在猫鼬聚合期间保持原始字段完整或通过管道传递

Question

db.testA.aggregate([
  {
    "$lookup": {
      "from": "testB",
      "localField": "_id",
      "foreignField": "aId",
      "as": "join"
    }
  },
  {
    $project: {
      count: {
        $size: "$join"
      }
    }
  },
  {
    $set: {
      favorite: {
        $switch: {
          branches: [
            {
              case: {
                $gte: [
                  "$count",
                  1
                ]
              },
              then: true
            },
            {
              case: {
                $gte: [
                  "$count",
                  0
                ]
              },
              then: false
            },
            
          ],
          default: false
        }
      }
    }
  }
])

我有这个聚合函数。我想保留这些字段，但我不确定它们为什么消失了。

db={
  "testA": [
    {
      "_id": ObjectId("60508eeb52a2ab598a013bb9"),
      "message": "hello",
      "field1": false,
      "field2": 1,
      "field3": "something"
    },
    {
      "_id": ObjectId("60508f2852a2ab598a013bba"),
      "message": "hello",
      "field1": false,
      "field2": 1,
      "field3": "something"
    },
    {
      "_id": ObjectId("60508f2852a2ab665a013bba"),
      "message": "hello",
      "field1": false,
      "field2": 1,
      "field3": "something"
    }
  ],
  "testB": [
    {
      "_id": ObjectId("60508f4152a2ab598a013bbb"),
      "aId": ObjectId("60508f2852a2ab598a013bba")
    },
    {
      "_id": ObjectId("60508f4552a2ab598a013bbc"),
      "aId": ObjectId("60508f2852a2ab598a013bba")
    },
    {
      "_id": ObjectId("605090a452a2ab598a013bbd"),
      "aId": ObjectId("60508eeb52a2ab598a013bb9")
    }
  ]
}

这是我的数据库。本质上，我希望通过管道传递消息、field1、field2、field3，以便最后得到 6 个字段而不是 2 个字段。

这是我得到的结果：

[
  {
    "_id": ObjectId("60508eeb52a2ab598a013bb9"),
    "count": 1,
    "favorite": true
  },
  {
    "_id": ObjectId("60508f2852a2ab598a013bba"),
    "count": 2,
    "favorite": true
  },
  {
    "_id": ObjectId("60508f2852a2ab665a013bba"),
    "count": 0,
    "favorite": false
  }
]

https://mongoplayground.net/p/KjquoKCUw4P

如果不清楚，这是我想要的：

[
  {
    "_id": ObjectId("60508eeb52a2ab598a013bb9"),
    "count": 1,
    "favorite": true,
    "message": "hello",
    "field1": false,
    "field2": 1,
    "field3": "something"
  },
  {
    "_id": ObjectId("60508f2852a2ab598a013bba"),
    "count": 2,
    "favorite": true,
    "message": "hello",
    "field1": false,
    "field2": 1,
    "field3": "something"
  },
  {
    "_id": ObjectId("60508f2852a2ab665a013bba"),
    "count": 0,
    "favorite": false,
    "message": "hello",
    "field1": false,
    "field2": 1,
    "field3": "something"
  }
]

数据几乎相同，但假设它们都不同。

Answer 1

使用 $addFields 而不是 $project:

  {
    $addFields: {
      count: {
        $size: "$join"
      }
    }
  },

在猫鼬聚合期间保持原始字段完整或通过管道传递

Keeping original fields intact or piping them through during mongoose aggregation

mongoose

mongodb

aggregation-framework