在字典中搜索更多数据
search the dictionary for more data
我创建了这个脚本，我在这里尝试了各种方法，但没有任何帮助，所以我想作为更有经验的人与您联系
基本上脚本原理是做什么的？
我放在这里的代码就是这样做的
输入
1:1:1
输出
1:1:1 this is text from file
效果很好，但如果我想搜索两个结果，所以它在这里不起作用，我尝试了几种方法
问题是我想同时找两个东西
输入1:1:1 === 4:1:2===0---0
我在这里拆分一下
split ("===") [0]
split ("===") [1]
split ("===") [2]
我正在寻找的输出是
1: 1: 1 this is text from file 4: 1: 2 this is next text resolut 0 --- 0
从中获取数据的文件看起来像这样
"numberssearch.txt"
1:1:1===4:1:2===0---0
1:1:1===4:2:3===-1----1
1:1:1===4:3:4===-2----2
1:1:1===4:4:5===-3----3
1:1:1===4:5:6===-4----4
1:1:1===4:6:7===-5----5
这就是它从中获取数据的文件的样子
"book.txt"
1:1:1 text1
1:1:2 text2
1:1:3 text3
1:1:4 text4
1:1:5 text5
1:1:6 text6
1:1:7 text7
ect...
这是代码
with open ("numberssearch.txt") as f:
unsolved = set (f.read (). split ())
for unsolved_elem in unsolved:
userinput = unsolved_elem
file = open("book.txt",encoding='ISO-8859-1')
lines = file.readlines()
for line in lines:
words = line.split()
unsolved_elem = unsolved_elem.split("===")[0]
if len(words) > 0 and unsolved_elem == words[0]:
print(line, file=open(""+str("solved")+".txt", "a",encoding='ISO-8859-1'))
它需要 运行 两个嵌套循环 - 并且它需要在两个循环中从文件 book 中读取 - 所以最好先读取数据 book.txt 和创建字典。
我使用 io 只是为了模拟内存中的文件 - 所以每个人都可以简单地复制并 运行 它。
但是你应该使用 open()
在这个版本中，我假设 book 可能有很多次相同的数字，所以它需要列表来保留这个数字的所有文本。
book_txt = '''1:1:1 text1
1:1:2 text2
1:1:3 text3
1:1:4 text4
1:1:5 text5
1:1:6 text6
1:1:7 text7
4:2:3 other3
4:2:4 other4
4:4:5 other5'''
import io
# --- read book.txt ---
book = {}
#with open("book.txt") as f:
with io.StringIO(book_txt) as f:
for line in f:
number, text = line.strip().split(" ", 1)
if number not in book:
book[number] = []
book[number].append(text)
for item in book.items():
print(item)
结果：
('1:1:1', ['text1'])
('1:1:2', ['text2'])
('1:1:3', ['text3'])
('1:1:4', ['text4'])
('1:1:5', ['text5'])
('1:1:6', ['text6'])
('1:1:7', ['text7'])
('4:2:3', ['other3'])
('4:2:4', ['other4'])
('4:4:5', ['other5'])
与文件 numberssearch.txt 类似 - 首先我会阅读所有行和 运行 split('===')
numberssearch_txt = '''1:1:1===4:1:2===0---0
1:1:1===4:2:3===-1----1
1:1:1===4:3:4===-2----2
1:1:1===4:4:5===-3----3
1:1:1===4:5:6===-4----4
1:1:1===4:6:7===-5----5'''
import io
# --- read numberssearch.txt ---
unsolved = set()
#with open ("numberssearch.txt") as f:
with io.StringIO(numberssearch_txt) as f:
for line in f:
parts = tuple(line.strip().split('==='))
unsolved.add(parts)
for item in unsolved:
print(item)
结果：
('1:1:1', '4:5:6', '-4----4')
('1:1:1', '4:4:5', '-3----3')
('1:1:1', '4:1:2', '0---0')
('1:1:1', '4:3:4', '-2----2')
('1:1:1', '4:6:7', '-5----5')
('1:1:1', '4:2:3', '-1----1')
然后我会在 unsolved
中搜索 book 中的数字
for number1, number2, rest in unsolved:
if (number1 in book) and (number2 in book):
# nested loops which use `book`
for text1 in book[number1]:
for text2 in book[number2]:
print(number1, text1, number2, text2, rest)
结果：
1:1:1 text1 4:4:5 other5 -3----3
1:1:1 text1 4:2:3 other3 -1----1
完整的工作代码：
编辑： 我根据评论添加了更改。
# files with empty lines
book_txt = '''1:1:1 text1
