Javascript: 合并对象数组

Question

我有一个包含嵌套对象的对象数组，如下所示：

[
  {
    "metric1": 4.1,
    "addons": {
      "call_uuid_1": "13d1e097-0363-4a81-b9e4-85c6a770cdb2",
      "ThisDN_1": "50002",
      "call_uuid": "13d1e097-0363-4a81-b9e4-85c6a770cdb4",
      "ThisDN": "50004"
    }
  },
  {
    "metric2": -12345.123412341234,
    "addons": {
      "call_uuid_2": "13d1e097-0363-4a81-b9e4-85c6a770cdb3",
      "ThisDN_2": "50003",
      "call_uuid": "13d1e097-0363-4a81-b9e4-85c6a770cdb4",
      "ThisDN": "50004"
    }
  },
  {
    "metric3": -2345.123412341234,
    "addons": {
      "call_uuid_1": "13d1e097-0363-4a81-b9e4-85c6a770cdb2",
      "ThisDN_1": "50002",
      "call_uuid": "13d1e097-0363-4a81-b9e4-85c6a770cdb4",
      "ThisDN": "50004"
    }
  },
  {
    "metric4": -345.12341234123414,
    "addons": {
      "call_uuid_2": "13d1e097-0363-4a81-b9e4-85c6a770cdb3",
      "ThisDN_2": "50003",
      "call_uuid": "13d1e097-0363-4a81-b9e4-85c6a770cdb4",
      "ThisDN": "50004"
    }
  }
]

我想合并一些数组对象与同一个嵌套对象addons，这样之前的数组就变成：

[
  {
    "metric1": 4.1,
    "metric3": -2345.123412341234,
    "addons": {
      "call_uuid_1
": "13d1e097-0363-4a81-b9e4-85c6a770cdb2",
      "ThisDN_1": "50002",
      "call_uuid": "13d1e097-0363-4a81-b9e4-85c6a770cdb4",
      "ThisDN": "50004"
    }
  },
  {
    "metric2": -12345.123412341234,
    "metric4": -345.12341234123414,
    "addons": {
      "call_uuid_2": "13d1e097-0363-4a81-b9e4-85c6a770cdb3",
      "ThisDN_2": "50003",
      "call_uuid": "13d1e097-0363-4a81-b9e4-85c6a770cdb4",
      "ThisDN": "50004"
    }
  }
]

有没有办法做到这一点？

Answer 1

您可以使用 JSON.stringify 在 addons 对象中寻找相等性，然后合并您的对象。像这样：

const array = [
  {
    "metric1": 4.1,
    "addons": {
      "call_uuid_1": "13d1e097-0363-4a81-b9e4-85c6a770cdb2",
      "ThisDN_1": "50002",
      "call_uuid": "13d1e097-0363-4a81-b9e4-85c6a770cdb4",
      "ThisDN": "50004"
    }
  },
  {
    "metric2": -12345.123412341234,
    "addons": {
      "call_uuid_2": "13d1e097-0363-4a81-b9e4-85c6a770cdb3",
      "ThisDN_2": "50003",
      "call_uuid": "13d1e097-0363-4a81-b9e4-85c6a770cdb4",
      "ThisDN": "50004"
    }
  },
  {
    "metric3": -2345.123412341234,
    "addons": {
      "call_uuid_1": "13d1e097-0363-4a81-b9e4-85c6a770cdb2",
      "ThisDN_1": "50002",
      "call_uuid": "13d1e097-0363-4a81-b9e4-85c6a770cdb4",
      "ThisDN": "50004"
    }
  },
  {
    "metric4": -345.12341234123414,
    "addons": {
      "call_uuid_2": "13d1e097-0363-4a81-b9e4-85c6a770cdb3",
      "ThisDN_2": "50003",
      "call_uuid": "13d1e097-0363-4a81-b9e4-85c6a770cdb4",
      "ThisDN": "50004"
    }
  }
];

const mergedArray = [];
const addonsToIndexMap = {};

array.forEach(item => {
 const stringifyAddon = JSON.stringify(item.addons);    
 let indexInTheMap = addonsToIndexMap[stringifyAddon];
 if(indexInTheMap !== undefined) {
   mergedArray[indexInTheMap] = {...mergedArray[indexInTheMap], ...item};
 } else {
   mergedArray.push(item);
   addonsToIndexMap[stringifyAddon] = mergedArray.length - 1;
 }
});
console.log(mergedArray);

使用addonsToIndexMap只是为了优化目的。 注意： 此方法仅在 addon 对象中的键顺序相同时有效。此外，我纠正了我程序中的输入，以更新密钥 call_uuid_l 和 call_uuid_1 以获得预期的输出，如评论中所述。请相应修改。

Answer 2

如果数组中有多个元素具有相同的 addons 对象，您可以删除第一个的 addons 对象，然后将其与其他元素合并。

for (let i = 0; i < arr.length; i++) {
  for (let j = i + 1; j < arr.length; j++) {
    if (JSON.stringify(arr[i]["addons"]) === JSON.stringify(arr[j]["addons"])) {
      delete arr[i]["addons"];
      Object.assign(arr[i], arr[j]);
      arr.splice(j, 1);
      j -= 1;
    }
  }
}

输出：

[
  {
    metric1: 4.1,
    metric3: -2345.123412341234,
    addons: {
      call_uuid_1: '13d1e097-0363-4a81-b9e4-85c6a770cdb2',
      ThisDN_1: '50002',
      call_uuid: '13d1e097-0363-4a81-b9e4-85c6a770cdb4',
      ThisDN: '50004'
    }
  },
  {
    metric2: -12345.123412341234,
    metric4: -345.12341234123414,
    addons: {
      call_uuid_2: '13d1e097-0363-4a81-b9e4-85c6a770cdb3',
      ThisDN_2: '50003',
      call_uuid: '13d1e097-0363-4a81-b9e4-85c6a770cdb4',
      ThisDN: '50004'
    }
  }
]

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