在 SQL 中使用 "OR" 和 "INTERSECT"

Question

我只有一个Table Table一个像下面这样:

ID	Type	Date
First	BS	12-APR-22
First	GH	10-MAY-22
First	MPN	15-APR-22
Second	BS	10-MAY-22
Second	MPN	10-MAY-22
Third	GH	10-MAY-22
Third	BS	10-MAY-22
Fourth	MPN	15-MAY-22
Fourth	GH	15-MAY-22
Fifth	GH	06-MAY-22

我想实现如下输出：

ID	Type	Date
First	BS	12-APR-22
First	GH	10-MAY-22
First	MPN	15-APR-22
Second	BS	10-MAY-22
Second	MPN	10-MAY-22
Third	GH	10-MAY-22
Third	BS	10-MAY-22

我有如下查询，但没有看到任何输出：

Select ID from TableA 
WHERE 
(DATE BETWEEN '13-APR-22' AND '11-MAY-22') 
AND
(
(TYPE = 'BS' AND TYPE = 'GH') 
OR
(TYPE = 'GH' AND TYPE = 'MPN') 
OR
(TYPE = 'BS' AND TYPE = 'MPN')

);

我也尝试了以下方法，但在输出中出现错误：

Select ID from TableA WHERE (DATE BETWEEN '13-APR-22' AND '11-MAY-22') AND (TYPE = 'BS')

INTERSECT

Select ID from TableA WHERE (DATE BETWEEN '13-APR-22' AND '11-MAY-22') AND (TYPE = 'GH')

OR

Select ID from TableA WHERE (DATE BETWEEN '13-APR-22' AND '11-MAY-22') AND (TYPE = 'GH')

INTERSECT

Select ID from TableA WHERE (DATE BETWEEN '13-APR-22' AND '11-MAY-22') AND (TYPE = 'MPN')

OR

Select ID from TableA WHERE (DATE BETWEEN '13-APR-22' AND '11-MAY-22') AND (TYPE = 'BS')

INTERSECT

Select ID from TableA WHERE (DATE BETWEEN '13-APR-22' AND '11-MAY-22') AND (TYPE = 'MPN')

请帮助我实现我正在寻找的输出。提前致谢！

Answer 1

我会在这里使用聚合方法：

WITH cte AS (
    SELECT ID
    FROM TableA
    WHERE "DATE" BETWEEN date '2022-04-13' AND date '2022-05-11'
    GROUP BY ID
    HAVING
        (COUNT(CASE WHEN TYPE = 'BS' THEN 1 END) > 0 AND
         COUNT(CASE WHEN TYPE = 'GH' THEN 1 END) > 0)
        OR
        (COUNT(CASE WHEN TYPE = 'GH' THEN 1 END) > 0 AND
         COUNT(CASE WHEN TYPE = 'MPN' THEN 1 END) > 0)
        OR
        (COUNT(CASE WHEN TYPE = 'BS' THEN 1 END) > 0 AND
         COUNT(CASE WHEN TYPE = 'MPN' THEN 1 END) > 0)
)

SELECT *
FROM TableA
WHERE ID IN (SELECT ID FROM cte);

Answer 2

使用分析函数和条件聚合，这样您就不必查询 table 两次：

SELECT id, type, "DATE"
FROM   (
  SELECT t.*,
         COUNT(
           CASE
           WHEN TYPE = 'BS'
           AND  "DATE" >= DATE '2022-04-13'
           AND  "DATE" <  DATE '2022-05-12'
           THEN 1
           END
         ) OVER (PARTITION BY id) AS num_bs,
         COUNT(
           CASE
           WHEN TYPE = 'GH'
           AND  "DATE" >= DATE '2022-04-13'
           AND  "DATE" <  DATE '2022-05-12'
           THEN 1
           END
         ) OVER (PARTITION BY id) AS num_gh,
         COUNT(
           CASE
           WHEN TYPE = 'MPN'
           AND  "DATE" >= DATE '2022-04-13'
           AND  "DATE" <  DATE '2022-05-12'
           THEN 1
           END
         ) OVER (PARTITION BY id) AS num_mpn
  FROM   tableA t
)
WHERE (num_bs > 0 AND num_gh > 0)
OR    (num_bs > 0 AND num_mpn > 0)
OR    (num_gh > 0 AND num_mpn > 0)

其中，对于示例数据：

CREATE TABLE tablea (ID, Type, "DATE") AS
SELECT 'First',  'BS',  DATE '2022-04-12' FROM DUAL UNION ALL
SELECT 'First',  'GH',  DATE '2022-05-10' FROM DUAL UNION ALL
SELECT 'First',  'MPN', DATE '2022-04-15' FROM DUAL UNION ALL
SELECT 'Second', 'BS',  DATE '2022-05-10' FROM DUAL UNION ALL
SELECT 'Second', 'MPN', DATE '2022-05-10' FROM DUAL UNION ALL
SELECT 'Third',  'GH',  DATE '2022-05-10' FROM DUAL UNION ALL
SELECT 'Third',  'BS',  DATE '2022-05-10' FROM DUAL UNION ALL
SELECT 'Fourth', 'MPN', DATE '2022-05-15' FROM DUAL UNION ALL
SELECT 'Fourth', 'GH',  DATE '2022-05-15' FROM DUAL UNION ALL
SELECT 'Fifth',  'GH',  DATE '2022-05-06' FROM DUAL;

输出：

ID TYPE DATE

First GH 10-MAY-22

First MPN 15-APR-22

First BS 12-APR-22

Second BS 10-MAY-22

Second MPN 10-MAY-22

Third GH 10-MAY-22

Third BS 10-MAY-22

db<>fiddle here

在 SQL 中使用 "OR" 和 "INTERSECT"

Use of "OR" and "INTERSECT" in SQL

sql

oracle