laravel 9 具有多个可选参数的路由模型绑定

Question

我定义了这条路线：

Route::get('/categories/{category}/{country}/{state?}/{county?}/{city?}', ['App\Http\Controllers\LocationController', 'show'])->withScopedBindings();

public function show(Category $category, Country $country, State $state = null, County $county = null, City $city = null) {
   echo 'ok';
}

很好，自动检查关系，使用 1、2 或 3 个可选参数。但是......我想扩展它，以便 COUNTY 并不总是强制性的。因为有些城市与州有直接关系，中间没有 county_id。城市 table 有 county_id 和 state_id，并且总是只有其中一个存在。如果我添加：

Route::get('/categories/{category}/{country}/{state?}/{city?}', ['App\Http\Controllers\LocationController', 'show'])->withScopedBindings();

只有一条路线有效。

我该如何解决这个问题？谢谢

Answer 1

您可以定义两条单独的路线

Route::get(
    '/categories/{category}/{country}/{state?}/{county?}', 
    ['App\Http\Controllers\LocationController', 'show']
)
->withScopedBindings()
->name('categories.show.county');

Route::get(
    '/categories/{category}/{country}/{state?}/{county?}/{city?}', 
    ['App\Http\Controllers\LocationController', 'show']
)
->withScopedBindings()
->name('categories.show.county.city');

然后在控制器中检查路由名称


public function show(
    Category $category, 
    Country $country, 
    State $state = null
) {
    if(
        request()->route()->named('categories.show.county') &&
         request()->route()->hasParameter('county')
    ) {
        $county = County::where(
            (new County)->getRouteKeyName(),request()->route('county')
        )
        ->firstOrFail();
    }
    if(request()->route()->named('categories.show.county.city')) {
        if(request()->route()->hasParameter('county') {
            $county = County::where(
               (new County)->getRouteKeyName(),request()->route('county')
            )
            ->firstOrFail();
        }
        
        if(request()->route()->hasParameter('city')) {
            $city = City::where(
                (new City)->getRouteKeyName(),request()->route('city')
            )
            ->firstOrFail();
        }
    }
}

Answer 2

所以，根据 Donkarnash 的回答，我终于找到了解决方案。

Route::get('/categories/{category}/{country}/{state?}/{county_slug?}/{city_slug?}',
    ['App\Http\Controllers\LocationController', 'show'])->scopeBindings();

public function show(
    Category $category,
    Country $country,
    State $state = null,
    $county_slug = null,
    $city_slug = null
) {
    if ($county_slug && $city_slug)
    {
        // two parameters present, that means the chain is state -> county -> city
        $county = County::where('state_id', $state->id)
            ->where('slug', $county_slug)
            ->firstOrFail();
        $city = City::where('county_id', $county->id)
            ->where('slug', $city_slug)
            ->firstOrFail();
    } else {
        if ($county_slug) {
            // one parameter present, that means the chain is state -> county OR state -> city
            $county = County::where('state_id', $state->id)
                ->where('slug', $county_slug)
                ->first();
            if (!$county) {
                $city_slug = $county_slug;
                $city = City::where('state_id', $state->id)
                    ->where('slug', $city_slug)
                    ->first();
            }
            if (!$county && !$city) {
                abort(404);
            }
        }
    }
}

然后在迁移状态 table:

$table->unique(['slug', 'country_id']);

县table：

$table->unique(['slug', 'state_id']);

城市table：

$table->unique(['slug', 'state_id']);
$table->unique(['slug', 'county_id']);

并且有效。唯一的缺点是，如果有属于同一州的县和市具有相同的鼻涕虫。例如，带有 slug“test”和 state_id“15”的县以及带有 slug“test”和 state_id“15”的城市。那么它将无法正常工作并导致县。但通常一个国家/地区的所有城市都有一个国家链 -> 州 -> 县 -> 市或国家 -> 州 -> 市，因此这个小缺点不会影响网站的最终结果。尽管如此，这也可以通过调整请求验证规则来解决。

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