提交数据后 @Html.RenderAction 上的错误 System.Web.Mvc.HttpHandlerUtil+ServerExecuteHttpHandlerAsyncWrapper

Question

我正在尝试使用 @Html.RenderAction 在索引视图中显示创建视图，以便在一页中显示它。

用户输入名字、姓氏等，然后单击创建按钮提交数据，然后通过重新加载索引视图（没有 AJAX).

当我单击“创建”按钮添加新记录时，出现以下错误：

Error executing child request for handler 'System.Web.Mvc.HttpHandlerUtil+ServerExecuteHttpHandlerAsyncWrapper'.

在记录添加到数据库并重定向到索引视图后的 @{ Html.RenderAction("Create"); } 脚本上。

我做错了什么？这样使用RenderAction可以吗？奇怪的是，我点击创建按钮时会先点击Index Action，然后点击Create(Post) Action，为什么不直接点击Action (Post)呢？

代码如下：

索引视图：

@model IEnumerable<MailMerge.ViewModels.EmployeeIndexViewModel>

@{
    ViewBag.Title = "Home Page";
}

@{ Html.RenderAction("Create"); }

<h2>List</h2>

<table class="table">
    <thead>
        <tr>
            <th>@Html.DisplayNameFor(m => m.FirstName)</th>
            <th>@Html.DisplayNameFor(m => m.LastName)</th>
            <th>@Html.DisplayNameFor(m => m.Address)</th>
        </tr>
    </thead>
    <tbody>
        @foreach (var item in Model)
        {
            <tr>
                <td>
                    @Html.DisplayFor(modelItem => item.FirstName)
                </td>
                <td>
                    @Html.DisplayFor(modelItem => item.LastName)
                </td>
                <td>
                    @Html.DisplayFor(modelItem => item.Address)
                </td>
            </tr>
        }
    </tbody>
</table>

创建视图：

@model MailMerge.ViewModels.EmployeeCreateViewModel

@{
    ViewBag.Title = "Create";
}

<h2>Create</h2>

@using (Html.BeginForm())
{
    @Html.AntiForgeryToken()

    <div class="form-horizontal">
        <div class="form-group">
            @Html.LabelFor(model => model.FirstName, htmlAttributes: new { @class = "control-label col-md-2" })
            <div class="col-md-10">
                @Html.EditorFor(model => model.FirstName)
                @Html.ValidationMessageFor(model => model.FirstName)
            </div>
        </div>

        <div class="form-group">
            @Html.LabelFor(model => model.LastName, htmlAttributes: new { @class = "control-label col-md-2" })
            <div class="col-md-10">
                @Html.EditorFor(model => model.LastName)
                @Html.ValidationMessageFor(model => model.LastName)
            </div>
        </div>

        <div class="form-group">
            @Html.LabelFor(model => model.Address, htmlAttributes: new { @class = "control-label col-md-2" })
            <div class="col-md-10">
                @Html.EditorFor(model => model.Address)
                @Html.ValidationMessageFor(model => model.Address)
            </div>
        </div>

        <div class="form-group">
            <div class="col-md-offset-2 col-md-10">
                <input type="submit" value="Create" class="btn btn-primary" />
            </div>
        </div>
    </div>
}

控制器：

public class HomeController : Controller
{
    TestEntities db = new TestEntities();

    public ActionResult Index()
    {
        var employees = db.Employees.ToList();

        List<EmployeeIndexViewModel> employeesVM = new List<EmployeeIndexViewModel>();

        foreach (Employee employee in employees)
        {
            employeesVM.Add(new EmployeeIndexViewModel
            {
                ID = employee.ID,
                FirstName = employee.FirstName,
                LastName = employee.LastName,
                Address = employee.Address
            });
        }

        return View(employeesVM);
    }

    public ActionResult Create()
    {
        EmployeeCreateViewModel employeeVM = new EmployeeCreateViewModel();

        return PartialView("_Create", employeeVM);
    }

    [HttpPost]
    [ValidateAntiForgeryToken]
    public ActionResult Create(EmployeeCreateViewModel employeeVM)
    {
        if (ModelState.IsValid)
        {
            Employee employee = new Employee();
            employee.FirstName = employeeVM.FirstName;
            employee.LastName = employeeVM.LastName;
            employee.Address = employeeVM.Address;

            db.Employees.Add(employee);
            db.SaveChanges();

            return RedirectToAction("Index");
        }

        return PartialView("_Create", employeeVM);
    }
}

Answer 1

即使您 post 从您的部分视图中查看，它也在索引视图内部和它的路径下。如果您想 post 到不同的视图，您需要在提交时将表单操作设置为 post 到该视图。

<form method="post" action="@Url.Action("Create", "Home")" >

Answer 2

您可以在 Html.Beginform()

中添加操作和控制器参数

@using(Html.BeginForm("Create", "Home")) 
    {
      @Html.AntiForgeryToken()

      <div class="form-horizontal">
      ....
      </div>

    }

提交数据后 @Html.RenderAction 上的错误 System.Web.Mvc.HttpHandlerUtil+ServerExecuteHttpHandlerAsyncWrapper

Error System.Web.Mvc.HttpHandlerUtil+ServerExecuteHttpHandlerAsyncWrapper on @Html.RenderAction after submit the data

c#

asp.net-mvc

renderaction