codeigniter

Question

帮帮我..!! 我在最后一个项目中，使用 Framwork CodeIgniter 构建一个 web。但我很难在控制脚本中有所作为，我列出的示例日期为 07.02.2015 并且应该在 3 天前注册但我忘记注册所以出现警告..如何制作

Answer 1

CREATE TABLE date (date1 timestamp, date2 timestamp);

INSERT INTO date VALUES ('2010-03-11 12:00:00', '2010-03-30 05:00:00');
INSERT INTO date VALUES ('2010-03-11 12:00:00', '2010-03-30 13:00:00');
INSERT INTO date VALUES ('2010-03-11 00:00:00', '2010-03-30 13:00:00');
INSERT INTO date VALUES ('2010-03-10 12:00:00', '2010-03-30 13:00:00');
INSERT INTO date VALUES ('2010-03-10 12:00:00', '2010-04-01 13:00:00');

SELECT date2 as d2,date1 as d1, DATEDIFF(d2, d1) AS diff FROM date;

+---------------------+---------------------+------+
| d2                  | d1                  | diff |
+---------------------+---------------------+------+
| 2010-03-30 05:00:00 | 2010-03-11 12:00:00 |   19 |
| 2010-03-30 13:00:00 | 2010-03-11 12:00:00 |   19 |
| 2010-03-30 13:00:00 | 2010-03-11 00:00:00 |   19 |
| 2010-03-30 13:00:00 | 2010-03-10 12:00:00 |   20 |
| 2010-04-01 13:00:00 | 2010-03-10 12:00:00 |   22 |
+---------------------+---------------------+------+
5 rows in set (0.00 sec)

Answer 2

irwan 你必须运行 cron 作业来每天检查日期。通过 cron 作业运行此代码：

$current_date=date('Y-m-d');
$date = strtotime($date);
$date = strtotime("+3 day", $date);
$adate=date=date('Y-m-d', $date); // this is after three days's date.

然后运行查询：

$this->db->where('date',$adate);
$q=$this->db->get('table');

如果您从上述查询中获取数据，则执行某些操作（无论您想要什么，例如发送邮件或其他任何操作）。希望你明白了:)

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