如何使 complex/long 运行 SQL 查询更有效率？

Question

我创建了一个从多个 table 中检索数据的查询。当我运行它时，执行需要大约 200 秒。我现在正在尝试使查询更有效率，但我已达到我的极限并且无法找到解决方案。您是否知道我可以如何改进以下查询？

SELECT s1.otherdeed_id, s1.timestamp_start, s1.listingprice, s1.listing_currency, otherdeed_index.category, otherdeed_index.koda_id, kodas.mega, otherdeed_index.artifact_name, otherdeed_index.sediment
FROM otherdeed_opensea_listings s1
JOIN (
  SELECT otherdeed_id, listingprice, MAX(timestamp_start) AS timestamp_start
  FROM otherdeed_opensea_listings
  GROUP BY otherdeed_id) AS s2
  ON s1.otherdeed_id = s2.otherdeed_id AND s1.timestamp_start = s2.timestamp_start
INNER JOIN otherdeed_index ON otherdeed_index.id_otherdeed = s1.otherdeed_id 
INNER JOIN kodas ON otherdeed_index.koda_id = kodas.kodaname
ORDER BY otherdeed_id;

查询应提供 otherdeed_opensea_listings table（16k条目）并将其与 tables otherdeed_index（100k 条目）和 kodas (10k 条目) 获取一些相关数据进行分析。

我将 otherdeed_opensea_listings table 分组，每个只得到一个结果otherdeedid，此外，只获取最高 timestamp_start[=38= 的最新结果也很重要]值。

下面你可以看到我的sql结构：

CREATE TABLE `kodas` ( `kodaid` int(11) NOT NULL AUTO_INCREMENT, `kodaname` int(11) NOT NULL, `image` varchar(255) NOT NULL, `mega` tinyint(1) NOT NULL, `clothing` varchar(100) NOT NULL, `core` varchar(100) NOT NULL, `eyes` varchar(100) NOT NULL, `head` varchar(100) NOT NULL, `weapon` varchar(100) NOT NULL, PRIMARY KEY (`kodaid`) ) ENGINE=InnoDB AUTO_INCREMENT=10001 DEFAULT CHARSET=utf8 CREATE TABLE `otherdeed_index` ( `id` int(11) NOT NULL AUTO_INCREMENT, `id_otherdeed` int(11) NOT NULL, `plot` int(11) NOT NULL, `image` varchar(200) NOT NULL, `category` varchar(20) NOT NULL, `sediment` varchar(40) NOT NULL, `sediment_tier` tinyint(1) NOT NULL, `environment` varchar(50) NOT NULL, `environment_tier` tinyint(1) NOT NULL, `artifact_name` varchar(80) NOT NULL, `r_east` varchar(20) NOT NULL, `r_west` varchar(20) NOT NULL, `r_south` varchar(20) NOT NULL, `r_north` varchar(20) NOT NULL, `r_east_tier` tinyint(1) NOT NULL, `r_west_tier` tinyint(1) NOT NULL, `r_south_tier` tinyint(1) NOT NULL, `r_north_tier` tinyint(1) NOT NULL, `koda_id` int(6) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=InnoDB AUTO_INCREMENT=115001 DEFAULT CHARSET=utf8 CREATE TABLE `otherdeed_opensea_listings` ( `id` bigint(20) NOT NULL AUTO_INCREMENT, `eventid` bigint(20) NOT NULL, `event_type` varchar(10) NOT NULL, `auction_type` varchar(10) NOT NULL, `otherdeed_id` int(9) NOT NULL, `timestamp_created` int(11) NOT NULL, `timestamp_start` int(11) NOT NULL, `timestamp_end` int(11) NOT NULL, `duration_active` int(11) NOT NULL, `listingprice` float NOT NULL, `listing_currency` varchar(20) NOT NULL, `status` tinyint(1) NOT NULL, PRIMARY KEY (`id`) ) ENGINE=InnoDB AUTO_INCREMENT=418927 DEFAULT CHARSET=utf8

我的 sql 查询的输出：（解释 select）

Answer 1

您肯定需要一些索引。尝试添加以下内容：

ALTER TABLE otherdeed_opensea_listings 
ADD INDEX timestamp_start (timestamp_start),
ADD INDEX otherdeed_id (otherdeed_id);

ALTER TABLE otherdeed_index 
ADD INDEX id_otherdeed (id_otherdeed),
ADD INDEX koda_id (koda_id);

ALTER TABLE kodas 
ADD INDEX kodaname (kodaname);

这可能会给您更快的结果。这是 fiddle test with explain.

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