数组值在 gawk 中被覆盖

Question

我正在阅读的文件示例

011084,31.0581,-87.0547,  25.9 AL BREWTON 3 SSE     
012813,30.5467,-87.8808,   7.0 AL FAIRHOPE 2 NE     
013160,32.8347,-88.1342,  38.1 AL GAINESVILLE LOCK     
013511,32.7017,-87.5808,  67.1 AL GREENSBORO     
013816,31.8700,-86.2542, 132.0 AL HIGHLAND HOME     
015749,34.7442,-87.5997, 164.6 AL MUSCLE SHOALS AP     
017157,34.1736,-86.8133, 243.8 AL SAINT BERNARD     
017304,34.6736,-86.0536, 187.5 AL SCOTTSBORO

GAWK 代码

#!/bin/gawk

BEGIN{
FS=",";
OFS=",";
}

{
print ,,,
station="" #Forces to be string

#Save latitude 
stationInfo[station][lat]=
print "lat",stationInfo[station][lat]

#Save longitude
stationInfo[station][lon]=
print "lon",stationInfo[station][lon]

#Now try printing the latitude again
#It will return the value of the longitude instead
print "lat",stationInfo[station][lat]

print "---------------"
}

示例输出

011084,31.0581,-87.0547,  25.9 AL BREWTON 3 SSE                  
lat,31.0581
lon,-87.0547
lat,-87.0547
---------------
012813,30.5467,-87.8808,   7.0 AL FAIRHOPE 2 NE                  
lat,30.5467
lon,-87.8808
lat,-87.8808
---------------

由于某种原因，stationInfo[station][lat] 中存储的值被经度覆盖。我对世界上正在发生的事情感到茫然。

我在 Fedora 22 上使用 GAWK 4.1.1

Answer 1

你的问题是 lon 和 lat 是变量并且评估为空字符串，所以这个赋值 stationInfo[station][lat]= 和 stationInfo[station][lon]= 正在赋值给 stationInfo[station]["].

您需要在那些（和其他）行中引用 lat 和 lon 以使用字符串而不是变量。

#!/bin/gawk

BEGIN{
    FS=",";
    OFS=",";
}

{
    print ,,,
    station="" #Forces to be string

    #Save latitude 
    stationInfo[station]["lat"]=
    print "lat",stationInfo[station]["lat"]

    #Save longitude
    stationInfo[station]["lon"]=
    print "lon",stationInfo[station]["lon"]

    #Now try printing the latitude again
    #It will return the value of the longitude instead
    print "lat",stationInfo[station]["lat"]

    print "---------------"
}

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