C++ 计算错误，不显示百分比

Question

只有a和c计算正确，b计算错误，c差1。而且百分比只显示0。虽然公式是一样的，但我不明白为什么这两个是错误的，为什么百分比只显示零并且不符合我的公式。

这里是输出 enter image description here

这是我的代码

#include <iostream>
using namespace std; 

int main(){
    string candidate[4];
    int a[5], b[5], c[5], d[5];//precint
    int at,bt,ct,dt;
    int ap, bp, cp, dp;
    int total;
    int choice;
    char yesNo;
    int i;
    
    do{ 
    cout<<"[1] Enter candidates names and votes"<<endl;
    cout<<"[2] Show Tally"<<endl;
    cout<<"[3] Exit"<<endl;
    cout<<"Enter a choice: ";
    cin>>choice;
    switch(choice){
        case(1):
    
        for(int i=0; i<4; i++){
        cout<<"Enter candidate names: ";
        cin>>candidate[i];}
        
        for(int i=0; i<5; i++){
        cout<<"Candidate "<<candidate[0]<<" precinct "<<i+1<<" votes: ";
        cin>>a[i];
        }
        
        for(int i=0; i<5; i++){
        cout<<"Candidate "<<candidate[1]<<" precinct "<<i+1<<" votes: ";
        cin>>b[i];
        }
        
        for(int i=0; i<5; i++){
        cout<<"Candidate "<<candidate[2]<<" precinct "<<i+1<<" votes: ";
        cin>>c[i];
        }
        
        for(int i=0; i<5; i++){
        cout<<"Candidate "<<candidate[3]<<" precinct "<<i+1<<" votes: ";
        cin>>d[i];
        }
        
        break;
        case(2):
            cout<<"Precinct\t"<<candidate[0]<<"\t\t"<<candidate[1]<<"\t\t"<<candidate[2]<<"\t\t"<<candidate[3]<<endl;
            
            for(int i=0; i<5; i++){ //for displaying the tally
                cout<<i+1<<"\t\t"<<a[i]<<"\t\t"<<b[i]<<"\t\t"<<c[i]<<"\t\t"<<d[i]<<endl;
            }
            cout<<endl;
            for(int i=0; i<5; i++){ //for the total votes
                at=at+a[i];
                bt=bt+b[i];
                ct=ct+c[i];
                dt=dt+d[i];
                                
            }
            total=at+bt+ct+dt;  //for the percent
            ap=(at/total)*100;
            bp=(bt/total)*100;
            cp=(ct/total)*100;
            dp=(dt/total)*100;
            
            cout<<"Candidate "<<candidate[0]<<" total votes and percentage: "<<at<<" votes. "<<ap<<"%"<<endl;
            cout<<"Candidate "<<candidate[1]<<" total votes and percentage: "<<bt<<" votes. "<<ap<<"%"<<endl;
            cout<<"Candidate "<<candidate[2]<<" total votes and percentage: "<<ct<<" votes. "<<ap<<"%"<<endl;
            cout<<"Candidate "<<candidate[3]<<" total votes and percentage: "<<dt<<" votes. "<<ap<<"%"<<endl;
            
            
        break;
        }
        cout<<"Do you want to continue(Y/N): ";
        cin>>yesNo;
    }while (yesNo == 'y' || yesNo == 'Y');
        cout<<"Thank You!";
    

    
    
    return 0;
}

Answer 1

使用 double 而不是 int 来表示用于存储百分比的变量。初始化用于存储总计的变量。

您可以在此处找到有关双重转换的更多信息。 How to convert integer to double implicitly?

并且您正在为所有候选人打印相同的百分比值，即 ap。

int at = 0, bt = 0, ct = 0, dt = 0;
double ap, bp, cp, dp;

//Rest of the code

ap = ((double)at / total) * 100;
bp = ((double)bt / total) * 100;
cp = ((double)ct / total) * 100;
dp = ((double)dt / total) * 100;

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