如何对 python 中数组的 JSON 个对象进行排序？

Question

我想根据键“分数”对数组的 JSON 对象进行排序。这是示例数据：

[
    {
        "name": "Hilary Carr",
        "submissions": [
            {
                "name": "Laudantium deleniti beatae fuga.",
                "date": "05/12/2021",
                "score": 37
            }
        ]
    },
{
        "name": "Frederick Williamson",
        "submissions": [
            {
                "name": "Expedita architecto voluptas autem veniam.",
                "date": "03/05/2009",
                "score": 47
            },
            {
                "name": "Animi facere excepturi.",
                "date": "01/02/2021",
                "score": 100
            }
        ]
    }
]

示例输出：

[
    {
        "name": "Hilary Carr",
        "submissions": [
            {
                "name": "Laudantium deleniti beatae fuga.",
                "date": "05/12/2021",
                "score": 37
            }
        ]
    },
{
        "name": "Frederick Williamson",
        "submissions": [
            {
                "name": "Animi facere excepturi.",
                "date": "01/02/2021",
                "score": 100
            },
            {
                "name": "Expedita architecto voluptas autem veniam.",
                "date": "03/05/2009",
                "score": 47
            }
        ]
    }
]

我尝试了这个问题中给出的解决方案，但是我的JSON数据被这个弄乱了。这是我尝试过的：

for i in range(len(inputData)):
    sample_data_sort = dict(inputData)
    sample_data_sort = sorted(inputData[i]['submissions'], key=lambda x : x['score'], reverse=True)
    print(sample_data_sort)

我得到的输出：

[
  {
   "name": "Laudantium deleniti beatae fuga.",
   "date": "05/12/2021",
   "score": 37
   }
],
[
 {
 "name": "Animi facere excepturi.",
 "date": "01/02/2021",
 "score": 100
 },
 {
  "name": "Expedita architecto voluptas autem veniam.",
  "date": "03/05/2009",
  "score": 47
 }
]

如你所见，我把残缺不全的 JSON 找回来了。能否请您提供一些提示来纠正此问题，以便我得到的输出与输入相似？

Answer 1

Python字典条目以key:value对出现，可以通过键名进行引用。

如果允许修改原点JSON对象。

就这样：


def sort_submissions_of_items(json_list):
    for item in json_list:
        subs = item.get("submissions", [])
        if isinstance(subs, list):
            subs.sort(key=lambda x: x.get("score", 0), reverse=True)

sort_submissions_of_items(inputData)

Answer 2

试试这个
只需对内部字典进行排序，然后通过列表推导组合它们
并且会保证数据的原始结构

a = [
    {
        "name": "Hilary Carr",
        "submissions": [
            {
                "name": "Laudantium deleniti beatae fuga.",
                "date": "05/12/2021",
                "score": 37
            }
        ]
    },
    {
        "name": "Frederick Williamson",
        "submissions": [
            {
                "name": "Expedita architecto voluptas autem veniam.",
                "date": "03/05/2009",
                "score": 47
            },
            {
                "name": "Animi facere excepturi.",
                "date": "01/02/2021",
                "score": 100
            }
        ]
    }
]


result = [
    {
        "name": i["name"],
        "submissions": sorted(i["submissions"], key=lambda x: x["score"], reverse=True)
    }
    for i in a
]
print(result)

输出

[{'name': 'Hilary Carr', 'submissions': [{'name': 'Laudantium deleniti beatae fuga.', 'date': '05/12/2021', 'score': 37}]}, {'name': 'Frederick Williamson', 'submissions': [{'name': 'Animi facere excepturi.', 'date': '01/02/2021', 'score': 100}, {'name': 'Expedita architecto voluptas autem veniam.', 'date': '03/05/2009', 'score': 47}]}]

Answer 3

关键在这段代码

...sorted(inputData[i]['submissions']...

您没有对全部数据进行排序。相反，您正在做的是：

你取出原始数组中的每个元素（inputData[i]）
您只选择了 submissions 字段
您根据值 score

submissions

你想要的解决方案大概是这样的

outputData = [{**i, 'submissions': sorted(i['submissions'], key= lambda j: j['score'], reverse=True)} for i in inputData]

我建议通读它并将其与您的原始解决方案进行比较 :D

如何对 python 中数组的 JSON 个对象进行排序？

How to sort JSON objects of arrays in python?

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json