如何打开具有相同本地端口的两个 udp 客户端套接字

Question

如何打开两个具有相同本地端口的客户端套接字，如 java。在 Java 中，我们可以在创建 DatagramPacket 时提及源端口。我正在尝试进行 UDP 打孔。如果我做错了什么，请纠正我。

我在这里添加了我的代码。

void UDPClientConnect ( string IP , string Port ) 
{ 
    WSADATA wsa;


if ( WSAStartup(MAKEWORD(2,2),&wsa) != 0 )
{
    printf ( "startup failed %d\n" , WSAGetLastError() ) ;
    return ;
}
int reuse = 1 ; 
SOCKET s = socket ( AF_INET , SOCK_DGRAM , IPPROTO_UDP ) ;
setsockopt(s, SOL_SOCKET, SO_REUSEADDR,(char*) &reuse, sizeof(int)); 

struct sockaddr_in si_other;
int slen=sizeof(si_other);
char buf[BUFLEN];
char message[BUFLEN];

int p = atoi ( Port.c_str() ) ;

memset((char *) &si_other, 0, sizeof(si_other));
si_other.sin_family = AF_INET;

si_other.sin_port = htons(p);
si_other.sin_addr.S_un.S_addr = inet_addr( IP.c_str() );

strcpy_s ( message , "Hello" ) ;


//send the message
if ( sendto ( s , message , strlen(message) , 0 , (struct sockaddr *) &si_other , slen ) == SOCKET_ERROR)
{
    printf ( "sendto() failed with error code : %d" , WSAGetLastError() ) ;
   return ;
}

//receive a reply and print it
memset ( buf , '[=10=]' , BUFLEN ) ;
//try to receive some data, this is a blocking call
if ( recvfrom ( s , buf , BUFLEN , 0 , (struct sockaddr *) &si_other , &slen ) == SOCKET_ERROR )
{
    printf("recvfrom() failed with error code : %d" , WSAGetLastError());
    return ;
}

struct sockaddr_in localAddress;
int addrlen = sizeof(localAddress) ;

getsockname ( s , (struct sockaddr*)&localAddress , &addrlen ) ;

USHORT LocalPort = localAddress.sin_port ;
IN_ADDR localAddr = localAddress.sin_addr ;

printf("local address: %s\n", inet_ntoa( localAddress.sin_addr));
printf("local port: %d\n", (int) ntohs(localAddress.sin_port));

printf ( "\n******************************************\n\n" ) ;

int pos = 1 ;
CStringA CBuff = CStringA ( buf ) ;

string RemortPort = CBuff.Tokenize ( "-" , pos ) ;
string RemortIp = CBuff.Tokenize ( "-" , pos ) ;


reuse = 1 ;

SOCKET Sock_Reuse = socket ( AF_INET , SOCK_DGRAM , IPPROTO_UDP ) ;

setsockopt( Sock_Reuse , SOL_SOCKET, SO_REUSEADDR,(char*) &reuse, sizeof(int)); // optional, but recommended

struct sockaddr_in sin;
memset(&sin,0,sizeof(sin));
sin.sin_family=AF_INET;
sin.sin_port=htons(LocalPort);
sin.sin_addr.s_addr=INADDR_ANY;

if ( SOCKET_ERROR == connect(Sock_Reuse,(struct sockaddr *)&sin,sizeof(struct sockaddr_in)))
{
    printf ( "bind failed %d" , WSAGetLastError() ) ;
}

closesocket ( Sock_Reuse ) ;
closesocket ( s ) ;
WSACleanup ( ) ;

}

我试图用相同的方法打开具有相同端口的新套接字。

检查此 Java 代码我正尝试在 C/C++ 中这样做。这不可能??

import java.io.* ;
import java.net.* ;

public class UDPHolePunchingClient {

public static void main(String[] args) throws Exception {
    // prepare Socket
    DatagramSocket clientSocket = new DatagramSocket();

    // prepare Data
    byte[] sendData = "Hello".getBytes();

    // send Data to Server with fix IP (X.X.X.X)
    // Client1 uses port 7070, Client2 uses port 7071
    DatagramPacket sendPacket = new DatagramPacket(sendData,
            sendData.length, InetAddress.getByName("172.24.8.110"), 7070);
    clientSocket.send(sendPacket);

    // receive Data ==> Format:"<IP of other Client>-<Port of other Client>"
    DatagramPacket receivePacket = new DatagramPacket(new byte[1024], 1024);
    clientSocket.receive(receivePacket);

    // Convert Response to IP and Port
    String response = new String(receivePacket.getData());
    String[] splitResponse = response.split("-");
    InetAddress ip = InetAddress.getByName(splitResponse[0].substring(1));

    int port = Integer.parseInt(splitResponse[1]);

    // output converted Data for check
    System.out.println("IP: " + ip + " PORT: " + port);

    // close socket and open new socket with SAME localport
    int localPort = clientSocket.getLocalPort();
    clientSocket.close();
    clientSocket = new DatagramSocket(localPort);

    // set Timeout for receiving Data
    clientSocket.setSoTimeout(1000);

    // send 5000 Messages for testing
    for (int i = 0; i < 5000; i++) {

        // send Message to other client
        sendData = ("Datapacket(" + i + ")").getBytes();
        sendPacket = new DatagramPacket(sendData, sendData.length, ip, port);
        clientSocket.send(sendPacket);

        // receive Message from other client
        try {
            receivePacket.setData(new byte[1024]);
            clientSocket.receive(receivePacket);
            System.out.println("REC: "
                    + new String(receivePacket.getData()));

        } catch (Exception e) {
            System.out.println("SERVER TIMED OUT");
        }
    }

    // close connection
    clientSocket.close();
}

}

Answer 1

与所有评论相反，您所要做的就是在 bind().

之前设置套接字选项 SO_REUSEPORT

Answer 2

看来 Java 代码实际上并不是在同一端口上打开两个套接字，而是关闭第一个套接字，然后在与关闭的端口相同的端口上打开一个新套接字。对于未处于连接状态的 UDP 套接字，根本不需要这样做。

如果您不更改端口，您的 C++ 代码应该能够继续使用相同的套接字，而不是创建一个新套接字。假设您想要镜像 Java 代码正在做什么，您不需要调用 connect。只需使用 sendto 和 recvfrom 来回发送数据。

如何打开具有相同本地端口的两个 udp 客户端套接字

How to open the two udp client socket with same local port

c

sockets

udp

udpclient

hole-punching