如何用 serde 重命名 `start` 和 `end` 范围值?
How to rename `start` and `end` range values with serde?
我有 JSON 个格式如下的对象:
{
"name": "foo",
"value": 1234,
"upper_bound": 5000,
"lower_bound": 1000
}
我想使用 serde 来处理这些对象,结构类似于
struct MyObject {
name: String,
value: i32,
bound: Range<i32>,
}
在没有任何修改的情况下,序列化这些结构之一会产生
{
"name": "foo",
"value": 1234,
"bound": {
"start": 1000,
"end": 5000
}
}
我可以申请#[serde(flatten)]
靠近,屈服
{
"name": "foo",
"value": 1234,
"start": 1000,
"end": 5000
}
但是添加 #[serde(rename...)]
似乎没有任何改变,无论我尝试为重命名提供什么样的参数。是否可以展平范围并重命名参数?
你可以使用 serde 属性 with
并且只使用一个中间结构让真正的实现到 serde:
use core::ops::Range;
use serde::{Deserialize, Serialize};
use serde_json::Error;
#[derive(Debug, Default, PartialEq, Eq, Serialize, Deserialize)]
struct Foo {
name: String,
value: i32,
#[serde(with = "range_aux", flatten)]
bound: Range<i32>,
}
mod range_aux {
use core::ops::Range;
use serde::{Deserialize, Deserializer, Serialize, Serializer};
#[derive(Serialize, Deserialize)]
struct RangeAux {
upper_bound: i32,
lower_bound: i32,
}
pub fn serialize<S>(range: &Range<i32>, ser: S) -> Result<S::Ok, S::Error>
where
S: Serializer,
{
RangeAux::serialize(
&RangeAux {
upper_bound: range.end,
lower_bound: range.start,
},
ser,
)
}
pub fn deserialize<'de, D>(d: D) -> Result<Range<i32>, D::Error>
where
D: Deserializer<'de>,
{
let range_aux: RangeAux = RangeAux::deserialize(d)?;
Ok(Range {
start: range_aux.lower_bound,
end: range_aux.upper_bound,
})
}
}
fn main() -> Result<(), Error> {
let data = r#"{"name":"foo","value":1234,"upper_bound":5000,"lower_bound":1000}"#;
let foo: Foo = serde_json::from_str(data)?;
assert_eq!(
foo,
Foo {
name: "foo".to_string(),
value: 1234,
bound: 1000..5000
}
);
let output = serde_json::to_string(&foo)?;
assert_eq!(data, output);
Ok(())
}
非常接近 remote
pattern but this doesn't work with generic see serde#1844
。
可能的通用版本:
use core::ops::Range;
use serde::{Deserialize, Serialize};
use serde_json::Error;
#[derive(Debug, Default, PartialEq, Eq, Serialize, Deserialize)]
struct Foo {
name: String,
value: i32,
#[serde(with = "range_aux", flatten)]
bound: Range<i32>,
}
mod range_aux {
use core::ops::Range;
use serde::{Deserialize, Deserializer, Serialize, Serializer};
pub fn serialize<S, Idx: Serialize>(range: &Range<Idx>, ser: S) -> Result<S::Ok, S::Error>
where
S: Serializer,
{
// could require Idx to be Copy or Clone instead of borrowing Idx
#[derive(Serialize)]
struct RangeAux<'a, Idx> {
upper_bound: &'a Idx,
lower_bound: &'a Idx,
}
RangeAux::serialize(
&RangeAux {
upper_bound: &range.end,
lower_bound: &range.start,
},
ser,
)
}
pub fn deserialize<'de, D, Idx: Deserialize<'de>>(d: D) -> Result<Range<Idx>, D::Error>
where
D: Deserializer<'de>,
{
#[derive(Deserialize)]
struct RangeAux<Idx> {
upper_bound: Idx,
lower_bound: Idx,
}
let range_aux: RangeAux<Idx> = RangeAux::deserialize(d)?;
Ok(Range {
start: range_aux.lower_bound,
end: range_aux.upper_bound,
})
}
}
fn main() -> Result<(), Error> {
let data = r#"{"name":"foo","value":1234,"upper_bound":5000,"lower_bound":1000}"#;
let foo: Foo = serde_json::from_str(data)?;
assert_eq!(
foo,
Foo {
name: "foo".to_string(),
value: 1234,
bound: 1000..5000
}
);
let output = serde_json::to_string(&foo)?;
assert_eq!(data, output);
Ok(())
}
不一定比自定义序列化程序更简洁,但肯定更简单一点的是 [serde(from
和 into)]
的解决方案。 (我觉得我在每个 serde 问题上都发布了这个。:/)
您定义了一个辅助的、可序列化的结构,它具有您想要的 JSON 结构:
#[derive(Deserialize, Serialize, Clone)]
struct AuxMyObject {
name: String,
value: i32,
upper_bound: i32,
lower_bound: i32,
}
然后你向 rust 解释你的辅助结构与原始结构的关系。这有点乏味(但很简单),可能有一些宏箱可以帮助减轻打字负担:
impl From<MyObject> for AuxMyObject {
fn from(from: MyObject) -> Self {
Self {
name: from.name,
value: from.value,
lower_bound: from.bound.start,
upper_bound: from.bound.end,
}
}
}
impl From<AuxMyObject> for MyObject {
fn from(from: AuxMyObject) -> Self {
Self {
name: from.name,
value: from.value,
bound: Range {
start: from.lower_bound,
end: from.upper_bound,
},
}
}
}
最后,您告诉 serde 在序列化时用辅助结构替换主结构:
#[derive(Serialize, Deserialize, Debug, PartialEq, Clone)]
#[serde(from = "AuxMyObject", into = "AuxMyObject")]
struct MyObject { … }
我有 JSON 个格式如下的对象:
{
"name": "foo",
"value": 1234,
"upper_bound": 5000,
"lower_bound": 1000
}
我想使用 serde 来处理这些对象,结构类似于
struct MyObject {
name: String,
value: i32,
bound: Range<i32>,
}
在没有任何修改的情况下,序列化这些结构之一会产生
{
"name": "foo",
"value": 1234,
"bound": {
"start": 1000,
"end": 5000
}
}
我可以申请#[serde(flatten)]
靠近,屈服
{
"name": "foo",
"value": 1234,
"start": 1000,
"end": 5000
}
但是添加 #[serde(rename...)]