1:1:2 text2
1:1:3 text3
1:1:4 text4
1:1:5 text5
1:1:6 text6
1:1:7 text7
4:2:3 Hello World 1
4:2:4 Hello World 2
4:4:5 Hello World 3'''
numberssearch_txt = '''1:1:1===4:1:2===0---0
1:1:1===4:2:3===-1----1
1:1:1===4:3:4===-2----2
1:1:1===4:4:5===-3----3
1:1:1===4:5:6===-4----4
1:1:1===4:6:7===-5----5'''
import io
# --- read book.txt ---
book = {}
#with open("book.txt") as f:
with io.StringIO(book_txt) as f:
for line in f:
line = line.strip()
if line:
parts = line.split(" ", 1)
if len(parts) == 2:
number, text = parts
text = text.strip()
if number not in book:
book[number] = []
book[number].append(text)
for item in book.items():
print(item)
# --- read numberssearch.txt ---
unsolved = set()
#with open ("numberssearch.txt") as f:
with io.StringIO(numberssearch_txt) as f:
for line in f:
line = line.strip()
if line:
parts = tuple(line.split('==='))
if len(parts) == 3:
unsolved.add(parts)
for item in unsolved:
print(item)
# --- search ---
for number1, number2, rest in unsolved:
if (number1 in book) and (number2 in book):
for text1 in book[number1]:
for text2 in book[number2]:
print(number1, text1, number2, text2, rest)
如果book.txt可能每个数字只有一次那么代码会更简单。
编辑： 我根据评论添加了更改。
# files with empty lines
book_txt = '''1:1:1 text1
1:1:2 text2
1:1:3 text3
1:1:4 text4
1:1:5 text5
1:1:6 text6
1:1:7 text7
4:2:3 Hello World 1
4:2:4 Hello World 2
4:4:5 Hello World 3'''
numberssearch_txt = '''1:1:1===4:1:2===0---0
1:1:1===4:2:3===-1----1
1:1:1===4:3:4===-2----2
1:1:1===4:4:5===-3----3
1:1:1===4:5:6===-4----4
1:1:1===4:6:7===-5----5'''
import io
# --- read book.txt ---
book = {}
#with open("book.txt") as f:
with io.StringIO(book_txt) as f:
for line in f:
line = line.strip()
if line:
parts = line.split(" ", 1)
if len(parts) == 2:
number, text = parts
text = text.strip()
book[number] = text
for item in book.items():
print(item)
# --- read numberssearch.txt ---
unsolved = set()
#with open ("numberssearch.txt") as f:
with io.StringIO(numberssearch_txt) as f:
for line in f:
line = line.strip()
if line:
parts = tuple(line.split('==='))
if len(parts) == 3:
unsolved.add(parts)
for item in unsolved:
print(item)
# --- search ---
for number1, number2, rest in unsolved:
if (number1 in book) and (number2 in book):
text1 = book[number1]
text2 = book[number2]
print(number1, text1, number2, text2, rest)
我创建了这个脚本，我在这里尝试了各种方法，但没有任何帮助，所以我想作为更有经验的人与您联系
基本上脚本原理是做什么的？
我放在这里的代码就是这样做的
输入
1:1:1
输出
1:1:1 this is text from file
效果很好，但如果我想搜索两个结果，所以它在这里不起作用，我尝试了几种方法
问题是我想同时找两个东西
输入1:1:1 === 4:1:2===0---0
我在这里拆分一下
split ("===") [0]
split ("===") [1]
split ("===") [2]
我正在寻找的输出是
1: 1: 1 this is text from file 4: 1: 2 this is next text resolut 0 --- 0
从中获取数据的文件看起来像这样
"numberssearch.txt"
1:1:1===4:1:2===0---0
1:1:1===4:2:3===-1----1
1:1:1===4:3:4===-2----2
1:1:1===4:4:5===-3----3
1:1:1===4:5:6===-4----4
1:1:1===4:6:7===-5----5
这就是它从中获取数据的文件的样子
"book.txt"
1:1:1 text1
1:1:2 text2
1:1:3 text3
1:1:4 text4
1:1:5 text5
1:1:6 text6
1:1:7 text7
ect...
