Saripaar 验证 Android，多种形式

Question

我有 3 个相同的 activity（和布局）表单，我想使用 saripaar 进行验证。这验证了三种形式，但它们不独立验证。

这是布局：

Form1：输入电子邮件并提交按钮。
Form2：输入验证码并提交按钮。
Form3: 输入密码，密码确认和提交按钮。

我希望当您为 form1 按提交时，仅验证 form1 的规则，对于 form2 和 form3 也是如此。

我有 3 个验证器对象，每个对象的逻辑都是相似的。例如：

validatorEmail = new Validator(this);
editTextRecoveryEmail = (EditText) findViewById(R.id.editTextRecoveryEmail);
buttonRecoveryEmail = (Button) findViewById(R.id.buttonRecoveryEmail);

validatorEmail.setValidationListener(new ValidationListener() {

            @Override
            public void onValidationSucceeded() {
                // Enviar el email
            }

            @Override
            public void onValidationFailed(View failedView, Rule<?> failedRule) {
                String message = failedRule.getFailureMessage();
                if (failedView instanceof EditText) {
                    if (failedView.getId() == editTextRecoveryEmail.getId()) {
                        failedView.requestFocus();
                        ((EditText) failedView).setError(message);
                    }
                }
            }
        });

buttonRecoveryEmail.setOnClickListener(new OnClickListener() {

            @Override
            public void onClick(View v) {
                validatorEmail.validate();
            }

        });

这是我的完整 activity 代码：

/* Inicializamos los controles */
        editTextRecoveryEmail = (EditText) findViewById(R.id.editTextRecoveryEmail);
        editTextRecoveryCode = (EditText) findViewById(R.id.editTextRecoveryCode);
        editTextRecoveryPassword = (EditText) findViewById(R.id.editTextRecoveryPassword);
        editTextRecoveryPasswordConfirm = (EditText) findViewById(R.id.editTextRecoveryPasswordConfirm);
        buttonRecoverySubmit = (Button) findViewById(R.id.buttonRecoverySubmit);
        buttonRecoveryCode = (Button) findViewById(R.id.buttonRecoveryCode);
        buttonRecoveryEmail = (Button) findViewById(R.id.buttonRecoveryEmail);
    /* Objeto validador */
    validatorEmail = new Validator(this);
    validatorCode = new Validator(this);
    validatorSubmit = new Validator(this);

    validatorEmail.setValidationListener(new ValidationListener() {

        @Override
        public void onValidationSucceeded() {
            // Enviar el email
        }

        @Override
        public void onValidationFailed(View failedView, Rule<?> failedRule) {
            String message = failedRule.getFailureMessage();
            if (failedView instanceof EditText) {
                if (failedView.getId() == editTextRecoveryEmail.getId()) {
                    failedView.requestFocus();
                    ((EditText) failedView).setError(message);
                }
            }
        }
    });

    validatorCode.setValidationListener(new ValidationListener() {

        @Override
        public void onValidationSucceeded() {
            // Validar código
        }

        @Override
        public void onValidationFailed(View failedView, Rule<?> failedRule) {
            String message = failedRule.getFailureMessage();
            if (failedView instanceof EditText) {
                if (failedView.getId() == editTextRecoveryCode.getId()) {
                    failedView.requestFocus();
                    ((EditText) failedView).setError(message);
                }
            }

        }
    });

    validatorSubmit.setValidationListener(new ValidationListener() {

        @Override
        public void onValidationSucceeded() {
            // Validar Submit
        }

        @Override
        public void onValidationFailed(View failedView, Rule<?> failedRule) {
            String message = failedRule.getFailureMessage();
            if (failedView instanceof EditText) {
                if (failedView.getId() == editTextRecoveryPassword.getId()
                        || failedView.getId() == editTextRecoveryPasswordConfirm.getId()) {
                    failedView.requestFocus();
                    ((EditText) failedView).setError(message);
                }
            }

        }
    });

    /* Comportamiento del botón de Registro */
    buttonRecoveryEmail.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View v) {
            validatorEmail.validate();
        }

    });

    /* Comportamiento del botón de Registro */
    buttonRecoveryCode.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View v) {
            validatorCode.validate();
        }

    });

    /* Comportamiento del botón de Registro */
    buttonRecoverySubmit.setOnClickListener(new OnClickListener() {

        @Override
        public void onClick(View v) {
            validatorSubmit.validate();
        }

    });

Answer 1

这是一个有趣的问题。您需要在 3 个不同的控制器中使用 3 个验证器类来处理这种情况。

static class EmailController implements ValidationListener {

    @Email
    private EditText mEmailEditText;
    private Button mSubmitButton;

    private Context mContext;
    private Validator mValidator;

    public EmailController(@NonNull EditText emailEditText, @NonNull Button submitButton) {
        mEmailEditText = emailEditText;
        mSubmitButton = submitButton;
        mContext = emailEditText.getContext();

        mValidator = new Validator(this);
        mValidator.setValidationListener(this);

        mSubmitButton.setOnClickListener(new OnClickListener() {
            @Override
            public void onClick(View v) {
                validator.validate();
            }
        });
    }

    @Override
    public void onValidationSucceeded() {
        // Success...
    }

    @Override
    public void onValidationFailed(List<ValidationError> errors) {
        // Failure...
    }
}

您还需要 2 个 - 一个用于验证码，另一个用于密码。如果您希望与您的 activity 通信，请传递它或实施适当的侦听器接口。

如果可能，请考虑简化表单。

Saripaar 验证 Android，多种形式

Saripaar validation Android, multiple forms

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validation

android

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