
},
{
$match: {
"events.host": "Bob"
}
},
{
"$project": {
"events": 1,
"_id": 0
}
},
{
"$replaceRoot": {
"newRoot": "$events"
}
})
您可以在此处尝试更多测试数据:https://mongoplayground.net/p/A1UbZdZgZmr
您可以通过简单的流水线阶段实现
db.collection.aggregate([
{
"$match": {//Match
"events.host": "Bob"
}
},
{
"$project": {
"e": {
"$filter": {//Filter matching elements
"input": "$events",
"as": "event",
"cond": {
"$eq": [
"$$event.host",
"Bob"
]
}
}
}
}
}
])
以下结构可以通过在 MongoDB 中使用 projection query 来实现,上面的一个清晰的解决方案可以是这个
db.collection("temp").find({ "events":{ $elemMatch:{ "eventName":"e3" } } }, {"events":1,"_id":0})
假设我有这个 MongoDB 文档:
{
"_id": {
"$oid": "628f739398580cae9c21b44f"
},
"place":"Amsterdam",
"events": [
{
"eventName": "Event one",
"eventText": "Event",
"eventDate": "010101"
"host":"Bob"
},
{
"eventName": "E2",
"eventText": "e2",
"eventDate": "020202"
"host":"John"
}
]
}
{
"_id": {
"$oid": "628f739398580cae9c21b44f"
},
"place":"London",
"events": [
{
"eventName": "e3",
"eventText": "e3",
"eventDate": "010101",
"host":"Bob"
}
]
}
我想获取 Bob 主持的事件数组块,我该怎么做?我试过像这样使用 $elemSelector
:
const result = await mongoDatabase
.collection("temp")
.find({ events: { $elemMatch: { eventName: "E2" } } })
.toArray();
console.log(JSON.stringify({ result }));
但它只是 returns 所有与所选地点相同的活动,在本例中为阿姆斯特丹。
想要的结果:
{
"eventName": "Event one",
"eventText": "Event",
"eventDate": "010101"
"host":"Bob"
},
{
"eventName": "e3",
"eventText": "e3",
"eventDate": "010101",
"host":"Bob"
}
试试这个。
db.getCollection('events_or_whatever_u_').find({'_id': ObjectId('xxxxx')})
看看这个
db.collection.aggregate({
$unwind: "$events"
},
{
$match: {
"events.host": "Bob"
}
},
{
"$project": {
"events": 1,
"_id": 0
}
},
{
"$replaceRoot": {
"newRoot": "$events"
}
})
您可以在此处尝试更多测试数据:https://mongoplayground.net/p/A1UbZdZgZmr
您可以通过简单的流水线阶段实现
db.collection.aggregate([
{
"$match": {//Match
"events.host": "Bob"
}
},
{
"$project": {
"e": {
"$filter": {//Filter matching elements
"input": "$events",
"as": "event",
"cond": {
"$eq": [
"$$event.host",
"Bob"
]
}
}
}
}
}
])
以下结构可以通过在 MongoDB 中使用 projection query 来实现,上面的一个清晰的解决方案可以是这个
db.collection("temp").find({ "events":{ $elemMatch:{ "eventName":"e3" } } }, {"events":1,"_id":0})