SQL 从 codeigniter 中的复选框查询动态 table 列选择？

Question

我正在尝试根据 codeigniter 中的复选框 selection 从数据库中检索列。但是我不知道该怎么做？

例如数据库中有一个列table成员：

|  ID   | Name   | Gender   | Status  |
---------------------------------------
|  1    | Anne   |  F       | Member  |
|  2    | Brown  |  M       | Member  |
|  3    | Carl   |  M       | Member  |

然后 data.php 视图中的复选框 select 要显示的列

<?php echo form_open(data/getData);?>
<label class="col-md-4" for="parameter">Parameter</label>
<div class="col-md-6">
 <input type="checkbox" id="parameter" value="name"> Name <br>
 <input type="checkbox" id="parameter" value="gender"> Gender <br>
 <input type="checkbox" id="parameter" value="status"> status <br>
</div>
<input type="submit" class="btn btn-md btn-info" value="Process" />
<?php echo form_close();?>

<div class="well">
   <table class="table table-bordered table-hover" cellspacing="0" width="100%">
     <thead>
       <tr class="info">
         <th>ID</th>
         <th></th>
         <th></th>
         <th></th>
       </tr>
     </thead>
     <tbody>
       <?php foreach($query as $d): ?>
        <tr> 
         <td><?php echo $d['ID'];?></td>
         <td><?php echo $d[''];?></td>
         <td><?php echo $d[''];?></td>
         <td><?php echo $d[''];?></td>
        </tr>
       <?php endforeach ?>
     </tbody>
   </table>
 </div>

如何动态生成从复选框中检索的列名？

Data_model.php:

function getData(){
  //I don't know how to get the dynamic column select from the view to the select query

  $this->db->select(?);
  $this->db->from('member');
  $query = $this->db->get();
  return $query->result();
}

有人帮我解决这个问题吗？

Answer 1

试试这个简单的方法，将一个 POST/GET 的名称属性设为 param[] 数组

<input type="checkbox" id="parameter" name="param[]" value="name"> Name <br>
 <input type="checkbox" id="parameter" name="param[]" value="gender"> Gender <br>
 <input type="checkbox" id="parameter" name="param[]" value="status"> status <br>

in PHP（假设 post 值）

$param = $this->input->post('param');

//if no param get all columns
if(empty($param)){
 $param = '*';
}else{

  //if array value is more than 1 use implode else just take the 1st array
  $param = (count($param) > 1 ) ? implode(',', $param) : $param[0]; //make a single string and concatenate them with , 
}
example output: name,status

然后像这样在模型中使用 $param $this->db->select("$param");

SQL 从 codeigniter 中的复选框查询动态 table 列选择？

SQL query for dynamic table column selection from checkbox in codeigniter?

sql

checkbox

codeigniter

dynamic