这是代码
with open ("numberssearch.txt") as f:
unsolved = set (f.read (). split ())
for unsolved_elem in unsolved:
userinput = unsolved_elem
file = open("book.txt",encoding='ISO-8859-1')
lines = file.readlines()
for line in lines:
words = line.split()
unsolved_elem = unsolved_elem.split("===")[0]
if len(words) > 0 and unsolved_elem == words[0]:
print(line, file=open(""+str("solved")+".txt", "a",encoding='ISO-8859-1'))
它需要 运行 两个嵌套循环 - 并且它需要在两个循环中从文件 book 中读取 - 所以最好先读取数据 book.txt 和创建字典。
我使用 io 只是为了模拟内存中的文件 - 所以每个人都可以简单地复制并 运行 它。
但是你应该使用 open()
在这个版本中，我假设 book 可能有很多次相同的数字，所以它需要列表来保留这个数字的所有文本。
book_txt = '''1:1:1 text1
1:1:2 text2
1:1:3 text3
1:1:4 text4
1:1:5 text5
1:1:6 text6
1:1:7 text7
4:2:3 other3
4:2:4 other4
4:4:5 other5'''
import io
# --- read book.txt ---
book = {}
#with open("book.txt") as f:
with io.StringIO(book_txt) as f:
for line in f:
number, text = line.strip().split(" ", 1)
if number not in book:
book[number] = []
book[number].append(text)
for item in book.items():
print(item)
结果：
('1:1:1', ['text1'])
('1:1:2', ['text2'])
('1:1:3', ['text3'])
('1:1:4', ['text4'])
('1:1:5', ['text5'])
('1:1:6', ['text6'])
('1:1:7', ['text7'])
('4:2:3', ['other3'])
('4:2:4', ['other4'])
('4:4:5', ['other5'])
与文件 numberssearch.txt 类似 - 首先我会阅读所有行和 运行 split('===')
numberssearch_txt = '''1:1:1===4:1:2===0---0
1:1:1===4:2:3===-1----1
1:1:1===4:3:4===-2----2
1:1:1===4:4:5===-3----3
1:1:1===4:5:6===-4----4
1:1:1===4:6:7===-5----5'''
import io
# --- read numberssearch.txt ---
unsolved = set()
#with open ("numberssearch.txt") as f:
with io.StringIO(numberssearch_txt) as f:
for line in f:
parts = tuple(line.strip().split('==='))
unsolved.add(parts)
for item in unsolved:
print(item)
结果：
('1:1:1', '4:5:6', '-4----4')
('1:1:1', '4:4:5', '-3----3')
('1:1:1', '4:1:2', '0---0')
('1:1:1', '4:3:4', '-2----2')
('1:1:1', '4:6:7', '-5----5')
('1:1:1', '4:2:3', '-1----1')
然后我会在 unsolved
book 中的数字
for number1, number2, rest in unsolved:
if (number1 in book) and (number2 in book):
# nested loops which use `book`
for text1 in book[number1]:
for text2 in book[number2]:
print(number1, text1, number2, text2, rest)
结果：
1:1:1 text1 4:4:5 other5 -3----3
1:1:1 text1 4:2:3 other3 -1----1
完整的工作代码：
编辑： 我根据评论添加了更改。
# files with empty lines
book_txt = '''1:1:1 text1
1:1:2 text2
1:1:3 text3
1:1:4 text4
1:1:5 text5
1:1:6 text6
1:1:7 text7
4:2:3 Hello World 1
4:2:4 Hello World 2
4:4:5 Hello World 3'''
numberssearch_txt = '''1:1:1===4:1:2===0---0
1:1:1===4:2:3===-1----1
1:1:1===4:3:4===-2----2
1:1:1===4:4:5===-3----3
1:1:1===4:5:6===-4----4
1:1:1===4:6:7===-5----5'''
import io
# --- read book.txt ---
book = {}
#with open("book.txt") as f:
with io.StringIO(book_txt) as f:
for line in f:
line = line.strip()
if line:
parts = line.split(" ", 1)
if len(parts) == 2:
number, text = parts
text = text.strip()
if number not in book:
book[number] = []
book[number].append(text)
for item in book.items():
print(item)
# --- read numberssearch.txt ---
unsolved = set()
#with open ("numberssearch.txt") as f:
with io.StringIO(numberssearch_txt) as f:
for line in f:
line = line.strip()
if line:
parts = tuple(line.split('==='))
if len(parts) == 3:
unsolved.add(parts)
for item in unsolved:
print(item)
# --- search ---
for number1, number2, rest in unsolved:
if (number1 in book) and (number2 in book):
for text1 in book[number1]:
for text2 in book[number2]:
print(number1, text1, number2, text2, rest)
如果book.txt可能每个数字只有一次那么代码会更简单。
编辑： 我根据评论添加了更改。
# files with empty lines
book_txt = '''1:1:1 text1
1:1:2 text2
1:1:3 text3
1:1:4 text4
1:1:5 text5
1:1:6 text6
1:1:7 text7
4:2:3 Hello World 1
4:2:4 Hello World 2
4:4:5 Hello World 3'''
numberssearch_txt = '''1:1:1===4:1:2===0---0
1:1:1===4:2:3===-1----1
1:1:1===4:3:4===-2----2
1:1:1===4:4:5===-3----3
1:1:1===4:5:6===-4----4
1:1:1===4:6:7===-5----5'''
import io
# --- read book.txt ---
book = {}
#with open("book.txt") as f:
with io.StringIO(book_txt) as f:
for line in f:
line = line.strip()
if line:
parts = line.split(" ", 1)
if len(parts) == 2:
number, text = parts
text = text.strip()
book[number] = text
for item in book.items():
print(item)
# --- read numberssearch.txt ---
unsolved = set()
#with open ("numberssearch.txt") as f:
with io.StringIO(numberssearch_txt) as f:
for line in f:
line = line.strip()
if line:
parts = tuple(line.split('==='))
if len(parts) == 3:
unsolved.add(parts)
for item in unsolved:
print(item)
# --- search ---
for number1, number2, rest in unsolved:
if (number1 in book) and (number2 in book):
text1 = book[number1]
text2 = book[number2]
print(number1, text1, number2, text2, rest)