Django graphene - 无需打字的突变输入
Django graphene - mutation input without typing
在突变中,我只需要保存事件名称及其可能不同的负载,我不需要对其进行任何验证。我怎么能说石墨烯我只需要接受一个物体?
class SendEvent(MutationMixin, relay.ClientIDMutation):
class Input:
event = graphene.String(required=True)
payload = # any object
希望大家可以使用GenericScalar(...)
from graphene.types.generic import GenericScalar
class SendEvent(MutationMixin, relay.ClientIDMutation):
class Input:
event = graphene.String(required=True)
payload = <b>GenericScalar(required=True)</b>
在突变中,我只需要保存事件名称及其可能不同的负载,我不需要对其进行任何验证。我怎么能说石墨烯我只需要接受一个物体?
class SendEvent(MutationMixin, relay.ClientIDMutation):
class Input:
event = graphene.String(required=True)
payload = # any object
希望大家可以使用GenericScalar(...)
from graphene.types.generic import GenericScalar
class SendEvent(MutationMixin, relay.ClientIDMutation):
class Input:
event = graphene.String(required=True)
payload = <b>GenericScalar(required=True)</b>