如何检索获得最高奖金的员工？

Question

我必须显示获得最高奖金的员工详细信息（一个包含员工详细信息，另一个 table 包含奖金详细信息）。在这里，我创建了一个 'performance bonus' 列来汇总多个奖金。如何从该列中检索员工？

select e.Employee_id,
       e.First_name,
       e.Department,
       e.Salary,
       coalesce((select sum(b.Bonus_Amount) 
    as Bonus-- Let's sum up all Employee's the bonuses
from Employee_Bonus_Table b
where b.Employee_ref_id = e.Employee_Id), 0) [Performance_bonus]
    from Employee_Table e

Answer 1

如果我理解正确的话，那么奖励是可以重复的，对吧？那么我们首先要把所有的奖金按员工加起来，然后从大到小排序，得到列表中的第一个

--- for examples:
with Employee_Bonus_Table as(
    select Bonus_Amount = 1 ,Employee_ref_id = 1
    union select Bonus_Amount = 1000 ,Employee_ref_id = 2
    union select Bonus_Amount = 2000 ,Employee_ref_id = 2


),Employee_Table as (
    select Employee_id=1
       ,First_name='First_name'
       ,Department= 'Department'
       ,Salary = 1000

    UNION select Employee_id=2
       ,First_name='First_name2'
       ,Department= 'Department2'
       ,Salary = 2000
)
--reslut query:
select top 1
       e.Employee_id,
       e.First_name,
       e.Department,
       e.Salary,
       b.sumBonus_Amount
  from Employee_Table e
        join (select sumBonus_Amount = sum(Bonus_Amount), Employee_ref_id 
            from  Employee_Bonus_Table
            group by Employee_ref_id
            ) b on b.Employee_ref_id = e.Employee_Id
order by b.sumBonus_Amount desc

如何检索获得最高奖金的员工？

how to retrieve the employee who got maximum bonus?

sql

sql-server