Return 具有相同子数组元素的文档

Question

我有以下合集：

{ "_id" : 1, "tags" : [ "school", "home" ] }
{ "_id" : 2, "tags" : [ "school", "storage", "home" ] }
{ "_id" : 3, "tags" : [ "school", "storage", "home", "bones" ] }
{ "_id" : 4, "tags" : [ "school", "storage", "home", "bones", "milk" ] }
{ "_id" : 5, "tags" : [ "homes", "maps", "bones" ] }
{ "_id" : 6, "tags" : [ "xxx", "yyy", "zzz" ] }

我想 return 所有“标签”与具有完全相同数组元素的文档相匹配的文档。

因此，如果我要查询标签 == ["school", "home"] 或标签 == ["home", "school"]，文档 w/ _id=1 将是 returned

我正在做以下事情：

db.test.find({tags: {$in: ['school', 'home']}}) or 
db.test.find({tags: {$in: ['home', 'school']}})

以下是 return编辑的：

{ "_id" : 1, "tags" : [ "school", "home" ] }
{ "_id" : 2, "tags" : [ "school", "storage", "home" ] }
{ "_id" : 3, "tags" : [ "school", "storage", "home", "bones" ] }
{ "_id" : 4, "tags" : [ "school", "storage", "home", "bones", "milk" ] }

我怎样才能实现只有 _id=1 的项目被 returned？

Answer 1

也许是这样的：

选项 1：

 db.collection.find({
  $and: [
 {
  tags: "school"
 },
 {
  tags: "home"
 },
 {
  tags: {
      $size: 2
    }
 }
 ]
})

解释：

如果学校和家庭在标签数组中并且数组大小为 2，则匹配。

Playground

选项 2：

db.collection.find({
 $or: [
  {
    tags: [
    "school",
    "home"
  ]
  },
  {
  tags: [
    "home",
    "school"
  ]
  }
 ]
})

解释：

匹配两个可能的数组选项

Playground2

Return 具有相同子数组元素的文档

Return Documents with Same Subarray elements

arrays

mongodb