当 class 的两个实例被输入为基础 class 和 subclass 时测试它们的相等性？

Question

假设我有一个高级接口IRobot

public interface IRobot
{
    Boolean DoAction(object action);
}

还有两个实现这个接口的类

public class WalkingRobot : IRobot
{
    public enum WalkAction { SLOW, FAST };
    public new Boolean DoAction(object inAction)
    {
        WalkAction action = (WalkAction)inAction;
        // Does the action based on argument
        return true;
    }
}

public class TalkingRobot : IRobot
{
    public enum TalkAction { ENGLISH, GERMAN };
    public new Boolean DoAction(object inAction)
    {
        TalkAction action = (TalkAction)inAction;
        // Does the action based on argument
        return true;
    }
}

如果我有一个包含这两个实例的 List<IRobot> 类

WalkingRobot walker = new WalkingRobot();
TalkingRobot talker = new TalkingRobot();
List<IRobot> robots = new List<>();
robots.Add(walker);
robots.Add(talker);

我能否遍历 List<> 并将每个 IRobot 与我创建的实例进行比较？

WalkAction wAction = WalkAction.FAST;
TalkAction tAction = TalkAction.ENGLISH;
foreach(IRobot robot in robots)
{
    if(robot == walker)
        robot.DoAction((object)wAction);
    if(robot == talker)
        robot.DoAction((object)tAction);
}

Answer 1

除非有一个您没有显示的 == 重载，否则您只是比较两个引用是否相等 - 没关系。您甚至不需要将 wAction 和 tAction 转换为 object，因为您可以使用隐式转换：

foreach(IRobot robot in robots)
{
    if (robot == walker)
    {
        robot.DoAction(wAction);
    }
    else if (robot == talker)
    {
        robot.DoAction(tAction);
    }
}

这会起作用，但总的来说，这在很长一段时间内都不是很好的面向对象设计。你和机器人不一样，每个机器人都必须将他们的动作转换为正确的类型。

如果这只是是关于将对象与 == 进行比较的问题，那很好 - 但我会避开其余代码一个设计。

当 class 的两个实例被输入为基础 class 和 subclass 时测试它们的相等性？

Testing equality of two instances of a class when they are typed as their base class and subclass?

c#

casting

equality