有条件地显示 HTML 中的数据
Conditionally display data in HTML with conditions
我想打印 Nord、Est、Ouest... 等对象的属性作为 HTML
中的元素,例如 label: value which label is the name of the direction and value its real value if exist!
但有时一些 属性 不存在(即它们是 null
),所以我只想在它们存在时渲染它们!
function print_directions(dirs) {
let { nord, nordest, nordouest, est, sud, sudest, sudouest, ouest } =
dirs;
document.querySelector(".content").innerHTML = `
<div class="info-dir ${nord == null ? "d-none" : ""}">
Nord:
<span>${nord ?? ""}</span>
</div>
<div class="info-dir ${nordest == null ? "d-none" : ""}">
nord-est:
<span>${nordest ?? ""}</span>
</div>
<div class="info-dir ${nordouest == null ? "d-none" : ""}">
nord-ouest:
<span>${nordouest ?? ""}</span>
</div>
<div class="info-dir ${est == null ? "d-none" : ""}">
Est:
<span>${est ?? ""}</span>
</div>
<div class="info-dir ${sud == null ? "d-none" : ""}">
Sud:
<span>${sud ?? ""}</span>
</div>
<div class="info-dir ${sudest == null ? "d-none" : ""}">
Sud-est:
<span>${sudest ?? ""}</span>
</div>
<div class="info-dir ${sudouest == null ? "d-none" : ""}">
Sud-ouest:
<span>${sudouest ?? ""}</span>
</div>
<div class="info-dir ${ouest == null ? "d-none" : ""}">
Ouest:
<span>${ouest ?? ""}</span>
</div>`;
}
let dirs = { nord: 10, est: 19, sudouest: 5 };
print_directions(dirs);
.d-none {
display: none;
}
<div class="content"></div>
我已经这样做了但是它太冗长了吗?
非常感谢任何使其简短的建议。
你可以这样做
function print_directions(dirs) {
const translations = {
nord: 'Nord',
sud: 'Sud',
ouest: 'Ouest',
est: 'Est',
sudouest: 'Sud-ouest',
sudest: 'Sud-est',
nordouest: 'Nord-ouest',
nordest: 'Nord-est'
}
const html = Object.entries(dirs).map(([dir, value]) => `<div class="info-dir">
${translations[dir] || dir}:
<span>${value}</span>
</div>`).join('')
document.querySelector(".content").innerHTML = html;
}
let dirs = { nord: 10, est: 19, sudouest: 5 };
print_directions(dirs);
.d-none {
display: none;
}
<div class="content"></div>
我想打印 Nord、Est、Ouest... 等对象的属性作为 HTML
中的元素,例如 label: value which label is the name of the direction and value its real value if exist!
但有时一些 属性 不存在(即它们是 null
),所以我只想在它们存在时渲染它们!
function print_directions(dirs) {
let { nord, nordest, nordouest, est, sud, sudest, sudouest, ouest } =
dirs;
document.querySelector(".content").innerHTML = `
<div class="info-dir ${nord == null ? "d-none" : ""}">
Nord:
<span>${nord ?? ""}</span>
</div>
<div class="info-dir ${nordest == null ? "d-none" : ""}">
nord-est:
<span>${nordest ?? ""}</span>
</div>
<div class="info-dir ${nordouest == null ? "d-none" : ""}">
nord-ouest:
<span>${nordouest ?? ""}</span>
</div>
<div class="info-dir ${est == null ? "d-none" : ""}">
Est:
<span>${est ?? ""}</span>
</div>
<div class="info-dir ${sud == null ? "d-none" : ""}">
Sud:
<span>${sud ?? ""}</span>
</div>
<div class="info-dir ${sudest == null ? "d-none" : ""}">
Sud-est:
<span>${sudest ?? ""}</span>
</div>
<div class="info-dir ${sudouest == null ? "d-none" : ""}">
Sud-ouest:
<span>${sudouest ?? ""}</span>
</div>
<div class="info-dir ${ouest == null ? "d-none" : ""}">
Ouest:
<span>${ouest ?? ""}</span>
</div>`;
}
let dirs = { nord: 10, est: 19, sudouest: 5 };
print_directions(dirs);
.d-none {
display: none;
}
<div class="content"></div>
我已经这样做了但是它太冗长了吗? 非常感谢任何使其简短的建议。
你可以这样做
function print_directions(dirs) {
const translations = {
nord: 'Nord',
sud: 'Sud',
ouest: 'Ouest',
est: 'Est',
sudouest: 'Sud-ouest',
sudest: 'Sud-est',
nordouest: 'Nord-ouest',
nordest: 'Nord-est'
}
const html = Object.entries(dirs).map(([dir, value]) => `<div class="info-dir">
${translations[dir] || dir}:
<span>${value}</span>
</div>`).join('')
document.querySelector(".content").innerHTML = html;
}
let dirs = { nord: 10, est: 19, sudouest: 5 };
print_directions(dirs);
.d-none {
display: none;
}
<div class="content"></div>