似乎没有任何改变,无论我尝试为重命名提供什么样的参数。是否可以展平范围并重命名参数?
你可以使用 serde 属性 with
并且只使用一个中间结构让真正的实现到 serde:
use core::ops::Range;
use serde::{Deserialize, Serialize};
use serde_json::Error;
#[derive(Debug, Default, PartialEq, Eq, Serialize, Deserialize)]
struct Foo {
name: String,
value: i32,
#[serde(with = "range_aux", flatten)]
bound: Range<i32>,
}
mod range_aux {
use core::ops::Range;
use serde::{Deserialize, Deserializer, Serialize, Serializer};
#[derive(Serialize, Deserialize)]
struct RangeAux {
upper_bound: i32,
lower_bound: i32,
}
pub fn serialize<S>(range: &Range<i32>, ser: S) -> Result<S::Ok, S::Error>
where
S: Serializer,
{
RangeAux::serialize(
&RangeAux {
upper_bound: range.end,
lower_bound: range.start,
},
ser,
)
}
pub fn deserialize<'de, D>(d: D) -> Result<Range<i32>, D::Error>
where
D: Deserializer<'de>,
{
let range_aux: RangeAux = RangeAux::deserialize(d)?;
Ok(Range {
start: range_aux.lower_bound,
end: range_aux.upper_bound,
})
}
}
fn main() -> Result<(), Error> {
let data = r#"{"name":"foo","value":1234,"upper_bound":5000,"lower_bound":1000}"#;
let foo: Foo = serde_json::from_str(data)?;
assert_eq!(
foo,
Foo {
name: "foo".to_string(),
value: 1234,
bound: 1000..5000
}
);
let output = serde_json::to_string(&foo)?;
assert_eq!(data, output);
Ok(())
}
非常接近 remote
pattern but this doesn't work with generic see serde#1844
。
可能的通用版本:
use core::ops::Range;
use serde::{Deserialize, Serialize};
use serde_json::Error;
#[derive(Debug, Default, PartialEq, Eq, Serialize, Deserialize)]
struct Foo {
name: String,
value: i32,
#[serde(with = "range_aux", flatten)]
bound: Range<i32>,
}
mod range_aux {
use core::ops::Range;
use serde::{Deserialize, Deserializer, Serialize, Serializer};
pub fn serialize<S, Idx: Serialize>(range: &Range<Idx>, ser: S) -> Result<S::Ok, S::Error>
where
S: Serializer,
{
// could require Idx to be Copy or Clone instead of borrowing Idx
#[derive(Serialize)]
struct RangeAux<'a, Idx> {
upper_bound: &'a Idx,
lower_bound: &'a Idx,
}
RangeAux::serialize(
&RangeAux {
upper_bound: &range.end,
lower_bound: &range.start,
},
ser,
)
}
pub fn deserialize<'de, D, Idx: Deserialize<'de>>(d: D) -> Result<Range<Idx>, D::Error>
where
D: Deserializer<'de>,
{
#[derive(Deserialize)]
struct RangeAux<Idx> {
upper_bound: Idx,
lower_bound: Idx,
}
let range_aux: RangeAux<Idx> = RangeAux::deserialize(d)?;
Ok(Range {
start: range_aux.lower_bound,
end: range_aux.upper_bound,
})
}
}
fn main() -> Result<(), Error> {
let data = r#"{"name":"foo","value":1234,"upper_bound":5000,"lower_bound":1000}"#;
let foo: Foo = serde_json::from_str(data)?;
assert_eq!(
foo,
Foo {
name: "foo".to_string(),
value: 1234,
bound: 1000..5000
}
);
let output = serde_json::to_string(&foo)?;
assert_eq!(data, output);
Ok(())
}
不一定比自定义序列化程序更简洁,但肯定更简单一点的是 [serde(from
和 into)]
的解决方案。 (我觉得我在每个 serde 问题上都发布了这个。:/)
您定义了一个辅助的、可序列化的结构,它具有您想要的 JSON 结构:
#[derive(Deserialize, Serialize, Clone)]
struct AuxMyObject {
name: String,
value: i32,
upper_bound: i32,
lower_bound: i32,
}
然后你向 rust 解释你的辅助结构与原始结构的关系。这有点乏味(但很简单),可能有一些宏箱可以帮助减轻打字负担:
impl From<MyObject> for AuxMyObject {
fn from(from: MyObject) -> Self {
Self {
name: from.name,
value: from.value,
lower_bound: from.bound.start,
upper_bound: from.bound.end,
}
}
}
impl From<AuxMyObject> for MyObject {
fn from(from: AuxMyObject) -> Self {
Self {
name: from.name,
value: from.value,
bound: Range {
start: from.lower_bound,
end: from.upper_bound,
},
}
}
}
最后,您告诉 serde 在序列化时用辅助结构替换主结构:
#[derive(Serialize, Deserialize, Debug, PartialEq, Clone)]
#[serde(from = "AuxMyObject", into = "AuxMyObject")]
struct MyObject { … }