打印一系列列对齐的列表

Question

我有一个函数，它传递一个整数列表和所需的行长度。假设数据的长度可以被行长度整除。列表中的所有整数都代表字节，因此它们不超过3位，并且不小于0。这是我的功能：

    def pprint(data, rowlen):
    # Prints out the list in a nice grid format
    print '-' * 50
    for index in range(0, len(data), rowlen):
        print data[index:(index+rowlen)]
    print '-' * 50
    return data

输出看起来像这样：

[0, 0, 2, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 0, 0]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 0, 0, 0, 0, 0, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 0]

如您所见，这种方法可行，但我想要更像这样的东西：

[0  , 0  , 2  , 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 0  , 0  ]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 0  , 0  , 0  , 0  , 0  , 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139]
[139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 139, 0  ]

这样一来，所有数据都以网格格式对齐，并且很容易看出所有内容的位置。

有没有一种简单的方法可以实现这一点，而不必遍历每个条目并插入空格。

Answer 1

使用string.format

    data = [i for i in range(0, 200)]

    def pprint(data, rowlen):
        print '-' * 50
        for index in range(0, len(data), rowlen):
            print ['{:3}'.format(i) for i in data[index:(index+rowlen)]]
        print '-' * 50
        return data

    pprint(data, 10)

打印一系列列对齐的列表

Print series of lists with aligned columns

python

printing

format

text

pprint