获取 SQL 中 XML 文件的所有值

Question

<MEMBER>
                <LABEL>[None]</LABEL>
                <AT Name="DefCurrency">[None]</AT>
                <AT Name="AllowAdjs">N</AT>
                <AT Name="IsICP">N</AT>
                <AT Name="AllowAdjFromChildren">N</AT>
                <AT Name="SecurityClass">NONE</AT>
                <AT Name="UserDefined1"> </AT>
                <AT Name="UserDefined2"> </AT>
                <AT Name="UserDefined3"> </AT>
                <AT Name="HoldingCompany"></AT>
                <AT Name="SecurityAsPartner"></AT>
                <DEFAULTPARENT>#root</DEFAULTPARENT>
                <DESCRIPTION Language="English">None</DESCRIPTION>
</MEMBER>

我尝试了 @Name，我得到了所有值，例如 DefCurrency、IsICP 等，但我没有得到这些值。

请参阅下面的代码。

DECLARE @XML AS XML, @hDoc AS INT
SELECT @XML = XMLData FROM XMLwithOpenXML

EXEC sp_xml_preparedocument @hDoc OUTPUT, @XML

SELECT      
            LABEL,
        
            val

FROM OPENXML(@hDoc, '/MEMBER/AT')
WITH 
(
LABEL [varchar](50) '@Name',

val [varchar](50) '../AT'


)

提前致谢

Answer 1

所有受支持的 Microsoft SQL Server 版本都有 nodes() and value() 方法可用于查询 XML 数据类型，例如：

declare @xml xml = '<MEMBER>
                <LABEL>[None]</LABEL>
                <AT Name="DefCurrency">[None]</AT>
                <AT Name="AllowAdjs">N</AT>
                <AT Name="IsICP">N</AT>
                <AT Name="AllowAdjFromChildren">N</AT>
                <AT Name="SecurityClass">NONE</AT>
                <AT Name="UserDefined1"> </AT>
                <AT Name="UserDefined2"> </AT>
                <AT Name="UserDefined3"> </AT>
                <AT Name="HoldingCompany"></AT>
                <AT Name="SecurityAsPartner"></AT>
                <DEFAULTPARENT>#root</DEFAULTPARENT>
                <DESCRIPTION Language="English">None</DESCRIPTION>
</MEMBER>';

select
  at.value(N'@Name', N'nvarchar(128)') as LABEL,
  at.value(N'(text())[1]', N'nvarchar(128)') as val
from @xml.nodes(N'/MEMBER/AT') member(at);

产生输出：

LABEL	val
DefCurrency	[None]
AllowAdjs	N
IsICP	N
AllowAdjFromChildren	N
SecurityClass	NONE
UserDefined1
UserDefined2
UserDefined3
HoldingCompany
SecurityAsPartner

如@Charlieface 所述，您还可以直接查询 table 并 cross apply 使用 nodes() 方法：

select
  at.value(N'@Name', N'nvarchar(128)') as LABEL,
  at.value(N'(text())[1]', N'nvarchar(128)') as val
from XMLwithOpenXML
cross apply XMLData.nodes(N'/MEMBER/AT') member(at);

可以叠加多层cross apply ... .nodes()，所以要包含LABEL元素的内容可以修改如下代码：

select
  label.value(N'(text())[1]', 'nvarchar(128)') as LabelValue,
  at.value(N'@Name', N'nvarchar(128)') as LABEL,
  at.value(N'(text())[1]', N'nvarchar(128)') as val
from XMLwithOpenXML
cross apply XMLData.nodes(N'/MEMBER') nodes1(member)
cross apply member.nodes(N'LABEL') nodes2(label)
cross apply member.nodes(N'AT') nodes3(at);

产生输出：

LabelValue	LABEL	val
[None]	DefCurrency	[None]
[None]	AllowAdjs	N
[None]	IsICP	N
[None]	AllowAdjFromChildren	N
[None]	SecurityClass	NONE
[None]	UserDefined1
[None]	UserDefined2
[None]	UserDefined3
[None]	HoldingCompany
[None]	SecurityAsPartner

不过，您很可能不想在多行中重复 LABEL 元素的值，因此您可以改用 XQuery 来过滤 Name 属性并有效地转换数据具有以下内容：

select
  label.value(N'(text())[1]', 'nvarchar(128)') as LabelValue,
  member.value(N'(AT[@Name="DefCurrency"]/text())[1]', N'nvarchar(128)') as DefCurrency,
  member.value(N'(AT[@Name="AllowAdjs"]/text())[1]', N'nvarchar(128)') as AllowAdjs,
  member.value(N'(AT[@Name="IsICP"]/text())[1]', N'nvarchar(128)') as IsICP,
  member.value(N'(AT[@Name="AllowAdjFromChildren"]/text())[1]', N'nvarchar(128)') as AllowAdjFromChildren,
  member.value(N'(AT[@Name="SecurityClass"]/text())[1]', N'nvarchar(128)') as SecurityClass,
  member.value(N'(AT[@Name="UserDefined1"]/text())[1]', N'nvarchar(128)') as UserDefined1,
  member.value(N'(AT[@Name="UserDefined2"]/text())[1]', N'nvarchar(128)') as UserDefined2,
  member.value(N'(AT[@Name="UserDefined3"]/text())[1]', N'nvarchar(128)') as UserDefined3,
  member.value(N'(AT[@Name="HoldingCompany"]/text())[1]', N'nvarchar(128)') as HoldingCompany,
  member.value(N'(AT[@Name="SecurityAsPartner"]/text())[1]', N'nvarchar(128)') as SecurityAsPartner
from XMLwithOpenXML
cross apply XMLData.nodes(N'/MEMBER') nodes1(member)
cross apply member.nodes(N'LABEL') nodes2(label);

LabelValue	DefCurrency	AllowAdjs	IsICP	AllowAdjFromChildren	SecurityClass	UserDefined1	UserDefined2	UserDefined3	HoldingCompany	SecurityAsPartner
[None]	[None]	N	N	N	NONE

获取 SQL 中 XML 文件的所有值

Get all values for the XML file in SQL

sql

sql-server

xml