从对象中获取所有唯一值并将它们分配到正确键下的数组中

Get all unique values from objects and assign them into array under correct key

我有一个对象数组要转换为一个对象,该对象具有分配给相同键的唯一值数组。

我怎样才能得到这个输出?

//输入

let users = [
  { id: 1, name: "Alan", surname: "Davis", age: 34, isAdmin: 'yes'},
  { id: 2, name: "John", surname: "Doe", age: 35, isAdmin: 'no'},
  { id: 3, name: "Monica", surname: "Bush", age: 25, isAdmin: 'no'},
  { id: 4, name: "Sandra", surname: "Back", age: 23, isAdmin: 'no'},
  { id: 5, name: "Jacob", surname: "Front", age: 34, isAdmin: 'yes'},
];

//输出

let unique = {
  id: [1, 2, 3 ,4 ,5],
  name: ['Alan', 'John', 'Monica', 'Sandra', 'Jacob'],
  surname: ['Davis', 'Doe', 'Bush', 'Back', 'Front'],
  age: [34, 35, 25, 23],
  isAdmin: ['yes', 'no'],
}

这是一种方法

  1. 迭代数组中第一个对象的键以生成键列表
  2. 创建相应值的数组。过滤数组中的重复项。
  3. 将键和值包装回一个对象

let users = [
  { id: 1, name: "Alan", surname: "Davis", age: 34, isAdmin: 'yes'},
  { id: 2, name: "John", surname: "Doe", age: 35, isAdmin: 'no'},
  { id: 3, name: "Monica", surname: "Bush", age: 25, isAdmin: 'no'},
  { id: 4, name: "Sandra", surname: "Back", age: 23, isAdmin: 'no'},
  { id: 5, name: "Jacob", surname: "Front", age: 34, isAdmin: 'yes'},
];

let unique = Object.fromEntries(
  Object.keys(users[0]).map(k => 
    [k, users.map(u => u[k]).filter((value, i, arr) => arr.indexOf(value) === i)]
  )
);

console.log(unique);

您可以使用Array.prototype.reduce() and for all of the items iterate over with Array.prototype.forEach() and creating a unique array with Set

代码:

const users = [{ id: 1, name: 'Alan', surname: 'Davis', age: 34, isAdmin: 'yes' },{ id: 2, name: 'John', surname: 'Doe', age: 35, isAdmin: 'no' },{ id: 3, name: 'Monica', surname: 'Bush', age: 25, isAdmin: 'no' },{ id: 4, name: 'Sandra', surname: 'Back', age: 23, isAdmin: 'no' },{ id: 5, name: 'Jacob', surname: 'Front', age: 34, isAdmin: 'yes' },]

const unique = users.reduce((a, c) => (
  Object
    .entries(c)
    .forEach(([k, v]) => a[k] = [...new Set([...(a[k] || []), v])]), 
  a
), {})

console.log(unique)